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John Smith wrote:
Hey, Cecil - Did you slip a digit or two? 1/4WL at 30 meters with .66 V is just shy of 5 meters, no? I get about 16 feet. Egads John, I thought this was a J-Pole for 146 MHz. You are certainly correct for 30m. The principle still applies but the fact that it is for 30m may mean the feedpoint impedance is indeed 23 ohms and the 75 ohm coax solution won't work. If it is 23 ohms, one would need 34 ohm coax and I don't have any. :-) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#2
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In message , Cecil Moore
writes John Smith wrote: Hey, Cecil - Did you slip a digit or two? 1/4WL at 30 meters with .66 V is just shy of 5 meters, no? I get about 16 feet. Egads John, I thought this was a J-Pole for 146 MHz. You are certainly correct for 30m. The principle still applies but the fact that it is for 30m may mean the feedpoint impedance is indeed 23 ohms and the 75 ohm coax solution won't work. If it is 23 ohms, one would need 34 ohm coax and I don't have any. :-) 2 x 75ohm in parallel? Ian. -- |
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