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#1
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On Fri, 25 Feb 2005 03:17:12 GMT, gwhite wrote:
RF transmitter power amps are not "impedance matched." Neither are audio power amps for that matter. Hi OM, You seem to be shy of facts and long on claims. Got any experience at the bench, or is this all arm-chair philosophy? 73's Richard Clark, KB7QHC |
#2
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Arguments about whether the power ammplifier is matched or not matched to 50
ohms arise due to misunderstandings about the meaning of "matched". Meaning 1. ------------- The PA has been designed for maximum, linear, undistorted power output when loaded with Ro ohms and the load reistance has actually been adjusted to equal Ro. Ro is usually 50 ohms. (There may be additional criteria to define what constitutes an optimum match.) Meaning 2. ------------- The load impedance Z = R+jX has been adjusted to equal the conjugate of the internal impedance resistance of the PA. (The internal impedance of the PA is usually unknown but the circuit is assumed to behave as if a conjugate match exists.) The two meanings are entirely different from each other. If there is danger of confusion then the meaning should be stated. Some people already use the descriptions "Zo match" and "Conjugate match". ---- Reg, G4FGQ |
#3
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In article ,
Reg Edwards g4fgq,regp@ZZZbtinternet,com wrote: Arguments about whether the power ammplifier is matched or not matched to 50 ohms arise due to misunderstandings about the meaning of "matched". Meaning 1. ------------- The PA has been designed for maximum, linear, undistorted power output when loaded with Ro ohms and the load reistance has actually been adjusted to equal Ro. Ro is usually 50 ohms. (There may be additional criteria to define what constitutes an optimum match.) Meaning 2. ------------- The load impedance Z = R+jX has been adjusted to equal the conjugate of the internal impedance resistance of the PA. (The internal impedance of the PA is usually unknown but the circuit is assumed to behave as if a conjugate match exists.) Meaning 3: The PA has been designed to deliver the maximum power at that load impedance and the distortion is not an issue. The two meanings are entirely different from each other. If there is danger of confusion then the meaning should be stated. Some people already use the descriptions "Zo match" and "Conjugate match". Actually meanings 2 and 3 are effectively equal in the case of the tuned system, if you define the Zo based on the change in output power vs connected impedance for small changes. Since a lot of such systems aren't linear, this is the way you end up having to define the impedance. You can't use open circuit voltage and short circuit current. Remember that this all started with the OP having a "transmitter". This would include any needed filtering. He was just connecting a 1/4 and 1/2 wave lengths of bent up wire. His output filter, I assume is just a bunch of LC sections. -- -- forging knowledge |
#4
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The phrase "output impedance" in connection with amplifiers is ambiguous and
likely to result in arguments. The correct description is "internal impedance" or "internal resistance" and should always be used. ---- Reg. |
#5
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"Reg Edwards" wrote in
message ... The phrase "output impedance" in connection with amplifiers is ambiguous and likely to result in arguments. I suppose the same could be said of any block that is susceptible to having some feedback put around it. Therefore the term "output impedance" should never be used at all. And of course, any term that could, or has ever been known to lead to an argument, with any uninformed person that might come along, should be eliminated from our vocabulary. Uuugh. Mmmmph. Me drag woman to cave by hair. The correct description is "internal impedance" or "internal resistance" and should always be used. Nonsense. If I wanted to speak of an impedance inside of some circuit, I might loosely speak of it as "internal", but in any useful discussion, it would be spoken of as either an output impedance or an input impedance, and, with most people I have such discussions with, there would be no need to add that some unknown additional feed- back not part of the present discussion could alter the observable impedance. I hope your post was a troll. -- --Larry Brasfield email: Above views may belong only to me. |
#7
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John Woodgate wrote:
"The problem is that people say "output impedance" when they mean "load impedance". Quite right. I`ll use "source" and "load". Current through a load depends on the voltage. Ratio of volts to amps is the impedance. A source with the same resistance and offsetting reactance to the load enjoys a Goldilocks relationship with its load. The source`s volts and amps perfectly match the demands of the load. It`s just right. There`s no surplus of either volts or amps when source and load are connected. Its a match. Only a matched source and load deliver all the power available in a source. If we have too much resistance in our load, it doesn`t take as much power as it could. If we have too little resistance in our load, too much power is lost in our source. The perfect match of equal source and load resistances, with the reactance neutralized, is the only condition permitting maximum power transfer. Somme amateurs want all the power they can get from their transmitters. Best regards, Richard Harrison, KB5WZI |
#8
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Richard Harrison wrote:
Some amateurs want all the power they can get from their transmitters. I learned long ago that approach burns up unprotected transmitters. Nowadays, I settle for efficiency and lots of protection circuitry. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#9
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True, but only in a linear system representable by a Thevenin source having
a resistive component that is dissipative. But an r-f amplifier is a non-linear system with a non-dissipationless "internal resistance" and cannot be modeled with a Thevinin dissipative source. IF the Thevenin source approach worked, we would have to be content with max 50% efficient amplifiers. We know we can do better than that substantially. The latest QEX has a revealing examination of impedance and conjugate matching matters. Bottom line seems to be that one concentrates upon the specific load *resistance* specified for all other specs to be met. Such a load permits the amplifier to deliver maximum power within specifications and as such is conjugately matched to its load. -- 73, George W5YR Fairview, TX http://www.w5yr.com "Richard Harrison" wrote in message ... John Woodgate wrote: "The problem is that people say "output impedance" when they mean "load impedance". Quite right. I`ll use "source" and "load". Current through a load depends on the voltage. Ratio of volts to amps is the impedance. A source with the same resistance and offsetting reactance to the load enjoys a Goldilocks relationship with its load. The source`s volts and amps perfectly match the demands of the load. It`s just right. There`s no surplus of either volts or amps when source and load are connected. Its a match. Only a matched source and load deliver all the power available in a source. If we have too much resistance in our load, it doesn`t take as much power as it could. If we have too little resistance in our load, too much power is lost in our source. The perfect match of equal source and load resistances, with the reactance neutralized, is the only condition permitting maximum power transfer. Somme amateurs want all the power they can get from their transmitters. Best regards, Richard Harrison, KB5WZI |
#10
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On Fri, 25 Feb 2005 21:42:37 -0800, Larry Brasfield wrote:
Uuugh. Mmmmph. Me drag woman to cave by hair. Uh. Nuh. Drag _FROM_ hair. |
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