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#1
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In article , Cecil Moore wrote:
Ken Smith wrote: RF transmitter power amps are certainly "impedance matched" to the intended load. Take a look in the ARRL "The radio amateur's handbook". If you have the 1944 addition, you will need to start reading at page 96 in the lower right column. If you don't have that, try Motorola's AN-721. A CMOS Class-E amp is in full saturation (0.5v at 2a) for 10% of a cycle and off (12v at 0a) for the other 90% of a cycle. The tank circuit changes the digital energy to analog energy by filtering out everything except the fundamental frequency component. How in the world does one determine the steady-state impedance of the CMOS source? Isn't the best one can do with a digital switch is to keep it within specified parameters? The CMOS device dissipates 2 watts for 10% of the time - therefore 0.2 watts steady-state. For what you say here really to be true the transistors must switch very fast. About 25pS switching speed is needed at about 400KHz. If we take that to be the case however, I think you will see why matching still applies. Lets take the reactive component first. If there is a reactive component to the loading, the current in the switch will have a higher RMS value without that increase in RMS increasing the radiated power of the system. So the reactive component of the matching is fairly obvious. Imagine that you have a well designed Class-E circuit loaded with the load the designer optimized it for. Now imagine that you slightly increase the resistance slightly. When you do so, the current into the load will decrease but the voltage will not increase enough to compensate for this. Now lets assume that you slightly decrease the resistance. Since we are assuming that this is a well designed case, we can assume that the designer took steps to ensure that the output devices would be protected from excess currents. This could be done by reducing the operating voltage of the output section, for example. In any case, the voltage on the load will decrease by a larger factor than the current will increase. So it is obvious that the reactive part is matched and the resistive part is matched just as it would be in a non-class-E output section. -- -- forging knowledge |
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#2
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Ken Smith wrote:
Now lets assume that you slightly decrease the resistance. Since we are assuming that this is a well designed case, we can assume that the designer took steps to ensure that the output devices would be protected from excess currents. Let's assume the designer is an amateur who didn't provide any protection for his tube's output. The lower the resistive load, the more current the output device draws until it fails. What is the output impedance of the device? -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
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#3
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In article , Cecil Moore wrote:
Ken Smith wrote: Now lets assume that you slightly decrease the resistance. Since we are assuming that this is a well designed case, we can assume that the designer took steps to ensure that the output devices would be protected from excess currents. Let's assume the designer is an amateur who didn't provide any protection for his tube's output. The lower the resistive load, the more current the output device draws until it fails. What is the output impedance of the device? At the point where it fails, the output goes to zero, I assume. If so, wouldn't that be the impedance as I've been defining it. -- -- forging knowledge |
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#4
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Ken Smith wrote:
At the point where it fails, the output goes to zero, I assume. If so, wouldn't that be the impedance as I've been defining it. Is an amp that fails at one minute with 100w FM better matched than an amp that fails at two minutes with 100w CW? -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
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#5
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I read in sci.electronics.design that Cecil Moore
wrote (in ) about '1/4 vs 1/2 wavelength antenna', on Sat, 26 Feb 2005: Is an amp that fails at one minute with 100w FM better matched than an amp that fails at two minutes with 100w CW? If the FM is what passes for music these days, it's MUCH better IMHO. (;-) -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
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#6
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In article ,
John Woodgate wrote: [...] If the FM is what passes for music these days, it's MUCH better IMHO. There is very little that is sent in the form of radio waves that is worth the electrical power to send it. The really sad thing is that much of what is send via FM is really "voice grade" material. When FM was new, the material for FM was specially produced to take advantage of the wide bandwidth and large dynamic range. -- -- forging knowledge |
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#7
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On Sun, 27 Feb 2005 17:12:46 +0000, Ken Smith wrote:
In article , John Woodgate wrote: [...] If the FM is what passes for music these days, it's MUCH better IMHO. There is very little that is sent in the form of radio waves that is worth the electrical power to send it. Hmm, many advertisers would disagree. Since they have real money at stake and you don't... The really sad thing is that much of what is send via FM is really "voice grade" material. When FM was new, the material for FM was specially produced to take advantage of the wide bandwidth and large dynamic range. Bandwidth, perhaps. Wide dynamic range? The FCC rules seem to suggest otherwise. -- Keith |
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#8
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In article , Cecil Moore wrote:
Ken Smith wrote: At the point where it fails, the output goes to zero, I assume. If so, wouldn't that be the impedance as I've been defining it. Is an amp that fails at one minute with 100w FM better matched than an amp that fails at two minutes with 100w CW? No, you've got the concept backwards. Obviously the worst matched is the 1 o=minute case, next would be the 2 minute case and so on up to one which runs for about its MTBF at the connected load. This last case would likely be the one the designer was targeting. -- -- forging knowledge |
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#10
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In article ,
Jim Thompson wrote: [....] But I vaguely recall a 5/8 wavelength antenna that had a good low-angle pattern. Unfortunately, the OP (is he still here?) was stuck with a box to short to even fit a 1/4 wave whip. I also think that this box could not be assumed to be resting on the ground If you squint at the ASCII art below, you will see more or less the radiation pattern of a 5/8 whip over a large ground plain. ................................. .................!............... ...........******!*****.......... ..........*......!......*........ ..........*......!......*........ ...........****..!..****...A..... ........*******..!..*******...... .....***.........!.........***... ...*.............!.............*B ******************************** If you don't have a large enough ground plain, the notch in the side labeled "A" starts to go away and the peak at "B" reduces. -- -- forging knowledge |
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