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#1
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On Sat, 26 Feb 2005 08:33:25 -0600, Cecil Moore wrote:
Rich Grise wrote: On Fri, 25 Feb 2005 22:35:28 -0600, Cecil Moore wrote: Rich Grise wrote: If that's not impedance matching, I don't know what it is! (Oh, "Load line" matching? What are the two parameters of the load line? Voltage and Current, right? What's the slope of the load line? Impedance!) And there's the catch. If the load line is the source impedance, the load (not the designer) effects the source impedance. Apparently, I'm not following the same conversation here, because I thought that the impedance matching network (in the instant example, the pi-net output of the transmitter) was what translated the load impedance to the source impedance, matching both in the process. Maybe I inferred wrong. From your "load line equals impedance" statement above, I inferred that you were implying that the load line *is* the source impedance. No, just trying to make the point that it does, in fact, _have_ an impedance. (even if it's running class E.) What that exact impedance is, of course, is left as an exercise for the reader. :-) And another thing - in a transmitter, the impedance matching only happens at the one frequency, which is a lot different scenario from, say, a stereo. This could be a confusion factor here. Thanks, Rich |
#2
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Rich Grise wrote:
And another thing - in a transmitter, the impedance matching only happens at the one frequency, which is a lot different scenario from, say, a stereo. This could be a confusion factor here. Therefore, the key to converting the non-linear source to an equivalent linear source lies in a Fourier analysis? Do the other-than-fundamental terms in the Fourier analysis encounter a low impedance or a high impedance? -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#3
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I read in sci.electronics.design that Cecil Moore
wrote (in ) about '1/4 vs 1/2 wavelength antenna', on Sat, 26 Feb 2005: Rich Grise wrote: And another thing - in a transmitter, the impedance matching only happens at the one frequency, which is a lot different scenario from, say, a stereo. This could be a confusion factor here. Therefore, the key to converting the non-linear source to an equivalent linear source lies in a Fourier analysis? Do the other-than-fundamental terms in the Fourier analysis encounter a low impedance or a high impedance? Yes. Not facetious; the impedance matching network can be configured to minimise individual or a few harmonic emissions by adjusting its impedances at harmonic frequencies. Either high or low (or perhaps both) can minimise the emission, depending on the configuration. -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
#4
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John Woodgate wrote:
Cecil Moore wrote: Therefore, the key to converting the non-linear source to an equivalent linear source lies in a Fourier analysis? Do the other-than-fundamental terms in the Fourier analysis encounter a low impedance or a high impedance? Yes. Not facetious; the impedance matching network can be configured to minimise individual or a few harmonic emissions by adjusting its impedances at harmonic frequencies. Either high or low (or perhaps both) can minimise the emission, depending on the configuration. Whether the harmonic impedance is high or low would affect the efficiency, no? -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#5
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I read in sci.electronics.design that Cecil Moore
wrote (in ) about '1/4 vs 1/2 wavelength antenna', on Sat, 26 Feb 2005: John Woodgate wrote: Cecil Moore wrote: Therefore, the key to converting the non-linear source to an equivalent linear source lies in a Fourier analysis? Do the other-than-fundamental terms in the Fourier analysis encounter a low impedance or a high impedance? Yes. Not facetious; the impedance matching network can be configured to minimise individual or a few harmonic emissions by adjusting its impedances at harmonic frequencies. Either high or low (or perhaps both) can minimise the emission, depending on the configuration. Whether the harmonic impedance is high or low would affect the efficiency, no? I think the question can only be answered by 'It depends..'. For example, it is 'affected' if it's changed by 1%, but is that significant? -- Regards, John Woodgate, OOO - Own Opinions Only. The good news is that nothing is compulsory. The bad news is that everything is prohibited. http://www.jmwa.demon.co.uk Also see http://www.isce.org.uk |
#6
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"Rich Grise" bravely wrote to "All" (26 Feb 05 16:01:31)
--- on the heady topic of " 1/4 vs 1/2 wavelength antenna" RG From: Rich Grise RG Xref: aeinews rec.radio.amateur.antenna:26047 RG sci.electronics.design:194 RG On Sat, 26 Feb 2005 08:33:25 -0600, Cecil Moore wrote: Rich Grise wrote: On Fri, 25 Feb 2005 22:35:28 -0600, Cecil Moore wrote: Rich Grise wrote: If that's not impedance matching, I don't know what it is! (Oh, "Load line" matching? What are the two parameters of the load line? Voltage and Current, right? What's the slope of the load line? Impedance!) And there's the catch. If the load line is the source impedance, the load (not the designer) effects the source impedance. Apparently, I'm not following the same conversation here, because I thought that the impedance matching network (in the instant example, the pi-net output of the transmitter) was what translated the load impedance to the source impedance, matching both in the process. Maybe I inferred wrong. From your "load line equals impedance" statement above, I inferred that you were implying that the load line *is* the source impedance. RG No, just trying to make the point that it does, in fact, _have_ an RG impedance. (even if it's running class E.) What that exact impedance RG is, of course, is left as an exercise for the reader. :-) RG And another thing - in a transmitter, the impedance matching only RG happens at the one frequency, which is a lot different scenario from, RG say, a stereo. This could be a confusion factor here. RG Thanks, RG Rich There are a couple of things meant by matching. The usual notion has to do with the plate resistance of tubes. When used in a linear mode a tube has a given plate resistance. To get the most power output from a tube its plate resistance must equal the load. The available plate current curve and equivalent load then must match the supply voltage. A transformer is needed to adjust the typically low value load resistance to the much greater plate resistance. The other notion of matching has to do with using a switched voltage to synthesize the right output voltage and current to drive a given load. This type of transformation is done by using sampling over time. Another type of transformation uses a resonnant tank circuit which, like the above transformer, can adjust the load resistance to equal that of the source resistance by a choice of the proper tank network reactances. This is a single frequency only matching however. Transistor audio impedance is never matched since an extremely low source resistance is desirable for speaker damping. Musical instrument tube amplifiers are somewhat between these since the tube power must be transformed to match the high voltage supply low plate current to the high current low voltage load, but yet must present a low source resistance damping to a speaker so uses negative feedback for this. A*s*i*m*o*v .... Ok, I pulled the pin. Now what?.....Hey! Where are you all going? |
#7
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![]() Rich Grise wrote: No, just trying to make the point that it does, in fact, _have_ an impedance. (even if it's running class E.) What that exact impedance is, of course, is left as an exercise for the reader. :-) And like any impedance, is a function of frequency. And another thing - in a transmitter, the impedance matching only happens at the one frequency, which is a lot different scenario from, say, a stereo. This could be a confusion factor here. There may be more similarity than difference over the respective 20 KHz bandwidth. ac6xg |
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