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#1
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On Mon, 03 Nov 2003 15:19:44 -0600, Cecil Moore
wrote: Roy Lewallen wrote: Because you're seeing different currents at the two stub terminals, you must be modeling it with wires, which should reflect reality quite well. Look carefully at the currents along the stub and you'll find they're not equal and opposite on the two conductors. Such a radiating stub *is* very different from a coil. Instead of a knee-jerk defense of your ideas, why don't you actually take a look at the problem? Ah the quality of sneer review. Those stubs are vertical. EZNEC shows virtually zero vertically polarized radiation. According to EZNEC, those stubs are radiating a negligible amount, just like the lumped inductance. Why the 40% difference in current between the two configurations? Is this a characteristic of NEC? Cecil, you have two stubs and they are driven antiphase (typical of a doublet) and through symmetry would have equal antiphase currents when compared to their opposites, but not necessarily equal currents within their twin-pair of lines. The sum of ALL currents (and not just the myopic view of one of two stubs) would suggest exactly what Roy has offered. This, of course, returns us to the question of what part of the radiator radiates. Sadly, the convention of the current pulse (or maxima, or other equivalent term) trips up discussion just in these matters. ALL elements radiate, it is only in the far field where their contributions negate, not literally within the structure. 73's Richard Clark, KB7QHC |
#2
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Richard Clark wrote:
Cecil, you have two stubs and they are driven antiphase (typical of a doublet) and through symmetry would have equal antiphase currents when compared to their opposites, but not necessarily equal currents within their twin-pair of lines. The sum of ALL currents (and not just the myopic view of one of two stubs) would suggest exactly what Roy has offered. Sorry, Richard, 1/2 of the loaded dipole turned vertical doesn't show a trace of horizontal radiation. Sorry about that. Roy suggested the stubs might be radiating. EZNEC says they are not. You can add two inches of vertical wire to the ends of the antenna and see the red vertical radiation. The stubs are 0.04WL, #14 wire, and 6 inch spacing. How much could they radiate on 75m? The difference in current is not due to radiation. It is due to the phase shift between Ifwd and Iref through the stub. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#3
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I'll choose this one to respond to, since it talks directly about the
models. Cecil has been kind enough to provide me with the models, and given me permission to post them on my web site. You can download them from ftp://eznec.com/pub/ as Cecils_Models.zip, and run them with the standard version of EZNEC. If you only have the demo version, a reduced-segment model of the verticals at least should work well enough to illustrate the subject matter. I looked particularly at the two models of a vertical, since they're the simplest. They're both 51 feet high, on 75 meters. One has a single lumped "load" of +j335 ohms between 25 and 26 feet from the ground, and the other has a one-foot-spaced horizontal stub protruding horizontally from the same point. One point that seems to be drawing attention, if not to say some creative theories, is that the current at the bottom terminal of the stub isn't equal to the current at the top terminal. They are, EZNEC reports, 0.846 and 0.581 amps respectively (at the stub end segments). EZNEC shows them to have very little phase shift along the stub, and very nearly 180 degrees out of phase on the two wires. (People looking at the model should be aware that stub wires 2 and 4 are defined with end 1 of one opposite end 2 of the other. So the phase angles reported by EZNEC are referenced in opposite physical directions. EZNEC reports the phase angles of the currents on the two wires as being nearly identical. So that means that the currents are flowing in phase in opposite directions -- or nearly exactly out of phase if you define positive as the same direction for both wires.) The fact that the currents at the stub terminals aren't the same means that there can be no doubt that the stub is radiating. The difference constitutes a common mode current. Because the currents are almost exactly out of phase, we can simply subtract them to find the common mode current. At the antenna end of the stub, it's about 0.27 amp. At the output end, it's zero (EZNEC reports a 0.03 amp difference for the segments nearest the short). Taking a simple-minded average, we can say it's very roughly 0.15 amp. This is the equivalent single-wire common mode current. That is, it will radiate as though that amount of current were flowing on a single conductor of the same length. Field strength is proportional to the current flowing on a conductor, and the length of the conductor. It's not at all valid (using this sort of analysis at least) to apportion radiation to being so much from this part of the antenna or so much from that. For example, the field from one part of the antenna can interfere with the field from others, resulting in little or no contribution from those sections in certain directions, or maybe in nearly all directions. But to get an idea of the potential radiation from the stub, we can look at the 0.15 amp approximate average current flowing along the ten foot stub, and compare it to the roughly 0.5 amp average over 51 feet for the vertical itself. From that, we see it probably won't be a big contributor to the total field. But that's not at all a criterion for imbalancing the stub current -- which does affect the feedpoint impedance and potentially the pattern. In fact, the stub can cause more disturbance by modifying the current in the main radiator than by its own radiation. That's definitely true in something like a collinear with phasing stubs. The stub common mode current (that it, the imbalance between currents at the stub terminals) is due to mutual coupling between the stub conductors and the vertical portion of the antenna. It shouldn't be a surprise, and it doesn't require any new theory, reflected currents or powers, or hocus-pocus to explain. It's exactly the same phenomenon that induces current in a Yagi parasitic element, and countless other familiar everyday examples. And EZNEC does the calculation exactly the same (from very basic principles) for all conductors -- it doesn't know or care if you regard some of them as being a "stub". I'll make a prediction here without having actually tried it. So here's a chance to show just how full of BS I am. Convert the model to a dipole of double the length, in free space, but with a stub on only one side. Move the stub inward toward the center. As you do, I predict that the currents will become more and more balanced. That is, the currents on the two terminals of the stub should become more and more equal. Why? Because as you get it closer to the center, the mutual coupling from the two halves of the antenna to the stub becomes more equal. Exactly at the antenna center, they cancel out. At that point, you can replace the stub with a lumped inductor and find no change. I restricted this to one stub because if there were two, coupling from one stub to the other would create imbalance even near the center. To answer an earlier question of whether you should expect a ten foot stub to behave like a lumped inductor, the answer is, of course not. At least not if it's in the field of other current-carrying conductors. What's the mystery? What's the big deal? Roy Lewallen, W7EL Cecil Moore wrote: . . . Roy suggested the stubs might be radiating. EZNEC says they are not. You can add two inches of vertical wire to the ends of the antenna and see the red vertical radiation. The stubs are 0.04WL, #14 wire, and 6 inch spacing. How much could they radiate on 75m? The difference in current is not due to radiation. It is due to the phase shift between Ifwd and Iref through the stub. |
#4
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Here's an experiment to try.
Take Cecil's model of the vertical with the loading coil. Add a single horizontal wire, 10 feet long, connected at the top of the loading coil. That is, make the new wire go from 0, 0, 26 to 10, 0, 26. Notice how much current there is in the horizontal wire. Notice how much different the current is in the vertical below the wire compared to above the wire. Look familiar? We can work our magic without either an inductor or a stub. Roy Lewallen, W7EL |
#5
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Roy Lewallen wrote:
Here's an experiment to try. Take Cecil's model of the vertical with the loading coil. Add a single horizontal wire, 10 feet long, connected at the top of the loading coil. That is, make the new wire go from 0, 0, 26 to 10, 0, 26. Notice how much current there is in the horizontal wire. Notice how much different the current is in the vertical below the wire compared to above the wire. Look familiar? And please note that horizontal wire generates lots of horizontally polarized radiation where there is none for the horizontal stub alone. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#6
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Huh?
The stub produces just as much horizontally polarized radiation as the wire. Run your stub vertical model with an elevation plot, and azimuth angle of 90 degrees. Click FF Tab. Note the magnitude of the horizontal component -- roughly -30 dBi. Then repeat with the experimental model with the single horizontal wire. As I mentioned in my lengthy posting, the radiation from the stub isn't a large part of the overall field, and this certainly shows it. But it's certainly enough to disturb the vertical's current. Exactly the same thing holds for the straight wire. Common mode current is common mode current. No magic, no mysterious phenomena "not accounted for" by EZNEC. Roy Lewallen, W7EL Cecil Moore wrote: And please note that horizontal wire generates lots of horizontally polarized radiation where there is none for the horizontal stub alone. |
#7
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Roy Lewallen wrote:
The stub produces just as much horizontally polarized radiation as the wire. Not true. The wire produces 2 dB more radiation than the stub. Given that the stub is located in a high current region compared to the wire, it is significant how much the stub doesn't radiate. If you replace the stub with an equal length of single wire, it radiates 4 dB more than the stub. Run your stub vertical model with an elevation plot, and azimuth angle of 90 degrees. Click FF Tab. Note the magnitude of the horizontal component -- roughly -30 dBi. Then repeat with the experimental model with the single horizontal wire. Thanks, Roy, that's an angle I had not looked at. Results are above. As I mentioned in my lengthy posting, the radiation from the stub isn't a large part of the overall field, and this certainly shows it. But it's certainly enough to disturb the vertical's current. Exactly the same thing holds for the straight wire. Common mode current is common mode current. No magic, no mysterious phenomena "not accounted for" by EZNEC. What EZNEC doesn't account for is the phase delay through a bugcatcher coil which is an appreciable percentage of a wavelength. EZNEC is incapable of modeling a bugcatcher coil. The only coil that EZNEC is capable of modeling is one that does not and cannot exist in reality. Therefo One cannot use EZNEC to try to prove the current is the same at both ends of a bugcatcher coil which is what kicked off this entire discussion. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#8
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Roy Lewallen wrote:
What's the mystery? What's the big deal? Intel has a lot of problems with buses running in the hundreds of MHz because of the delay in the conductor path between chips. If I tell them to install a coil in each path instead of a conductor, the delays will disappear, right? You're pulling my leg, right? At frequencies where the delay through a coil is a negligible part of an AC cycle, the delay can be ignored. At frequencies where the delay through a coil is not a negligible part of an AC cycle, the delay cannot be ignored and circuit theory will not yield the correct answers. At the point where the circuit theory error becomes too great, we must switch to distributed network analysis. Consider one foot of wire carrying a 1 GHz signal. The phase shift is greater than 360 degrees. Can we reduce the phase shift to zero by installing a coil over that one foot length? You *are* pulling my leg, right? All coils have delays. Sometimes those delays are negligible. Sometimes they are not. The delay through a 75m mobile loading coil is NOT negligible. That assumption causes errors. The phase delay through a coil is approximately the same as the section of line replaced by the coil. For an 80m loading coil, that delay is around 80 degrees or the equivalent of 57 feet of wire. Otherwise, the forward and reflected currents on the antenna would not have the proper phase. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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