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#1
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How about a little more explanatin on the 50% reradiates?
-- 73 Hank WD5JFR "Richard Harrison" wrote in message ... Ken Wood wrote: "Can you tx on a tv antenna?" A perfectly matched TV receiving antenna reradiates 50% of all the energy it intercepts. A mismatched antenna retransmits a higher percentage. Best regards, Richard Harrison, KB5WZI |
#2
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Henry Kolesnik wrote:
How about a little more explanatin on the 50% reradiates? In a perfectly matched system, half the power is "lost" in the source. In the case of a receiving antenna, that power is lost to radiation from the antenna during receive, i.e. the antenna radiation resistance is the "source". Something I have wondered about: If we simply amplify the receiver voltage through a near infinite impedance FET with virtually no load on the signal, do we get the signal information but lose virtually all the power to re-radiation? (assume high S/S+N) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#3
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Cecil
Good thought. As I understand it a receiver doesn't really need any power, so if the antenna is 50 ohms and the Rx input is say 1000 ohms most of the power has to be relflected to the antenna. -- 73 Hank WD5JFR "Cecil Moore" wrote in message ... Henry Kolesnik wrote: How about a little more explanatin on the 50% reradiates? In a perfectly matched system, half the power is "lost" in the source. In the case of a receiving antenna, that power is lost to radiation from the antenna during receive, i.e. the antenna radiation resistance is the "source". Something I have wondered about: If we simply amplify the receiver voltage through a near infinite impedance FET with virtually no load on the signal, do we get the signal information but lose virtually all the power to re-radiation? (assume high S/S+N) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#4
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Henry Kolesnik wrote:
Cecil Good thought. As I understand it a receiver doesn't really need any power, so if the antenna is 50 ohms and the Rx input is say 1000 ohms most of the power has to be relflected to the antenna. Make it one megohm and virtually all receive power in a perfectly matched antenna is lost to re-radiation? So by astute choice of feedline length we can choose constructive interference or destructive interference in the re-radiated signals? :-) -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#5
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To the gentleman who posted the original to this thread: QST had an
article on how to convert a particular tv antenna to a vhf t/r antenna. I can't recall how long ago, perhaps in the fall or summer. KF5DE Cecil Moore wrote: Henry Kolesnik wrote: Cecil Good thought. As I understand it a receiver doesn't really need any power, so if the antenna is 50 ohms and the Rx input is say 1000 ohms most of the power has to be relflected to the antenna. Make it one megohm and virtually all receive power in a perfectly matched antenna is lost to re-radiation? So by astute choice of feedline length we can choose constructive interference or destructive interference in the re-radiated signals? :-) |
#6
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In article , Cecil Moore wrote:
Something I have wondered about: If we simply amplify the receiver voltage through a near infinite impedance FET with virtually no load on the signal, do we get the signal information but lose virtually all the power to re-radiation? (assume high S/S+N) I think so, yes. Electrically, a "driven element" which feeds a very-high-impedance FET would look like a simple passive element (e.g. like a parasitic director or reflector in a Yagi). There would be some small amount of power delivered into the load (the FET's gate capacitance and its associated losses), and some small amount dissipated as losses in the element itself, but the rest would be re-radiated... just as is the case with an unloaded parasitic element. -- Dave Platt AE6EO Hosting the Jade Warrior home page: http://www.radagast.org/jade-warrior I do _not_ wish to receive unsolicited commercial email, and I will boycott any company which has the gall to send me such ads! |
#7
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Cecil,
Check with Melles-Griot on this one. Hint: Think conservation of energy. Them joules gotta go somewhere. However, in reality the opposite happens. As the antenna load goes to infinity the scattering cross section (i.e. retransmission) goes to zero faster than the capture cross section. (Plagiarized from Kraus Antennas, 2nd ed.) 73, Gene W4SZ Cecil Moore wrote: Something I have wondered about: If we simply amplify the receiver voltage through a near infinite impedance FET with virtually no load on the signal, do we get the signal information but lose virtually all the power to re-radiation? (assume high S/S+N) |
#8
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Cecil, W5DXP wrote:
"If we simply amplify the receiver voltage through a near infinite impedance FET with virtually no load on the signal, do we get the signal information?" Not as much as possible. Just as the reactance must be tuned out of an antenna to receive maximum available power, to get maximum received carrier power, the resistance of the load in the antenna must be reduced to only that matcing the radiation resistance. Walter Maxwell, W2DU has had it right all along. Maximum power transfer requires a conjugate match. Best regards, Richard Harrison, KB5WZI |
#9
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![]() Richard Harrison wrote: Cecil, W5DXP wrote: "If we simply amplify the receiver voltage through a near infinite impedance FET with virtually no load on the signal, do we get the signal information?" Not as much as possible. Just as the reactance must be tuned out of an antenna to receive maximum available power, to get maximum received carrier power, the resistance of the load in the antenna must be reduced to only that matcing the radiation resistance. Walter Maxwell, W2DU has had it right all along. Maximum power transfer requires a conjugate match. I happend across this just the other day. On page 1426, "Physics: Volume Two Electricity, Magnetism, and Light", Ronald Blum/Duane E. Roller it reads "Note that the optimum power transfer occurs when p=0, R=Z0, and t=1. [p and t are reflection and transmission coefficients] In general, for lossy lines, this takes place when the load impedance in the complex conjugate of the characteristic impedance, just as with lumped circuits." Seems to be the only way for p = (R-Z0)/(R+Z0) = 0 and t = 2R/R+Z0 = 1 to hold true for any Z0. ac6xg ac6xg Best regards, Richard Harrison, KB5WZI |
#10
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Richard Harrison wrote:
Cecil, W5DXP wrote: "If we simply amplify the receiver voltage through a near infinite impedance FET with virtually no load on the signal, do we get the signal information?" Not as much as possible. Just as the reactance must be tuned out of an antenna to receive maximum available power, to get maximum received carrier power, the resistance of the load in the antenna must be reduced to only that matcing the radiation resistance. Walter Maxwell, W2DU has had it right all along. Maximum power transfer requires a conjugate match. But the information in a received signal can be had while consuming very little of the received signal's power. For instance, ten feet of wire into my IC-756PRO results in perfect reception of Neal Boortz on WTAW on 1620 kHz. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
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