Jim Kelley wrote:
You seem to be
assuming a constant 100 Joules per second input, regardless of the fact
that the impedance the source sees is changing over the interval.

It's a mental exercise, Jim. I told you it was equipped with
a very fast very smart autotuner. If you are cool with a one
second long lossless feedline, you should be cool with a
very fast very smart autotuner.

You have provided a lot of detail about where it all resides and in what
proportions, but you still haven't shown how much energy a source would
actually produce under such circumstances.

It's too simple to mention. The signal generator is putting out a
constant 100 watts. Hint: multiply the watts (joules/sec) by the
number of seconds to get the total joules. Dimensional analysis
indicates the product will be joules.

Further, you're assuming
that energy would move forward in a transmission line at a rate higher
than the rate at which it is provided by the source.

Nope, I'm not. All wave energy moves at the speed of light. You
are confused. 100 joules per second is headed toward the load.
50 joules per second is headed away from the load.

This is highly speculative and suspect.

Easy to understand given your level of confusion. To get the forward
power, divide the load power by one minus the power reflection
coefficient. That's 50w/0.5 = 100 watts. That's how you calculate
forward power.

... there's very little impetus to believe that there need be any more
than one second's worth of energy held within a one second long
transmission line.

Jim, if you have 1.5 gallons in a tank with one gallon/sec flowing
in and one gallon/sec flowing out, how many gallons are in the tank?
You have to have enough energy in the feedline to support the
forward power and the reflected power. More or less than that
amount would violate the conservation of energy principle.

It is therefore reasonable to contend that in the
first scenario, 100 Joules of energy is held within the transmission
line as it propagates toward the load.

Yes, half is headed into the load and half will be rejected by
the load.

And in this latest scenario, 50 Joules is heading toward the load,

50 joules are destined for the load but 100 joules are heading
toward the load. Remember to get 50 watts into the load, you
must hit the load with 100 watts. 100 watts for one second is
100 joules, not 50.

and 50 is in the path to the
circulator for a total of 100 Joules stored within the one second long
transmission line.

Your math or model or both are faulty. The forward power must
be 100 watts to get 50 into the load. Therefore, the forward
wave energy in a one second feedline is 100 joules. The reflected
wave energy is half of that. Therefore, there's 150 joules in
the feedline.
--
73, Cecil http://www.qsl.net/w5dxp

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