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#1
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Hello all,
in designing a monopole should i use the velocity factor of the wire in the equation or not? and if i want its impedance to be 50ohm should i use a matching network or is there another way? |
#2
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On 11 Jun 2005 14:04:37 -0700, "redhat" wrote:
Hello all, in designing a monopole should i use the velocity factor of the wire in the equation or not? and if i want its impedance to be 50ohm should i use a matching network or is there another way? Are you sure you want 50-ohm impedance and not 37-ohms? Danny, K6MHE |
#3
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yes, i want to match it to a 50ohm amplifier,why do you think it should
be 37ohm, i have simulated it using EZNEC and the source impedance is 1.684 - J 4592, is there something wrong in that? it is 1/8 wavelength monopole. Regards |
#4
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redhat wrote:
yes, i want to match it to a 50ohm amplifier,why do you think it should be 37ohm, i have simulated it using EZNEC and the source impedance is 1.684 - J 4592, is there something wrong in that? it is 1/8 wavelength monopole. Try a loading coil in the center of the 1/8 wavelength. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#5
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Well, undoubtedly...
the 1.684 is the "pure resistance value", and this would best be at 50 ohms... if "- J 4592" is a real minus 4592 ohms cap reactance--it would be good to insert a +Jx of 4592 ohms (an equal and opposite inductive reactance)... so that Jx ends up zero... .... at that time you will find the finals in the amp start lasting indefinitely--and you will not be bothered replacing them every few minutes or so... Warmest regards, John "redhat" wrote in message oups.com... yes, i want to match it to a 50ohm amplifier,why do you think it should be 37ohm, i have simulated it using EZNEC and the source impedance is 1.684 - J 4592, is there something wrong in that? it is 1/8 wavelength monopole. Regards |
#6
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what about the velocity factor of the wire, should i use it in the
equation of the antenna length or not? |
#7
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On 11 Jun 2005 18:03:05 -0700, "redhat" wrote:
what about the velocity factor of the wire, should i use it in the equation of the antenna length or not? Hi OM, Your problems with modeling go much further. The impedance you reported was seriously low, even for an 1/8th wave. What others were trying to communicate to you is that even the best 1/4th wave (a standard sized whip or monopole) will only give you 35 to 37 Ohms, not 50 Ohms. However, this is rarely an issue in achieving good performance. A 1 Ohm antenna, on the other hand, seriously begs close examination, patience, and care in feeding. 73's Richard Clark, KB7QHC |
#8
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yes, a wire in free space has a velocity factor... if the formula for
the antenna in question does not all ready take that velocity factor into consideration, you will need to consider the velocity... .... there is also "end effect"... .... simplest thing to do would be to use the formula which takes this all into consideration... .... first, I would google for "shortened antennas" or "shortened radiators" and get a bit more familiar with "loading" the antenna to resonance... Warmest regards, John "redhat" wrote in message ps.com... what about the velocity factor of the wire, should i use it in the equation of the antenna length or not? |
#9
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On 11 Jun 2005 16:29:47 -0700, "redhat" wrote:
yes, i want to match it to a 50ohm amplifier,why do you think it should be 37ohm, i have simulated it using EZNEC and the source impedance is 1.684 - J 4592, is there something wrong in that? it is 1/8 wavelength monopole. Regards You hadn't stated that you were using a 1/8-wavelength monopole in your original posting and I had assumed that you were discussing a *standard* 1/4-wave monopole. Danny, K6MHE |
#10
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in designing a monopole should i use the velocity factor of the wire
in the equation or not? No...It's silly...Do you check the VF of wire when you build a dipole? It's overkill worrying....The VF of straight wire is in the 95+ range...Not enough to worry about... and if i want its impedance to be 50ohm should i use a matching network or is there another way? There is no other way. If you want to build a 1/8 wave vertical, build it the same way you would build a mobile vertical. If not top loaded with a hat, you should use a loading coil at 1/2 to 3/4 up the vertical for best efficiency. You would use a matching device of the same type used for most mobiles. If you want to tinker with vertical design, I'd try something like Reg's "vertload" to design the antenna. It will tell the appx efficiency of the design, and also give you the values needed for a matching device, which can be a simple coil or cap depending how you set it up. Then, after that is done, you can try modeling it. Short vertical design is quite mature...You are not going to be able to reinvent the wheel... MK |
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