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#81
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Bob, W9MDK wrote:
"The above paragraph, however, was a rather difficult to ubderstand reading,---." I responded that the load would not accept volts and amps in a ratio which does not fit its load impedance. Perhaps we should reason together some more. The transmission line delivers power to the load at its Zo. When the load impedance is different, there is a surplus of either volts or amps. The surplus nust be reflected because the load can`t take it. That`s all. Best regards, Richard Harrison, KB5WZI |
#83
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Bob, W9MDK wrote:
"Actually, your previous response was much more than I expected." Bob Lay is a well known designer and author. I appreciate his criticisms and comments as I appreciate those of Cecil, Ian, Richard C., Walter, and others. I make mistakes and typos, but can`t blame the shakes. My problems are fuzzy sight and forgetfulness. I`ve never taught, or written for magazines or books. I`m just a perpetual student. I`ve learned a lot here. Thank you to all of you who have taught me much. I always read what Reg, Roy, and Wes have to say. They are rich information sources. There are many more great contributors, but I could not begin to name them all. Some of the conflicts are roll on the floor funny. I thoroughly enjoy them as an observer. Thanks for the memories. Best regards, Richard Harrison, KB5WZI |
#84
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Richard Harrison wrote:
Bob, W9MDK wrote: "The above paragraph, however, was a rather difficult to ubderstand reading,---." I responded that the load would not accept volts and amps in a ratio which does not fit its load impedance. Perhaps we should reason together some more. The transmission line delivers power to the load at its Zo. When the load impedance is different, there is a surplus of either volts or amps. The surplus nust be reflected because the load can`t take it. That`s all. Another way of saying the same thing: The mismatched load rejects voltage in the form of Vref and rejects current in the form of Iref. Thus Vload is the phasor sum of Vfor and Vref. Iload is the phasor sum of Ifor and Iref. The result is that (Vfor+Vref)/(Ifor+Iref) = Zload. If Z0 and Zload are purely resistive and Zload Z0 then: Zload = (Vfor+Vref)/(Ifor-Iref) Vfor and Vref are in phase, Ifor and Iref are 180 deg out of phase, because we need a higher voltage and a lower current for RL Z0. If Z0 and Zload are purely resistive and Zload Z0 then: Zload = (Vfor-Vref)/(Ifor+Iref) Vfor and Vref are 180 deg out of phase, Ifor and Iref are in phase, because we need a lower voltage and a higher current for RL Z0. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
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