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#1
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On Thu, 30 Jun 2005 00:22:48 GMT, james wrote:
In electrical engineering it is the instantaneous power density of two signals passing at the same spot from two directions. That is called Convolution. Hi James, No, it is called Superposition, and that is done only with voltage or current. What you are describing may be associated with the Fourier convolution of power series - an entirely different field (and not even additive). 73's Richard Clark, KB7QHC |
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#2
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On Wed, 29 Jun 2005 17:31:36 -0700, Richard Clark
wrote: On Thu, 30 Jun 2005 00:22:48 GMT, james wrote: In electrical engineering it is the instantaneous power density of two signals passing at the same spot from two directions. That is called Convolution. Hi James, No, it is called Superposition, and that is done only with voltage or current. What you are describing may be associated with the Fourier convolution of power series - an entirely different field (and not even additive). 73's Richard Clark, KB7QHC ***** Okay maybe I am not expressing my self correctly and right now I don't realy have the time or patience to look back through my old text books. It has been several years since I have done a lot of RF work and some things are not as fresh in my mind. It does seem like the less you use the more you forget or have trouble explaining what you think. Most of my work lately has been away from RF. james |
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#3
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On Thu, 30 Jun 2005 01:02:06 GMT, james wrote:
Most of my work lately has been away from RF. Uh huh. And do you drive a Kenworth or a Volvo? |
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#4
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Richard Clark wrote:
On Thu, 30 Jun 2005 00:22:48 GMT, james wrote: In electrical engineering it is the instantaneous power density of two signals passing at the same spot from two directions. That is called Convolution. Hi James, No, it is called Superposition, and that is done only with voltage or current. What you are describing may be associated with the Fourier convolution of power series - an entirely different field (and not even additive). 73's Richard Clark, KB7QHC Convolution is a mathematical stunt you can perform with two functions: f(x)* g(x) = (integral from 0 to x) f(t)g(x-t) dt. At least that's how it's explained in Schaum's Outline book _Differential Equations_. It's pretty tough to see how it relates to power in a transmission line. Maybe someone has a use for it there. 73, Tom Donaly, KA6RUH |
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#5
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On Thu, 30 Jun 2005 01:30:39 GMT, "Tom Donaly"
wrote: Convolution is a mathematical stunt you can perform with two functions: f(x)* g(x) = (integral from 0 to x) f(t)g(x-t) dt. At least that's how it's explained in Schaum's Outline book _Differential Equations_. It's pretty tough to see how it relates to power in a transmission line. Maybe someone has a use for it there. 73, Tom Donaly, KA6RUH **** Yes Tom Convultion was the wrong term to use. I made a mistake because i type as i think and on occasion hit send before i reread what i have written. I still contend that a sinusoidal wave travelling down a coax is comprised of perpendicular(orthogonal) E and H fields. The these vector fields that induce sinusodial current and voltage potential vectors in and between the shield and center conductors as the wave travels. Both the source and reflected waves are comprised of two vector fields, E and H. Granted this is true only when the load reflection coefficient is not zero. In that case of zero, then there is no reflected power. It is possible to derive from the vector current and vector voltage a magnitude of those vectors and thus a produce two scalar quantities that can be pluged into Ohm's Law and derive an instantaineous power at a given time and position on the coax. That both source and reflected sinusoidal current and voltage can have derived scalar values. These values can be directly added. This all started from an SWR question. I contend that the instantaineous power at any given time and position of the coax can be expressed as the sum of the magnitudes or scalar quantities of the source and reflected powers. If you are wanting just the magnitudes of the power, then this should work. james |
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