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SWR - wtf?
I don't see the original posting here on rec.radio.amateur, but there
are a few misconceptions in the followups which should be addressed. Lancer wrote: On Tue, 28 Jun 2005 19:13:35 GMT, james wrote: On Tue, 28 Jun 2005 18:31:58 GMT, Lancer wrote: To have the measured SWR change with coax length, means you have current flowing on the outside of the coax. Your coax then becomes part of the antenna, so changing its length is changing the antenna length. This would change the feedpoint impedance and the SWR. That's correct, except that coax loss will also cause the SWR to change with coax length. Loss will cause the SWR at the antenna (load) to always be greater than at the transmitter (source). Unless the line is carrying common mode currents that affect antenna impedance, changing coax length won't change the SWR, even if the antenna isn't matched. Again correct except for overlooking the effect of coax loss. But there's a real problem in communicating this. If you hook a 50 ohm SWR meter to the input of a 75 ohm, 300 ohm, or line of any impedance other than 50 ohms, the meter reading won't be the SWR on the transmission line. That can mislead people into thinking that the SWR is changing with line length when it actually isn't. ******** BS Common mode currents on the shield of coaxial cables do not alter the feed impedance. Repeat ofter me. Common mode currents on the shield of coaxial cables do not alter the feed impedance. Why repeat it if it isn't true? The explanation given by Lancer was correct. If you change the length of the antenna, the feedpoint impedance will change. When you have common mode current flowing on the feedline, the feedline is part of the antenna; changing its length is changing the antenna's length. The feed impedance of an antenna is solely determined by its physical length and any load impedances within the antenna structure. Load impedances can be stray capacitance with ground via metal objects within the near field of the antenna or even a building. You have to realize that a radiating feedline (one carrying common mode current) IS part of the antenna structure. The "Magic" of an electrical halfwave transmission line is at a precise frequency, the reflection of the load to the transmistter is equal to the characteristic impedance of the transmission line irregardless of what impedance it is terminated with. This is true only of a lossless line. If the load impedance isn't far from the line's characteristic impedance (i.e., the line's SWR is low), a small amount of loss won't make much difference. However, if the line SWR is high, even a small amount of loss can make a major change in the impedance seen at the line's input. The effect is to skew the impedance toward the line's Z0. Other lengths have the load impedance reflected back and transformed by the length of the coax. The coax then acts as a transformer. It will either step up or step down the impeadnace of the load depending on the load itself and the electrical length of the coax. It's a little more complicated than that. The line doesn't simply multiply or divide the impedance by a constant, like a transformer -- except in the special case of a quarter electrical wavelength line or odd multiples thereof. In other cases, the line does transform the impedance, but in a complex way in which the resistance and reactance are transformed by different factors. And reactance can be present at a line's input even when the load is purely resistive. A Smith chart is a good visual aid in seeing what happens. Assuming a lossless line, the impedance traverses a circle around the origin. The radius of the circle corresponds to the line's SWR. With the chart, you can see all the combinations of R and X which a given line can produce with a given load by changing its length. Incidentally, loss causes the impedance to spiral inward toward the origin as the line gets longer, showing how loss skews the input impedance toward Z0. All a tuner does is electrically lengthen or shoten the coax by introducing a lumped LC constant that helps present a resistive load to the transmitter. The SWR at the feedline does not change. By placing various different lengths of coax inline, you do the same thing a tuner does, add a lumped LC constant. As can be seen from the Smith chart, you can produce only particular combinations of R and X by changing the length of a line which has a given load impedance. Unless you're unusually lucky or have planned things carefully, none of these combinations will result in 50 + j0 ohms, the usual goal, at the line's input. In contrast, a tuner is able to adjust both R and X to produce, if designed right for the application, 50 + j0 for a wide range of load impedances. It requires at least two adjustable components to achieve an impedance match from an arbitrary load impedance, because there are two separate quantities, R and X or impedance magnitude and phase, which have to be adjusted. Changing the line length is only one adjustment, so it can't be guaranteed to provide a match. If you could also change the line's Z0, for example, or the length of a stub, you'd have two adjustments and you could guarantee a match providing you have enough adjustment range. james So thats all my tuner does, lengthen or shorten the coax? Are you sure about that? Rest assured, that's not all it does. Roy Lewallen, W7EL |
(I've snipped parts of Roy's original posting, indicated by ..., that I
hope are not particularly relevant to my added comments.) Roy Lewallen wrote: I don't see the original posting here on rec.radio.amateur, but there are a few misconceptions in the followups which should be addressed. .... Unless the line is carrying common mode currents that affect antenna impedance, changing coax length won't change the SWR, even if the antenna isn't matched. Again correct except for overlooking the effect of coax loss. But there's a real problem in communicating this. If you hook a 50 ohm SWR meter to the input of a 75 ohm, 300 ohm, or line of any impedance other than 50 ohms, the meter reading won't be the SWR on the transmission line. That can mislead people into thinking that the SWR is changing with line length when it actually isn't. In addition, most hams (and other non-professionals -- and even many professionals) don't bother to check that their SWR meter is properly calibrated to the impedance they think it is. Most are nominally 50 ohms, but they can be built for any practical line impedance. Checking calibration is not all that difficult, if you take the time to do it. In addition, your nominally 50 ohm line (or 75 or whatever) can have an actual impedance 10% or more from the nominal value. If you have properly calibrated your meter to 50 ohms, and your line is 60 ohms, you would read 1.2:1 SWR when your line is actually 1:1. And if the SWR on the 60 ohm line is 1.2:1, that 50 ohm SWR meter can read anything between 1:1 and 1.44:1, depending on the line length and its load. Finally, though you may have checked that the meter to reads 1:1 with a 50 ohm load and infinity to 1 with a short or open load, the construction of inexpensive meters may cause them to have significant errors at other load impedances. .... The "Magic" of an electrical halfwave transmission line is at a precise frequency, the reflection of the load to the transmistter is equal to the characteristic impedance of the transmission line irregardless of what impedance it is terminated with. This is true only of a lossless line. If the load impedance isn't far from the line's characteristic impedance (i.e., the line's SWR is low), a small amount of loss won't make much difference. However, if the line SWR is high, even a small amount of loss can make a major change in the impedance seen at the line's input. The effect is to skew the impedance toward the line's Z0. The piece that Roy quoted is so outrageous that I can easily believe he didn't read it right, but I've re-read it several times, and it keeps coming out the same: the "magical" halfwave line does NOT reflect an impedance to the source (transmitter) equal to the LINE impedance as the quoted section says, but it reflects the LOAD impedance (altered by line loss as Roy says). .... about tuners, Roy went on to write: It requires at least two adjustable components to achieve an impedance match from an arbitrary load impedance, because there are two separate quantities, R and X or impedance magnitude and phase, which have to be adjusted. Changing the line length is only one adjustment, so it can't be guaranteed to provide a match. If you could also change the line's Z0, for example, or the length of a stub, you'd have two adjustments and you could guarantee a match providing you have enough adjustment range. In addition, two adjustable components in a particular configuration, even if they are infinitely adjustable (and reasonably close to lossless!!--a very tall order!) won't necessarily give you the ability to transform any arbitrary impedance to 50 ohms. There may be whole practical areas of the complex impedance plane left untransformable. Also, the efficiency of a particular tuner topology for a given load impedance may be very good or may be terrible, when using practical components in the tuner. To reiterate what Roy wrote, it's important to use the right topology for the job you need to do. Cheers, Tom james So thats all my tuner does, lengthen or shorten the coax? Are you sure about that? Rest assured, that's not all it does. Roy Lewallen, W7EL |
Thanks to Tom for the comments and additions.
. . . [I've lost track of who said this:] The "Magic" of an electrical halfwave transmission line is at a precise frequency, the reflection of the load to the transmistter is equal to the characteristic impedance of the transmission line irregardless of what impedance it is terminated with. [Roy:] This is true only of a lossless line. If the load impedance isn't far from the line's characteristic impedance (i.e., the line's SWR is low), a small amount of loss won't make much difference. However, if the line SWR is high, even a small amount of loss can make a major change in the impedance seen at the line's input. The effect is to skew the impedance toward the line's Z0. [Tom:] The piece that Roy quoted is so outrageous that I can easily believe he didn't read it right, but I've re-read it several times, and it keeps coming out the same: the "magical" halfwave line does NOT reflect an impedance to the source (transmitter) equal to the LINE impedance as the quoted section says, but it reflects the LOAD impedance (altered by line loss as Roy says). . . . Wow, I certainly read that (top quote) too quickly. Tom is absolutely right, as written it's very wrong, and I misread it. I retract my statement about it's being "true only of a lossless line" -- of course it's not true at all, but works as Tom says. Roy Lewallen, W7EL |
On 28 Jun 2005 17:51:10 -0700, "K7ITM" wrote in
. com: snip But there's a real problem in communicating this. If you hook a 50 ohm SWR meter to the input of a 75 ohm, 300 ohm, or line of any impedance other than 50 ohms, the meter reading won't be the SWR on the transmission line. That can mislead people into thinking that the SWR is changing with line length when it actually isn't. In addition, most hams (and other non-professionals -- and even many professionals) don't bother to check that their SWR meter is properly calibrated to the impedance they think it is. Most are nominally 50 ohms, but they can be built for any practical line impedance. Checking calibration is not all that difficult, if you take the time to do it. In addition, your nominally 50 ohm line (or 75 or whatever) can have an actual impedance 10% or more from the nominal value. If you have properly calibrated your meter to 50 ohms, and your line is 60 ohms, you would read 1.2:1 SWR when your line is actually 1:1. And if the SWR on the 60 ohm line is 1.2:1, that 50 ohm SWR meter can read anything between 1:1 and 1.44:1, depending on the line length and its load. Finally, though you may have checked that the meter to reads 1:1 with a 50 ohm load and infinity to 1 with a short or open load, the construction of inexpensive meters may cause them to have significant errors at other load impedances. Impedance matching of an SWR meter is generally unimportant since most SWR meters used for HF have a directional coupler that is much shorter than the operating wavelength. Regardless, I'm not a big fan of SWR meters -- they are good for detecting a major malfunction but that's about it. Antenna tuning/matching is best done with a field strength meter. ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
Frank Gilliland wrote:
Impedance matching of an SWR meter is generally unimportant since most SWR meters used for HF have a directional coupler that is much shorter than the operating wavelength. Point is that they are usually calibrated for Z0=50 ohms and are in error when used in Z0 environments differing from Z0=50 ohms, e.g. Z0=75 ohms. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
On Tue, 28 Jun 2005 15:53:03 -0700, Roy Lewallen
wrote: To have the measured SWR change with coax length, means you have current flowing on the outside of the coax. Your coax then becomes part of the antenna, so changing its length is changing the antenna length. This would change the feedpoint impedance and the SWR. That's correct, except that coax loss will also cause the SWR to change with coax length. Loss will cause the SWR at the antenna (load) to always be greater than at the transmitter (source). Would the changing of the coax lead to moving the SWR meter to a different voltage point on the coax? -- 73 for now Buck N4PGW |
On Tue, 28 Jun 2005 20:49:46 -0700, Frank Gilliland
wrote: I'm not a big fan of SWR meters -- they are good for detecting a major malfunction but that's about it. Antenna tuning/matching is best done with a field strength meter. A local retired instructor of some sort (military, i believe) has the same opinion. He doesn't like SWR meters but instead measures all his antennas by field strength meter. I used to tune my Swan with one. I found when I used an SWR meter, the minimum SWR dip was NEVER the maximum field strength reading. I always had to raise the SWR to about 1.3:1 or so. Around here, most of us know not to mention the performance of an antenna to him if we only used an SWR meter or antenna analyzer. His first question is "How did it do with the FSM?" I believe he is right. Radios drop power when they don't like the SWR and raise it when it does. 73 N4PGW -- 73 for now Buck N4PGW |
On Wed, 29 Jun 2005 01:04:59 -0400, Buck wrote:
I used to tune my Swan with one. I found when I used an SWR meter, the minimum SWR dip was NEVER the maximum field strength reading. I always had to raise the SWR to about 1.3:1 or so. The probable reason for maximum power output not coinciding with the plate current dip is imperfect neutralisation (whether or not the stage is neutralised). If you have a neutralisation adjustment, you can get the two to coincide by properly adjusting the neutralisation. You can use this coincidence as a quite sensitive indication of optimal neutralisation if you use a digital meter to monitor plate current, and the power out indicator to monitor RF output power. Adjust the tuning and loading for rated power into a dummy load, check the tune cap is peaked for max Po, observe the plate current, carefully dip the plate current, noting whether the dip was left or right of max Po. Now tweak the neutralisation until the two coincide. When it is all done properly, the "dip" of the plate current should be symmetric, ie it should be as "sharp" approaching from one side as the other. (Asymetric dips are another symptom of non-omptimal neutralisation. Owen -- |
Buck wrote:
Would the changing of the coax lead to moving the SWR meter to a different voltage point on the coax? Sort of, but not exactly. Let's take an example. I'll keep the values purely real to help folks who aren't familiar with complex math, but keep in mind that these are special cases and a full treatment would be somewhat more involved. I'll also make all the transmission lines lossless to simplify things. An SWR meter really just provides another way of reporting the impedance it sees. You can verify this by connecting pure resistances of various values to its output. For example, a (properly calibrated and operating) 50 ohm SWR meter will report 1:1 if you connect its output to a 50 ohm resistor. If you connect it to either a 25 or 100 ohm resistor, it reports 2:1. It does this despite the fact that there's no transmission line at all connected to its output. Some people can put up a huge smokescreen and waving of hands about reflected waves of one kind or another, but at the end of the day the SWR meter can't tell the difference between a resistor and a transmission line terminated with a load, if the impedances the meter sees are the same. It's sensitive only to impedance; it has no way of knowing even if a transmission line is connected to its output, let alone what the transmission line's SWR or even characteristic impedance is. Now put a half wavelength piece of 50 ohm coax between the SWR meter and those resistors. The SWR meter will still see the same impedances as before, so it'll report the same SWRs. Now, though, there really is a transmission line connected to its output. And because the meter is a 50 ohm meter and the line has a 50 ohm Z0, the SWR meter reading is the same as the actual SWR on the line. When the load is 50 ohms, the line's SWR is 1:1 and the meter sees 50 ohms so it reports 1:1. When the load is 25 ohms, the line's SWR is 2:1, and the meter sees 25 ohms and reports 2:1. When the load is 100 ohms, the line's SWR is 2:1, and the meter sees 100 ohms and reports 2:1. Next experiment: Connect the SWR meter through a *quarter* wavelength of 50 ohm line to a 100 ohm load. Now the impedance looking into the line is 25 ohms instead of 100. But the SWR meter reads 2:1 when it sees 25 ohms as well as 100, so it still reads 2:1, which is also still the SWR on the 50 ohm line. You can change the length of the 50 ohm line all you want and, if it's lossless, the line's actual SWR stays the same -- but the impedance at the input end of the line changes. For a 100 ohm load, when the line is any even number of half wavelengths long, the input Z is 100 ohms. When the line is any odd number of quarter wavelengths long, the input Z is 25 ohms. At other lengths, the impedance is both resistive and reactive, but the line's SWR is always 2:1. And the SWR meter interprets all these possible impedances as 2:1, and that's what it reads. The line SWR doesn't change as you change its length, and the SWR meter reading doesn't change, either. Now instead of a 50 ohm line, let's connect a half wavelength 100 ohm line to the output of the same 50 ohm SWR meter and hook that to a 50 ohm resistive load. The line's actual SWR is 2:1 and, just like any lossless line, the SWR stays the same regardless of its length. If the transmission line is an even number of half wavelengths long we'll have 50 ohms at the input and the SWR meter will read 1:1, since it's a 50 ohm meter and interprets 50 ohms as 1:1. If we change the line length to a quarter wavelength, the input impedance will be 200 ohms, which the 50 ohm SWR meter will interpret and report as 4:1. So by changing the line length from a half to a quarter wavelength we've changed the SWR meter reading from 1:1 to 4:1, even though the line's actual SWR was 2:1 all along. That's what I was talking about. The SWR meter makes assumptions about the SWR on the line from the impedances it sees. The line transforms the load impedance in a different way than a 50 ohm line would. The SWR meter then assumes an incorrect SWR value for the line, and this incorrect value changes as the line length changes. The same thing happens if the line has a 50 ohm characteristic impedance and the meter is designed for some other Z0. The lesson is that an SWR meter shows the actual SWR on a transmission line connected to its output only if the SWR meter is designed for the same Z0 as the line. Too often, people say "The SWR is. . .", but really mean "The SWR meter reading is. . .". As you've seen, the two can often be very different. When you see the SWR reading changing as you change the line length, it doesn't necessarily mean that the line's SWR is actually changing. Remember, in the preceding discussion I've assumed for simplicity that all lines were lossless. In the real world, no line is, so the actual line SWR will always be higher at the load than the source (unless of course it's 1:1 at the load). Roy Lewallen, W7EL |
Roy, to cut things short, why don't you just say SWR meters don't
measure SWR on anything. All they do is indicate whether or not the transmitter is terminated with its correct load resistance. So they are quite useful. They won't even tell you what the load resistance actually is unless the load is exactly correct. Stop fooling and confusing yourselves. The solution to everybody's problems is simple - just change the name of the thing to TLI. (Transmitter Loading Indicator). ---- Reg, G4FGQ |
Reg Edwards wrote:
Roy, to cut things short, why don't you just say SWR meters don't measure SWR on anything. All they do is indicate whether or not the transmitter is terminated with its correct load resistance. So they are quite useful. They won't even tell you what the load resistance actually is unless the load is exactly correct. Stop fooling and confusing yourselves. The solution to everybody's problems is simple - just change the name of the thing to TLI. (Transmitter Loading Indicator). Or - recalling that what the meter actually measures is the reflection coefficient - why not go back to the old name of "Reflectometer"? -- 73 from Ian G/GM3SEK 'In Practice' columnist for RadCom (RSGB) http://www.ifwtech.co.uk/g3sek |
Thanks very much to Owen for pointing out the following errors in my
recent posting: Roy Lewallen wrote: . . . Next experiment: Connect the SWR meter through a *quarter* wavelength of 50 ohm line to a 100 ohm load. Now the impedance looking into the line is 25 ohms instead of 100. But the SWR meter reads 2:1 when it sees 25 ohms as well as 100, so it still reads 2:1, which is also still the SWR on the 50 ohm line. You can change the length of the 50 ohm line all you want and, if it's lossless, the line's actual SWR stays the same -- but the impedance at the input end of the line changes. For a 100 ohm load, when the line is any even number of half wavelengths long, the input Z is 100 ohms. . . That last sentence should be "For a 100 ohm load, when the line is *any whole number* of half wavelengths long, the input Z is 100 ohms." Likewise, Now instead of a 50 ohm line, let's connect a half wavelength 100 ohm line to the output of the same 50 ohm SWR meter and hook that to a 50 ohm resistive load. The line's actual SWR is 2:1 and, just like any lossless line, the SWR stays the same regardless of its length. If the transmission line is an even number of half wavelengths long we'll have 50 ohms at the input and the SWR meter will read 1:1, since it's a 50 ohm meter and interprets 50 ohms as 1:1. "an even number of half wavelengths" should be "any whole number of half wavelengths". I appreciate the corrections, and encourage anyone who spots errors to bring them to my attention, or the newsgroup's. Roy Lewallen, W7EL |
Steveo wrote:
if you have over a 2:1 standing wave you can do damage to your finals or linear Depends on what one is running. My IC-706 folds back automatically and protects itself. My SGC-500 linear is advertised to tolerate an SWR of up to 6:1. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
Roy Lewallen wrote:
Some people can put up a huge smokescreen and waving of hands about reflected waves of one kind or another, but at the end of the day the SWR meter can't tell the difference between a resistor and a transmission line terminated with a load, if the impedances the meter sees are the same. It's sensitive only to impedance; A 20K ohms/volt Simpson may yield an irrelevant screen voltage reading for a pentode because it loads the circuit down. Hand waving aside, any instrument can be misused. An SWR meter designed and calibrated for a Z0=50 standing-wave environment may yield an irrelevant reading when operated outside of a Z0=50 ohm standing-wave environment. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
Reg Edwards wrote:
Roy, to cut things short, why don't you just say SWR meters don't measure SWR on anything. All they do is indicate whether or not the transmitter is terminated with its correct load resistance. So they are quite useful. Reg, how about my 450 ohm SWR meter? It just sits there reading somewhere between 6:1 and 12:1. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
Ian White GM3SEK wrote:
Reg Edwards wrote: Stop fooling and confusing yourselves. The solution to everybody's problems is simple - just change the name of the thing to TLI. (Transmitter Loading Indicator). Or - recalling that what the meter actually measures is the reflection coefficient - why not go back to the old name of "Reflectometer"? Trouble is, during steady-state, they only measure the virtual reflection coefficient which is itself confusing since it is not the same as the physical reflection coefficient measured by a TDR. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
"Cecil Moore" wrote:
An SWR meter designed and calibrated for a Z0=50 standing-wave environment may yield an irrelevant reading when operated outside of a Z0=50 ohm standing-wave environment. ___________________ Elaborating, an SWR meter will produce ~ accurate readings for an unknown termination connected to it via a lossless transmission line of any length, as long as that line has the same Zo as the sample section in the SWR meter. It is only when the transmission line Zo varies from the Zo of the SWR meter line section that accurate measurement of load SWR is problematic. Selecting line lengths and line impedances to make an SWR meter and/or tx "happy" when connected to an antenna doesn't necessarily mean that the all components in the r-f output system have low SWR. The tx may be able to deliver more power to the net load under those conditions, but SWR may still exist on the transmission line capable of causing its failure. RF |
"Ian White wrote - Stop fooling and confusing yourselves. The solution to everybody's problems is simple - just change the name of the thing to TLI. (Transmitter Loading Indicator). Or - recalling that what the meter actually measures is the reflection coefficient - why not go back to the old name of "Reflectometer"? =================================== It does NOT read the reflection coefficient. It reads only half of it. At least half of the information lies in the angle of the RC - which is disregarded, ignored, by the so-called meter. The magnitude of the RC without its angle is just another worthless number. It can't be used for anything except to calculate a fictional SWR. ---- Reg, G4FGQ |
Reg Edwards wrote:
The magnitude of the RC without its angle is just another worthless number. It can't be used for anything except to calculate a fictional SWR. Actually, it is pretty useful for a Z0-matched system since there is one and only one unique solution at the Z0-match point. In a Z0-matched system, all forward and reflected voltages and currents are at the reference zero degrees or at 180 degrees so all the phase angles are known without measuring them. The physical reflection coefficient is a function of Z01 and Z02 at a Z0-match point. The sign of the reflection coefficient corresponds to either zero degrees or 180 degrees and depends on whether (Z01 Z02) or (Z01 Z02). Since the great majority of amateur radio systems are close to a Z0-match, this becomes a useful analysis tool for the most common cases. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
What is the reason a 2:1 SWR can cause such havoc?
How can I avoid this catastrophic condition? I feed my dipoles with 450 Ohm ladder line, but the last 20 feet or so is 50 Ohm coax, I guess that makes it work ok. I haven't blown up my finals yet. Lions and tigers and bears Oh my... "Steveo" wrote in message news:nceoaqqpc0a3yzz.280620052102@kirk... if you have over a 2:1 standing wave you can do damage to your finals or linear |
On Tue, 28 Jun 2005 22:15:18 GMT, Lancer wrote:
So thats all my tuner does, lengthen or shorten the coax? Are you sure about that? **** Essentially yes. Without having to go into detailed mathematics, it is the simplest form to explain what is happening. james |
On Tue, 28 Jun 2005 15:53:03 -0700, Roy Lewallen
wrote: It's a little more complicated than that. The line doesn't simply multiply or divide the impedance by a constant, like a transformer -- except in the special case of a quarter electrical wavelength line or odd multiples thereof. *** Roy I believe this thread started on rec.radio.cb and yes your correct here. I just did not want to get into great details on quarter wave sections and uses of transmission lines as lumped elements. I though that was beyond the scope of the original post. I am kind of sorry that I even mentions what I did. james |
Balderdash!
"james" wrote in message ... On Tue, 28 Jun 2005 22:15:18 GMT, Lancer wrote: So thats all my tuner does, lengthen or shorten the coax? Are you sure about that? **** Essentially yes. Without having to go into detailed mathematics, it is the simplest form to explain what is happening. james |
if you have over a 2:1 standing wave you can do damage to your finals
or linear Oh brother. Here we go again with more nonsense and myths about SWR! 73 Tom |
Reg Edwards wrote:
Roy, to cut things short, why don't you just say SWR meters don't measure SWR on anything. He did, he just felt compelled to add a page or so of explaination. All they do is indicate whether or not the transmitter is terminated with its correct load resistance. So they are quite useful. Well, to be picky all they do is indicate the divergence from the Zo of the meter, in a certain way. If the TX is designed for that Zo then they do what you say, and they're quite useful. They won't even tell you what the load resistance actually is unless the load is exactly correct. Yes Stop fooling and confusing yourselves. The solution to everybody's problems is simple - just change the name of the thing to TLI. (Transmitter Loading Indicator). Hmm. I'll stick with SWR meter -- which it is if it's used properly. -- ------------------------------------------- Tim Wescott Wescott Design Services http://www.wescottdesign.com |
Buck wrote:
I believe he is right. Radios drop power when they don't like the SWR and raise it when it does. That depends on the radio. Without SWR protection one with a class C final, like the ones in the little QRP rigs I have lying around, will deliver more power if it sees a lower RF impedance at the final transistor than it was designed for. It will also overheat said final transistor* and possibly damage it. This will happen for some SWR mismatches but not all. Again without SWR protection one with a class AB or B final, properly tuned for a 50 ohm resistive load, will deliver less power for some mismatches (the same mismatches that would be _higher_ power for the class C final). With other mismatches it would exhibit higher gain but more distortion. At some mismatch and level of drive you could probably expose the finals to too much power dissipation, too high an RF current or too high an RF voltage, and do damage. This depends _heavily_ on the design of the final stage. With SWR protection, of course, the radio will automatically back off, perhaps even in a way that will do some good. So I will use an SWR meter to keep the transmitter happy, and a field strength meter to make sure my antenna is doing it's job. * assuming I got the heatsink design right, neither overly conservative nor overly optimistic. ------------------------------------------- Tim Wescott Wescott Design Services http://www.wescottdesign.com |
james wrote:
Lancer wrote: So thats all my tuner does, lengthen or shorten the coax? Are you sure about that? Essentially yes. Without having to go into detailed mathematics, it is the simplest form to explain what is happening. If you include the possibility of changing the Z0 of the coax as well as the length, you will be closer to the truth. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
Buck wrote:
I believe he is right. Radios drop power when they don't like the SWR and raise it when it does. This is an illustration of a common problem. It's really improper *impedances* presented to the radio that disturb it; it doesn't know or care about the actual SWR on whatever transmission line may or may not be connected. Transmitters typically specify and show this load impedance as "SWR". But they can't tell the difference between a half wavelength 50 ohm line with 100 ohm load, which has a line SWR of 2:1; any length of 100 ohm line with a 100 ohm load, which has a line SWR of 1:1; a quarter wavelength of 300 ohm line with a 900 ohm load, which has a line SWR of 3:1; or a 100 ohm resistor. All these and an infinite number of other combinations will present 100 ohms to the rig, all will cause the rig's SWR meter to read 2:1, and all will have exactly the same effect. Roy Lewallen, W7EL |
On Tue, 28 Jun 2005 21:01:52 -0700, "Steveo"
wrote: if you have over a 2:1 standing wave you can do damage to your finals or linear ***** Only if you are exceeding the power dissapation of the devices. Considering the way most CBers use radios and amplifiers, your statement maybe more ture than false. Generaly if the power disapation of the finals is not exceeded and there is sufficient margin to handle the reflected power, it will just dissapate as heat in the output circuits and the fianls. Then this is only true if the reflection coefficient of the radio is zero. If other than zero then there will be some of the antenna power reflected back to the transmitter reflected back to the load. Then the rest is dissapated as heat. Then you get all kinds of funny things happening inside the coax. But that is another subject. james "Frank Gilliland" wrote in message .. . On 28 Jun 2005 17:51:10 -0700, "K7ITM" wrote in . com: snip But there's a real problem in communicating this. If you hook a 50 ohm SWR meter to the input of a 75 ohm, 300 ohm, or line of any impedance other than 50 ohms, the meter reading won't be the SWR on the transmission line. That can mislead people into thinking that the SWR is changing with line length when it actually isn't. In addition, most hams (and other non-professionals -- and even many professionals) don't bother to check that their SWR meter is properly calibrated to the impedance they think it is. Most are nominally 50 ohms, but they can be built for any practical line impedance. Checking calibration is not all that difficult, if you take the time to do it. In addition, your nominally 50 ohm line (or 75 or whatever) can have an actual impedance 10% or more from the nominal value. If you have properly calibrated your meter to 50 ohms, and your line is 60 ohms, you would read 1.2:1 SWR when your line is actually 1:1. And if the SWR on the 60 ohm line is 1.2:1, that 50 ohm SWR meter can read anything between 1:1 and 1.44:1, depending on the line length and its load. Finally, though you may have checked that the meter to reads 1:1 with a 50 ohm load and infinity to 1 with a short or open load, the construction of inexpensive meters may cause them to have significant errors at other load impedances. Impedance matching of an SWR meter is generally unimportant since most SWR meters used for HF have a directional coupler that is much shorter than the operating wavelength. Regardless, I'm not a big fan of SWR meters -- they are good for detecting a major malfunction but that's about it. Antenna tuning/matching is best done with a field strength meter. ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
On Wed, 29 Jun 2005 11:07:17 -0400, "Fred W4JLE"
wrote: What is the reason a 2:1 SWR can cause such havoc? How can I avoid this catastrophic condition? I feed my dipoles with 450 Ohm ladder line, but the last 20 feet or so is 50 Ohm coax, I guess that makes it work ok. I haven't blown up my finals yet. Lions and tigers and bears Oh my... ***** Actually can happen if you push the finals to where there is insufficeint margin to the maximum heat dissapation. Tubes are a bit more forgiving. Transistor inadequately heatsinked and overdriven, typical CB usage, often have little of no margin for heat dissapation. If the transmitter has a refelction coefficient of zero and the load say .3, then that reflected power from the load is dissapated as heat in the output circuits and any final transistors or tubes. Now if the radio has a reflection coefficient other than zero that will lessen the heat dissapation on the transimiiter. Now you get load and source reflections convoluting within the transmission line. You ought to model a 400 Mhz square wave with source and load refelctions coefficients other than zero. It can get ugly james |
On Tue, 28 Jun 2005 23:17:15 -0500, Cecil Moore
wrote in : Frank Gilliland wrote: Impedance matching of an SWR meter is generally unimportant since most SWR meters used for HF have a directional coupler that is much shorter than the operating wavelength. Point is that they are usually calibrated for Z0=50 ohms and are in error when used in Z0 environments differing from Z0=50 ohms, e.g. Z0=75 ohms. The point is that the error is insignificant when the directional coupler is much shorter than the wavelength. The error is even more insignificant when there are a host of variables and confounds between the SWR meter and the transmitted field that can (and frequently do) affect the objective -- field strength. It's much simpler (and just plain logical) to measure the field strength directly instead of measuring an abstract value halfway towards the objective and relying on nothing more than speculation that the rest is working according as expected. ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
"Frank Gilliland" wrote in message ... On Tue, 28 Jun 2005 23:17:15 -0500, Cecil Moore wrote in : Frank Gilliland wrote: Impedance matching of an SWR meter is generally unimportant since most SWR meters used for HF have a directional coupler that is much shorter than the operating wavelength. Point is that they are usually calibrated for Z0=50 ohms and are in error when used in Z0 environments differing from Z0=50 ohms, e.g. Z0=75 ohms. The point is that the error is insignificant when the directional coupler is much shorter than the wavelength. It is the directional coupler that is balanced for a particular value of Z0. Tam/WB2TT The error is even more insignificant when there are a host of variables and confounds between the SWR meter and the transmitted field that can (and frequently do) affect the objective -- field strength. It's much simpler (and just plain logical) to measure the field strength directly instead of measuring an abstract value halfway towards the objective and relying on nothing more than speculation that the rest is working according as expected. ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
Frank Gilliland wrote:
Point is that they are usually calibrated for Z0=50 ohms and are in error when used in Z0 environments differing from Z0=50 ohms, e.g. Z0=75 ohms. The point is that the error is insignificant when the directional coupler is much shorter than the wavelength. Nope, that's not the point at all. It is true that a 50 ohm SWR meter designed for HF may not work on 70 cm but the error I'm talking about is the calibration error in a 50 ohm SWR meter designed for HF and used on HF in, for instance, a Z0 = 450 ohm environment instead of its calibrated-for 50 ohm environment. It works perfectly in a 50 ohm environment at the HF frequency of operation. Here's the proof using a 50 ohm SWR meter: XMTR--1/2WL 450 ohm line--SWR meter--1/2WL 450 ohm line--50 ohm load The 50 ohm SWR meter will read 1:1, nowhere near the actual SWR XMTR--1/4WL 450 ohm line--SWR meter--1/4WL 450 ohm line--50 ohm load The 50 ohm SWR meter will read 81:1, nowhere near the actual SWR An SWR meter calibrated for 450 ohms will correctly read 9:1 in both cases. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
james wrote:
If the transmitter has a refelction coefficient of zero and the load say .3, then that reflected power from the load is dissapated as heat in the output circuits and any final transistors or tubes. Sometimes yes, sometimes no. If the reflected current arrives out of phase with the forward current, then the final dissipation can actually be *reduced* by the mismatch. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
On Wed, 29 Jun 2005 16:42:49 -0500, Cecil Moore
wrote: Sometimes yes, sometimes no. If the reflected current arrives out of phase with the forward current, then the final dissipation can actually be *reduced* by the mismatch. ***** Power is power. Phase is not a problem. Take the mafnitude of the transmitted power and teh magnitude of the reflected power. The results are phaseless. The magnitudes add linearly. QED james |
On Wed, 29 Jun 2005 17:28:01 -0400, "Tam/WB2TT"
wrote: It is the directional coupler that is balanced for a particular value of Z0. Tam/WB2TT ***** Correct james |
Frank Gilliland wrote, among other things, "The point is that the error
is insignificant when the directional coupler is much shorter than the wavelength." Certainly "directional couplers" for HF may be built at essentially zero length, and ideally would have exactly zero length, monitoring the current and voltage at a single point on a line. Then SWR or reflection coefficient magnitude or even complex reflection coefficient may be calculated under the assumption we know the desired reference impedance. But if the equipment combines the voltage and current samples in the wrong ratio, you will get the WRONG answer. Even if the coupler looks like a perfect 50 ohms impedance section of transmission line (with some attenuation), the error _in_measurement_output_ can be significant indeed. Just because the coupler looks like a 50 ohm line to the line it's hooked to doesn't mean it will read zero reflection when IT's presented with a 50 ohm load. And by the way, not everyone who measures and cares very much about SWR (or reflection coefficient) cares a whit about field strength. Not all loads are antennas. Indeed, as Reg says, we might do better in amateur applications to consider the SWR meter as an indicator of the degree to which we're presenting a transmitter with the desired load. That's really what we're using it for, most of the time. It may ALSO be interesting to know the field strength, but please be aware that a transmitter's distortion products may be significantly higher if it's presented the wrong load impedance, even though the power output may be increased. Field strength alone is not acceptable to me as a means to adjust an antenna load to a transmitter, or as a way to adjust the operating point of the transmitter. Cheers, Tom |
james wrote:
On Wed, 29 Jun 2005 11:07:17 -0400, "Fred W4JLE" wrote: What is the reason a 2:1 SWR can cause such havoc? How can I avoid this catastrophic condition? I feed my dipoles with 450 Ohm ladder line, but the last 20 feet or so is 50 Ohm coax, I guess that makes it work ok. I haven't blown up my finals yet. Lions and tigers and bears Oh my... ***** Actually can happen if you push the finals to where there is insufficeint margin to the maximum heat dissapation. Tubes are a bit more forgiving. Transistor inadequately heatsinked and overdriven, typical CB usage, often have little of no margin for heat dissapation. If the transmitter has a refelction coefficient of zero and the load say .3, then that reflected power from the load is dissapated as heat in the output circuits and any final transistors or tubes. Now if the radio has a reflection coefficient other than zero that will lessen the heat dissapation on the transimiiter. Now you get load and source reflections convoluting within the transmission line. You ought to model a 400 Mhz square wave with source and load refelctions coefficients other than zero. It can get ugly james Consider the MRF 140, a 150 Watt 2.0 - 150.0 Mhz N-Channel linear RF power fet. From the technical data sheet: "100% Tested For Load Mismatch At All Phase Angles With 30:1 VSWR." You'd have a tough time damaging this device with a mere 2:1 VSWR. How do load and source reflections convolute within the transmission line? That's a new one on me. My old dictionary defines 'convolute' as "Rolled or folded together with one part over another; twisted; coiled." The rest of the post is pretty fanciful, too. A trip to the library would do wonders. 73, Tom Donaly, KA6RUH |
james wrote:
On Wed, 29 Jun 2005 16:42:49 -0500, Cecil Moore wrote: Sometimes yes, sometimes no. If the reflected current arrives out of phase with the forward current, then the final dissipation can actually be *reduced* by the mismatch. ***** Power is power. Phase is not a problem. Take the mafnitude of the transmitted power and teh magnitude of the reflected power. The results are phaseless. The magnitudes add linearly. QED james Cecil was talking about current, not power. You can't add power the way you can voltage and current. If you could, you could build a very nice perpetual motion machine just by using the reflections in a transmission line to add power so that the output was greater than the input. 73, Tom Donaly, KA6RUH |
The rig has no way of detecting any alleged "reflected power". It can't
tell the difference between a feedline with a lot of "reflected power", a feedline with no "reflected power", and a plain resistor. It behaves exactly the same in all cases, provided only that the impedance that each provides to it is the same. Anyone not convinced of this should put a couple or more dummy loads in series or parallel, make up a few lengths of transmission line of various impedances, and see for himself. Roy Lewallen, W7EL james wrote: On Wed, 29 Jun 2005 16:42:49 -0500, Cecil Moore wrote: Sometimes yes, sometimes no. If the reflected current arrives out of phase with the forward current, then the final dissipation can actually be *reduced* by the mismatch. ***** Power is power. Phase is not a problem. Take the mafnitude of the transmitted power and teh magnitude of the reflected power. The results are phaseless. The magnitudes add linearly. QED james |
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