Richard Clark, KB7GHQ wrote:
"No one expects a binary engineer can (answer that)."

I have a different take on reflection of the reflected wave at the
generator. I think current results from potential difference. When there
is no difference, there is no current.

Suppose you have an ideal transformer with a perfectly centertapped
secondary. Volts are the same on both sides of the centettap but
180-degrees out of phase with respect to the centertap. Connect the
extremes together and a high current results from the short circuit.

Suppose you modify the secondary by untwisting the sentertap and this
results in two identical secondary coils. Connect these in the same
phase in parallel. No current flows between the coils because no
potential difference ever exists between the coils.

An ideal transmission line with a complete reflection at its far end is
much like the transformer with two identical secondaries. The incident
and reflected voltages are equal and at some points can completely add
or subtract.

Back at the generator connected to a line with a complete reflection at
the load end, there are line lengths which produces a reflection
arriving back at the generator 180-degrees out of phase with the
generator voltage. This produces the equivalent of a short circuit on
the generator.

If line length results in reflected volts exactly in-phase with
generated volts, no current flows into the line once steady-state
conditions are established. This is what happens in the short-circuited
1/4-wave stub (metal insulator). It is the standoff between identical
voltages which produces the extremely high impedance at the input to the
stub.

I have not tried my Bird wattmeter on this. Maybe Cecil has and will say
I am wrong.

Best regards, Richard Harrison, KB5WZI