On Tue, 19 Jul 2005 01:45:26 -0500, Cecil Moore
wrote:

Um, yes. Can tell us why your example exhibits a reflection product
TEN TIMES BRIGHTER THAN THE SUN; when in your words it has canceled
completely? :-)

It doesn't. All reflections are eliminated by wave cancellation.
That is a given boundary condition for the simple example.

What a larf. :-)

If you can't explain it, you simply re-write the math to suit the
outcome? This is neither demonstrable nor provable, unless, of course
you simply fudge the numbers until they agree with your result. Given
that every reader here has had the opposite experience as your
prediction, this is classic thumb on the scale work - quite shabby.

Richard Clark wrote:

Cecil Moore wrote:
Um, yes. Can tell us why your example exhibits a reflection product
TEN TIMES BRIGHTER THAN THE SUN; when in your words it has canceled
completely? :-)

It doesn't. All reflections are eliminated by wave cancellation.
That is a given boundary condition for the simple example.

If you can't explain it, you simply re-write the math to suit the
outcome?

The purpose of the laser example is to make it as much like a
transmission line example as possible. A Bird wattmeter indicates
that all reflections are eliminated in the T-line example so
the laser example assumes that as a boundary condition. Your
insistance on rewriting the math to make it as different from a
T-line example as possible is simply a diversion away from the
original purpose.
--
73, Cecil http://www.qsl.net/w5dxp

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On Tue, 19 Jul 2005 02:42:22 -0500, Cecil Moore
wrote:

The purpose of the laser example is to make it as much like a
transmission line example as possible. A Bird wattmeter indicates
that all reflections are eliminated

Never met the class of Bird wattmeter that measures laser - and
neither have you. Get your thumb off the scale and put it where it
belongs.