Richard Clark wrote:
"Again, what is the vector of direction for the light bulb?"

Electromagnetic waves include light and heat whicjh have extremely short
wavelengths. The light bulb may not be a perfect point source but the
waves travel away from the source with the velocity of light and consist
of electric and magnetic fields that are at right angles to each other
and also at right angles to the direction of travel. Wave energy is
divided 50-50 between the electric and magnetic fields.

Many frequencies (colors) make up the radiation from a light bulb. Much
more heat is radiated than visible light.

In a radio wave the essential properties are frequency, intensity,
direction of travel, and plane of polarization, For the constituents of
light bulb radiation, it is the same.

300 million m/sec is the velocity and this equals the product of
frequency X wavelength. Emissions of a light bulb are of extremely high
frequency but of extremely short wavelenggth too.

All points on a wavefront are equidistant from the source and emerged
simultaneouslly so they share the same phase.. From a point source light
bulb we would be in the far field.

The field is transverse. The power flow (J.D. Kraus` words), or Poynting
vector, is entirely radial.

Best regards, Richard Harrison, KB5WZI

On Thu, 21 Jul 2005 01:24:36 -0500, (Richard
Harrison) wrote:

Many frequencies (colors) make up the radiation from a light bulb. Much
more heat is radiated than visible light.

Hi Richard,

Actually that is quite wrong. IR is not heat, it is radiation. Heat,
actually phonons, constitutes something less that 10% of the
conversion of electrical power in a light bulb. Lest we take off on
the tangent of IR bulbs being used for heating, it is the load of that
IR radiation (directed upon a dissipative surface) that renders
phonons, otherwise IR is radiated in exactly the same manner as any
radiation. There are any number of simple, practical tests to confirm
this. For one, IR passes through most glass without heating it. You
have to go out of your way to obtain IR blocking glass (which doesn't
even absorb that much either). There are some IR wavelengths that go
right through water, and others that are entirely absorbed.

However, this is not about heat, nor IR, nor even the loss of a
principle vector property, its angle notation, or even the whole
absence of the vector property from the solution to wave interference
powers. Rather, it is about the facade of complete cancellation

Entirely ignoring all these other trivial details, that cancellation
is incomplete in and of necessity for real or imagined initial
conditions. This is revealed in any mathematical solution, and
certainly by examination.

73's
Richard Clark, KB7QHC

Richard Clark wrote:
Entirely ignoring all these other trivial details, that cancellation
is incomplete in and of necessity for real or imagined initial
conditions.

That's not true, Richard. If zero reflected energy reaches the
source in a system with reflections, a Z0-match has been
achieved. For a Z0-match to be achieved, 100% wave cancellation
is necessary. For all the nearly perfectly Z0-matched systems
out there, near perfect wave cancellation of reflected waves
has been achieved.
--
73, Cecil http://www.qsl.net/w5dxp


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Richard Clark wrote:
"Actually that is quite wrong. IR is not heat."

He got me. According to Lincoln`s Industrial Reference, from a 100-watt
MAZDA lamp the amount of energy emanating as light is 10%, and as
infrared is 72%. The rest is lost to gas end loss, etc. The loss would
be only 18% You can`t see infrared. The eye is most sensitive to a
yellow-green color around 5550 Angstrom units. Lamps are made to
emphasize white or "daylight" which is rated at about 2400 to 3100
degrees Kelvin.

Best regards, Richard Harrison, KB5WZI

On Thu, 21 Jul 2005 09:47:12 -0500, (Richard
Harrison) wrote:

Richard Clark wrote:
"Actually that is quite wrong. IR is not heat."

He got me. According to Lincoln`s Industrial Reference, from a 100-watt
MAZDA lamp the amount of energy emanating as light is 10%, and as
infrared is 72%. The rest is lost to gas end loss, etc. The loss would
be only 18% You can`t see infrared. The eye is most sensitive to a
yellow-green color around 5550 Angstrom units. Lamps are made to
emphasize white or "daylight" which is rated at about 2400 to 3100
degrees Kelvin.

Hi Richard,

Well, your ability to research the topic continues well in advance of
other's effort. Some may note the congruence of the specified
emission peak and my statements earlier choosing exactly this same
wavelength. This is called the eye's photopic response, but at night
it shifts slightly to become more sensitive in its scotopic response.
This is rod vision and occurs around the 510nM (5100Å) wavelength or a
pale blue.

The unintended consequence of this is that it suppress the eye's
ability to perceive red light at night (why you see them used in dark
rooms and WWII movies) which is something of a bummer for traffic
lights and taillights (they have to be brighter than they would be
normally).

Also, this discussion bears upon the answer to
"What is the wavelength of Glare?"
that has remained undiscovered by binary engineers. I bet our Readers
can catch this clue. :-)

73's
Richard Clark, KB7QHC

Richard Clark wrote:
"The unintended consequence of this (exposure to white light) is that it
suppresses the eye`s ability to perceive red light at night (why you see
them (red lights) used in dark rooms and WWII movies--..)"

I was in WW-2 and confirm that aboard my ship our chartroom (the
compartment with an opening tp tje outside) indeed was illuminated with
red lamps so that we would not be blind when we stepped outside. We were
told that we used our cones in the daytime and our rods at night. How
could I ever have remembered that?

From Lincoln`s Reference: Glare is said to reduce the ability to see,
and hastens fatigue. Glare is wasted since it lowers the effectiveness
of useful light. Glare is high light energy over a measurable period of
time from above normal angles of vision (30 to 90-degrees above the
vertical). I think this means you don`t want a bright light shining in
your eyes. It`s glaring and impairs vision for awhile.

I wasn`t a signalman but I noticed our signaling light was fitted at
night with a red filter called the "Nan-gear". Our phonetic alphabet in
those days went: able, baker, charlie, dog---nancy. I suppose Nan was
short for nighttime gear. I speculate it was hoped that the enemy would
step out of white lighted quarters and not notice our red signal beams.
So much for red lights and glare.

It probably wouldn`t work, but you might say to the policeman: I didn`t
see the red light. The white glare desensitized my eyes!

Best regards, Richard Harrison, KB5WZI

Nan gear was infra-red, not red. The purpose was to be non detectable
without special equipment.

"Richard Harrison" wrote in message
...
Richard Clark wrote:

I wasn`t a signalman but I noticed our signaling light was fitted at
night with a red filter called the "Nan-gear". Our phonetic alphabet in
those days went: able, baker, charlie, dog---nancy. I suppose Nan was
short for nighttime gear. I speculate it was hoped that the enemy would

On Thu, 21 Jul 2005 16:17:13 -0500, (Richard
Harrison) wrote:

From Lincoln`s Reference: Glare is said to reduce the ability to see,
and hastens fatigue. Glare is wasted since it lowers the effectiveness
of useful light. Glare is high light energy over a measurable period of
time from above normal angles of vision (30 to 90-degrees above the
vertical). I think this means you don`t want a bright light shining in
your eyes. It`s glaring and impairs vision for awhile.

Hi Richard,

Your continued research into the topic that the originator could not
identify reveals the problems of Glare being a subjective response and
not a technical specification.

However, I have already provided technical clues to answer:
"What is the wavelength of Glare?"
that has so far evaded absolutely any response from our binary
engineer.

So far the suggestions have been that it matters to a WHO, and there
is a practical WHY to reveal the WHEREFORE. The differences in
Photopic and Scotopic vision narrow down the wavelength, but there is
a vast gulf between them. Even being a binary choice, there is still
the chance of being wrong that puts the gag on his stepping forward
with an answer. In the end I will be alone in completing this I
suppose. It will cap off my full mathematical treatment and the
exposure of this full cancellation that is TEN TIMES BRIGHTER THAN THE
SUN ;-)

This topic of Glare, being his alone, has subsequently been identified
by him as being inconsequential detail, or better yet, wholly from my
distorted imagination (but only when I examine this point).

There is still much to mine here. With errors so abundant, it is
difficult to choose any one aspect and not have to correct three
aspects of its distortions.

73's
Richard Clark, KB7QHC

Richard Clark wrote:
This topic of Glare, being his alone, has subsequently been identified
by him as being inconsequential detail, ...

EXACTLY!!! When the glare is exactly the same frequency as the
forward laser beam, and when refraction has been eliminated,
as it is in a transmission line, your postings become completely
irrelevant, but I am not surprised since you seem to be protecting
some cow you consider to be sacred.
--
73, Cecil http://www.qsl.net/w5dxp

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Richard Harrison wrote:
It probably wouldn`t work, but you might say to the policeman: I didn`t
see the red light. The white glare desensitized my eyes!

There was a guy in my home town, who for decades, honked his
horn when encountering a red light, because he was color blind.
Everyone knew he would just blow through a red-light, honking
his horn, so everyone gave him the right-of-way. Finally, he
encountered a deaf person ...
--
73, Cecil http://www.qsl.net/w5dxp

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