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On Tue, 30 Aug 2005 20:05:05 -0700, dansawyeror
wrote: I have tried several parameters and have gotten results from a very low level with a close match to over 90% of power radiated in the feedline when the dipole resonance is far from the transmit frequency. We may use this model for a couple of things. It is available and it predicts radiation. That gives the opportunity to create a test. I for one are willing to experiment. Dan Will you please describe the details of your experiment where you claim 90% of the power is radiated from the feedline? How did you make this measurement? Walt, W2DU |
I have to call BS on this one Dan!
On Tue, 30 Aug 2005 20:05:05 -0700, dansawyeror wrote: I have tried several parameters and have gotten results from a very low level with a close match to over 90% of power radiated in the feedline when the dipole resonance is far from the transmit frequency. We may use this model for a couple of things. It is available and it predicts radiation. That gives the opportunity to create a test. I for one are willing to experiment. Dan |
Reg, G4FGQ wrote:
"Perhaps somebody might be prepared to state the power actually radiated from feedlines in watts." Someone has. A feedline is a way to get energy from here to there. Usually we want to keep all the energy on or close to the line as it travels and lose as little as possible to radiation and conversion to heat. Terman gives an approximate formula credited to Sterba and Feldman for radiation from a 2-wire nonresonant line, provided that the lengrh is at least 20X the spacing and the spacing is less than 0.1 wavelength: Radiated power/Isquared=160(pi D/lambda)squared. D/lambda is the spacing in wavelengths I is the rms line current. Terman notes that the parallel line radiates 4X the power that a doublet of length equal to the line spacing would, providing that the line and doublet currents are equal. Terman provides a figure to be used to adjust the estimated radiation upwards for longer feedlines (up to 5 wavelengths), and for greater heights (up to 0.5 wavelength above the earth). See 1943 "Radio Engineers` Handbook", page 194. Best regards, Richard Harrison, KB5WZI |
Dan wrote:
"We may use this model for a couple of things." Dan attached a posting from Reg, G4FGQ. Reg`s description of the "Centre-Fed Dipole - Radiation from Coaxial Feedline" tells it as it is. About 45 years ago, I (Richard Harrison) worked for a company exploring for oil in the Chaco Jungle of Bolivia. Communications were by HF radio at all sites in the jungle and at offices in Cochabamba and La Paz. Radios were Collins 30K-5 transmitters and 51-J receivers at all locations. All antennas were center-fed 1/2-wave dipoles up only about 1/4-wave due to economics and generally were broadside to some favored direction. The feedline was also about 1/4-wavelength for convenience, but the antennas loaded, took a lot of power and the 30-K finals dipped OK. Soil at the radio sites was mostly sand and didn`t really ground anything very much. The length of the coax presented a high impedance to the outside shield of the coax cable at the dipole, whatever it might have been. At 1/4-wave antenna height, directionality was small and whatever the coax radiated, it likely filled-in any nulls. All stations could clearly hear all others all day, so the operators were satisfied. Much of the radiation was straight up so we likely bebefitted from near vertical incidence propagation. The transmitters shook the aether with their power, but the 51-J has a nice dial but not much else. Nevertheless, everything worked. My previous employer had given away all its 51-J`s, they were so sorry, and replaced them with Hammarland SP-600`s. I didn`t take a 51-J, I was using one of the Super Pro`s. My experience is anecdotal. Best regards, Richard Harrison, KB5WZI |
"Cecil Moore" wrote in message ... dansawyeror wrote: Below is a link to a site that claims to model coax radiation from a dipole. http://www.smeter.net/feeding/feedpowr.php Please note that the third wire to ground creates the unbalance that causes feedline radiation. You seem to be confusing cause and effect. The cause of the feedline radiation is the existence of that third wire, not SWR. All it proves is that feedline radiation is caused by that third wire path which unbalances the source currents. -- 73, Cecil http://www.qsl.net/w5dxp Cecil How wrong would it be to say that the *coax* part of the line doesnt radiate at all? I see this as a situation where the *outer shield* of a transmission line is conducting current that radiates. It seems that a "balanced" antenna that is comprised of a single conductor and a L shaped conductor that includes the outer conductor of the coax, could be fed with a balanced line for modeling. Jerry |
Jerry Martes wrote:
"Cecil Moore" wrote in message ... dansawyeror wrote: Below is a link to a site that claims to model coax radiation from a dipole. http://www.smeter.net/feeding/feedpowr.php Please note that the third wire to ground creates the unbalance that causes feedline radiation. You seem to be confusing cause and effect. The cause of the feedline radiation is the existence of that third wire, not SWR. All it proves is that feedline radiation is caused by that third wire path which unbalances the source currents. -- 73, Cecil http://www.qsl.net/w5dxp Cecil How wrong would it be to say that the *coax* part of the line doesnt radiate at all? I see this as a situation where the *outer shield* of a transmission line is conducting current that radiates. It seems that a "balanced" antenna that is comprised of a single conductor and a L shaped conductor that includes the outer conductor of the coax, could be fed with a balanced line for modeling. Jerry What I was taught is that in a properly installed antenna system the coax will not radiate. If the antenna is not properly matched to the coax you get current flow along the outside of the coax shield. Dave WD9BDZ |
dansawyeror wrote:
If it is true it proves that a driving a "bad" load can cause the coax feedline to radiate a significant portion of the feed energy. You need to define "bad load". A "bad load" for unbalanced line is a balanced load, no matter what the impedance. A "bad load" for balanced line is an unbalanced load, no matter what the impedance. The third wire used in the aforementioned software is designed to unbalance the system, no matter what the impedance. To illustrate a balanced system, a fourth wire needs to be added in parallel with and about four inches away from the third wire. Then compare the currents in the third and fourth wires under conditions of changing loads. I due intend to perform experiments to measure and verify what is happening and the model. Please feel free to experiment but at least a dozen participants of this newsgroup already know what is happening and have been trying to tell you. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
On Wed, 31 Aug 2005 16:17:42 -0500, "David G. Nagel"
wrote: What I was taught is that in a properly installed antenna system the coax will not radiate. If the antenna is not properly matched to the coax you get current flow along the outside of the coax shield. Dave WD9BDZ Please read: http://www.w2du.com/r2ch21.pdf |
Jerry Martes wrote:
How wrong would it be to say that the *coax* part of the line doesnt radiate at all? The physical construction of the coax (ideal version) ensures that the inside of the coax doesn't radiate because, for ideal coax, the internal currents are perfectly balanced. Any unbalance in the currents is forced to the outside shield by the laws of physics. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
David G. Nagel wrote:
What I was taught is that in a properly installed antenna system the coax will not radiate. If the antenna is not properly matched to the coax you get current flow along the outside of the coax shield. Is "matched" the correct word to use there? A 50 ohm balanced dipole is perfectly "matched" to 50 ohm coax but the feedline will likely radiate. A 50 ohm balanced dipole is not "matched" to 600 ohm balanced line but with proper attention to details the feedline will like not radiate much. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
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