Cecil Moore wrote:

Harry wrote:

Would someone please explain that for me?


DC steady-state does not cause electrons to emit photons.

Except in flashlights, apparently.

For RF photons to be emitted from a copper wire dipole, the
free electrons must be accelerated and decelerated. The DC
component cannot accomplish that feat.

Quantum mechanics is completely unnecessary here, Cecil. I think
Faraday still provides the best explanation.

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