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Harry,
Forget all the nonsense about photons, continuity of space, and other blather. This is simply a matter of mathematics. In general the initial waveform will consist of a constant DC level and a number of AC components. Any DC component in the original pulse is lost when the pulse is differentiated by the transmitting antenna, leaving only the differentiated AC components. Therefore the integral of the differentiated waveform has a zero DC value. Of course one could always add in a constant to the integrated result, but that would not have much physical meaning in the context under discussion. 73, Gene W4SZ Harry wrote: It is said that a transmitted UWB pulse should not have any DC because of the transmitting antenna: "Without getting into the details of the physical generation of UWB waveforms, it is sufficient to note in this regard that the transmitting antenna has the general effect of differentiating the time waveform presented to it. As a consequence the transmitted pulse does not have a DC (direct current) value-the integral of the waveform over its duration must equal zero." (page 4, http://www.antd.nist.gov/wctg/manet/...rt_April03.pdf) Would someone please explain that for me? Thanks! -- Harry |
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