Dear Trabem,

The input impedance seen looking into the series-connected loop is the
RF loss resistance of the loop, in your case about .05 ohms.

If 0.05 is impedance-matched to a 10-ohm receiver then the working Q
only falls to about 100. But it is not an easy matter to match 0.05
ohms to 10 ohms at 60 KHz. ( I do not know the precise input
resistance of your receiver but you get the idea.)

The working Q of any tuned circuit, either series or parallel
connected, when impedance-matched to a load, always results in the
working Q becoming equal to half of the tuned circuit's intrinsic Q.

This is rather obvious because the loss resistance of the tuned
circuit and the load (after being transformed to the tuned circuit
value) are equal to each other.

Of course, impedance-matching also results in maximum voltage and
maximum current being developed in a given load (or receiver). Which
is also a desirable condition.

It is a serious mistake to think in terms only of volts-input to the
receiver. Or only current-input to the receiver. Receiver S-meters
are POWER meters. That's why they can be calibrated in decibels or in
terms of 6dB per S-unit. Or S9 plus so many decibels.

For example, with a 50-ohm receiver, the reference level S9 = 50
pico-watts receiver input power.

Please accept my apologies for digressiing from 5-metre square loops
at 60 KHz.
----
Reg.