OK Reg,

Hi Reg,

Read both of you responses, and it's very clear now that I was
seriously out in a fantasy world with respect to the topic. I feel a
lot closer to reality now.

If you can, check the latest comments between Richard and myself. I
think I'm getting it, or at least the first approximation::

You provided a key piece of info when you gave me the verbiage about
the loaded Q formula in a series tuned loop. When I started out, I had
no idea that the loaded Q could possibly drop so much when connected
to a receiver!

The working Q of any tuned circuit, either series or parallel
connected, when impedance-matched to a load, always results in the
working Q becoming equal to half of the tuned circuit's intrinsic Q.

I knew this already!

My big problem was in realizing that the loop impedance was so very
very low. Once Richard got me a closer approximation of the actual
number, it became VERY clear to me that there was no impedance match
in my original configuration! Richard suggested the impedance of the
loop was 2K, I guessed it was 2 ohms, but the actual figure was in the
milliohm range.

I feel SO MUCH better now and I think I'm much better off thanks to
your (and Richard's) patience. Thank you so much for helping me to get
to this point!

T