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#91
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On Sat, 5 Nov 2005 18:15:30 +0000 (UTC), "Reg Edwards"
wrote: "Cecil Moore" wrote Of course, you have deviated considerably from the original infinite number of coherent sources. You guys sure know how to enjoy yourselves trying to analyse hypothetical situations. So now there are at least two of you who can't find the "missing" power. Kelvinator is winding up a pitch to bounce another piece of chalk off your noggin, Reg. Fumbling what-ifs and nary a number from anyone. "WORK?!?" [with apologies to Maynard G. (for Walter) Krebs, rip]. |
#92
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Or, better still, forget all about the original exceedingly
ill-defined question by a leg-puller. You have been trolled. You should be ashamed of yourselves for being taken in by such a question. Hello Reg, I wrote the original question. It may be dumb but it was not facetious. I am not a troll. Happy birthday, Ron, W4TQT |
#93
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![]() Richard Clark wrote: EZNEC+ ver. 4.0 Dipole in Ring of Sources 11/2/2005 10:00:48 PM --------------- LOAD DATA --------------- Frequency = 70 MHz Load 1 Voltage = 4.783 V. at 23.52 deg. Current = 0.06643 A. at 23.52 deg. Impedance = 72 + J 0 ohms Power = 0.3177 watts Total applied power = 2000 watts Total load power = 0.3177 watts Taking the determination above as the "standard" I then have progressed to place an NBS yagi in three space about the center to obtain its best result. All such expressions (x,y,z) of the placement of the NBS yagi are with respect to its "driven" element. 0,0,0 Power = 0.2091 watts .5,0,0 Power = 0.2198 watts 1,0,0 Power = 0.1429 watts 1.5,0,0 Power = 0.1026 watts 2,0,0 Power = 0.1601 watts 2.5,0,0 Power = 0.2113 watts 3,0,0 Power = 0.1571 watts 3.5,0,0 Power = 0.06028 watts 4,0,0 Power = 0.04128 watts So, within one quadrant, and over the space of roughly a wavelength, and at intervals of roughly one eighth wavelength, nothing emerges as being equal to the "standard" above. Except perhaps a hidden peak between 0,0,0 and .5,0,0. To investigate this: .25,0,0 Power = 0.2286 watts examining further: .125,0,0 Power = 0.2219 watts nope, examining further: .375,0,0 Power = 0.2278 watts nope, examining further: .30,0,0 Power = 0.2291 watts nope, examining further: .35,0,0 Power = 0.2285 watts nope, looks like the one before at .30,0,0 is the new sweet spot. Now, to proceed to investigate the other quadrants to see if there is symmetry: -3.5,0,0 Power = 0.03997 watts 0,3.5,0 Power = 0.005925 watts 0,-3.5,0 Power = 0.005859 watts This last offers that on the Y axis there is a strong symmetry, and along the X axis there is a moderate symmetry. Now, in regard to both the X and the Y axis, there is a moderate symmetry. If we were to look at the fine data attempting to find the peak, we should notice that the "center" of the antenna lies between the "driven" element and its reflector. My having chosen the "driven" element as the nominal center was in error and my guess is that if I re-visited the same quadrant test above, with that new center at the sweet spot, then we would find very strong symmetry in all four quadrants. I will add that the Y axis data supports this due to its strong symmetry that is relatively immune from the choice of antenna center - at least at this scale. Putting that aside, it is enough to suggest that barring an exquisitely positioned peak of rather a sharp rise, then the yagi exhibits a poorer response compared to a dipole of approx. 1.4dB. Others are encouraged to investigate further to reclaim that missing dB or to put the horns to my error. 73's Richard Clark, KB7QHC Hi Richard, I think what you're seeing is the 3-D interference pattern generated by your sources. I'm not sure that really tells us very much about the antennas themselves. You'd need to surround each of the antennas with a uniform field in order to compare them. By uniform, I mean the field intensity toward the antenna is the same in any direction. Thanks, AC6XG |
#94
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Jim Kelley wrote:
I think what you're seeing is the 3-D interference pattern generated by your sources. Richard is not trying to superpose powers again, is he? :-) -- 73, Cecil http://www.qsl.net/w5dxp |
#95
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Jim Kelley wrote:
Hi Richard, I think what you're seeing is the 3-D interference pattern generated by your sources. I'm not sure that really tells us very much about the antennas themselves. You'd need to surround each of the antennas with a uniform field in order to compare them. By uniform, I mean the field intensity toward the antenna is the same in any direction. How about polarization? Roy Lewallen, W7EL |
#96
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![]() Roy Lewallen wrote: Jim Kelley wrote: Hi Richard, I think what you're seeing is the 3-D interference pattern generated by your sources. I'm not sure that really tells us very much about the antennas themselves. You'd need to surround each of the antennas with a uniform field in order to compare them. By uniform, I mean the field intensity toward the antenna is the same in any direction. How about polarization? Roy Lewallen, W7EL Hi Roy, Your guess is better than mine. I think in order not to bias the results, the solution would have to be that each source is randomly polarized, i.e. the Sun redshifted down into the radio spectrum - coming from every direction. The ring of point sources is an interesting approach. One could use rings at some number of elevation angles, both above and below the plane of the antennas. The greater the elevation angle, the smaller the diameter of the ring such that the radial distance to the antenna is kept constant. But I imgaine you have ideas of your own in this regard. 73, ac6xg |
#97
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#98
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On Mon, 07 Nov 2005 11:16:08 -0800, Jim Kelley
wrote: I think what you're seeing is the 3-D interference pattern generated by your sources. Hi Jim, 3D in two-space? No. I'm not sure that really tells us very much about the antennas themselves. You'd need to surround each of the antennas with a uniform field in order to compare them. By uniform, I mean the field intensity toward the antenna is the same in any direction. The problem has symmetry on its side, additional source add to the dipole in equal measure to the yagi. Adding more power does not create the missing power already lost. 73's Richard Clark, KB7QHC |
#99
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On Mon, 07 Nov 2005 15:08:26 -0800, Roy Lewallen
wrote: How about polarization? Hi Roy, How about it? 73's Richard Clark, KB7QHC |
#100
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On Mon, 07 Nov 2005 15:40:58 -0800, Jim Kelley
wrote: One could use rings at some number of elevation angles Hi Jim, This would increase the tedium factor considerably. Simply rotate the ring. 73's Richard Clark, KB7QHC |
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