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Antenna reception theory
Richard Clark wrote:
"You make a loop." There is a difference. The small whip has a high capacitive reactance. The small loop has a high inductive reacvtance. Both have low radiation resistance. But, the loop is more often used to determine EM field strength. You just need the right "fudge factor" to convert antenna voltage tto field strength or vice versa. Best regards, Richard Harrison, KB5WZI |
Antenna reception theory
"Richard Harrison" wrote in message ... Richard Clark wrote: "You make a loop." There is a difference. The small whip has a high capacitive reactance. The small loop has a high inductive reacvtance. Both have low radiation resistance. But, the loop is more often used to determine EM field strength. You just need the right "fudge factor" to convert antenna voltage tto field strength or vice versa. Best regards, Richard Harrison, KB5WZI ===================================== For the very last time I will repeat my question :- "What is the voltage measured between the bottom end of a 1 metre vertical antenna and ground when the field strength is 1 volt per metre. The height (length) of the antenna is much less than 1/4-wavelength. The bottom end of the antenna is immediately above the ground. The ground is assumed perfect. The field is vertically polarised. Frequency, loops, reactance, radiation resistance do not enter into the argument. No other information is needed. Terman, Kraus and Balanis' bibles provide answers to a different question in which I am not interested. Mere mention of these learned gentlemen only confuses the issue. The answer is entirely fundamental to e.m. radiation and reception. All I need is a number of volts. What is it please? ---- Reg, G4FGQ. |
Antenna reception theory
"Reg Edwards" wrote
For the very last time I will repeat my question :- Pray it so... "What is the voltage measured between the bottom end of a 1 metre vertical antenna and ground when the field strength is 1 volt per metre." Of what relevance is this to anyone but (apparently) you? Please elaborate. RF |
Antenna reception theory
On Tue, 20 Dec 2005 22:06:56 +0000 (UTC), "Reg Edwards"
wrote: I normally reply, if I reply at all to your idiotic statements, with "Phooey". Ah yes, Punchinello, As gracious as ever. it should be said Well, you generally fill the gap the that the voltage induced in a circular loop is altogether different which is redundant to the following: and very much smaller from that induced in a straight wire of the same length. Notably you say nothing of how much. For the sake of novices for whom you have such paternal feelings (but absolutely no answers) I would offer that the solution in the loop (that same wire bent over to touch ground) and loaded with 200 Ohms (not an open) reveals a voltage that need only be multiplied by 20 to obtain the correct value. Trivial! And what is more, far simpler to measure across 200 Ohms than an open at 20MHz. Thus in response to the question: On Tue, 20 Dec 2005 14:40:14 GMT, Andy Cowley wrote: And just how are you going to measure that voltage without getting an opposite voltage in your voltmeter leads. has been responded to fully, with a realizable design (barring this folderol of perfect ground) and removing the objection for meter leads. It takes no more software than the free version of EZNEC (zipped up, but it works). Have a miserable Christmas! That will be all too true with a visit to and through several of our nation's airports here soon. ;-( XOXOXOXOX, Richard Clark, KB7QHC |
Antenna reception theory
Richard Harrison wrote:
Reg, G4FGQ wrote: "Terman, Kraus, and Balanis and some computer programs are of no help!" My dictionary defines "field strength" as: "3. The strength of radio waves at a distance from the transmitting antenna, usually expressed in microvolts-per-meter. This is not the same as the strength of a radio signal at the antenna terminals of the receiver." The definition looks OK to me. The reason the signal is not the same as the microvolts-per-meter even when the antenna is a 1-meter length of wire with just the right slant is because the induced voltage gets divided between the antenna and its load (the receiver). No, that's not why. The terminal voltage of an open circuited 1 meter (electrically short) dipole is 1/2 the field strength in volts/meter. The terminal voltage when terminated with a conjugately matched load can be well over a thousand volts (in the theoretical lossless case). But it's pointless to keep repeating this. Reg keeps asking the same question, and you keep responding with the same incorrect answers. I believe I've gotten through to everyone who really wants to know the answers, so I'll let this be my last repetition. Roy Lewallen, W7EL |
Antenna reception theory
"Richard Fry" wrote in message ... "Reg Edwards" wrote For the very last time I will repeat my question :- Pray it so... "What is the voltage measured between the bottom end of a 1 metre vertical antenna and ground when the field strength is 1 volt per metre." Of what relevance is this to anyone but (apparently) you? Please elaborate. RF ========================================= For starters, Have you never heard of field strength measurements? Have you ever designed the input stage of a radio receiver? The topic is fundamental to an understanding of e.m. radiation and reception. Can YOU answer the simple question? Or are you entirely dependent on your gospel faith in 'Bibles'. On this occasion at least, the Bibles are letting dependent people down. The immediate relevance to me is that I have a program which has been reported to have a calculating error. It was reported by a person who is not dependent on bibles. He stated that the conventional/traditional calculating method used in my program was incorrect. I was not entirely convinced so I posed a related question on this newsgroup to which only one person has replied with a number. And he was wrong first time. Other persons who replied, after consulting their bibles, were unable even to answer the question, either rightly or wrongly. They just generated more confusion. The program concerned is GRNDWAV4 which I think, but not absolutely certain, has now been corrected. Why not download it, input a very few standard values, and tell me whether or not it provides the correct answer to receiver power input? You may, of course, prefer not to commit yourself. Is that enough elaboration for you? ---- .................................................. .......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. .......... |
Antenna reception theory
Reg, G4FGQ wrote:
"All I need is a number of volts." I`ll guess, because Reg asked, not because I know aanything. I`ve now discovered Kraus` effective antenna height which may be related to an Icelandic connection. Reg hasn`t told us everything he knows. One reason we don`t know is because the effective antenna height is related to the antenna`s length in terms of wavelength according to Kraus. One of the examples given by Kraus is a dipole of 1/10 of a wavelength. Kraus tells us the effective height of this length gives a factor of 0.5. According to Equation (1) on page 30 of the 3rd edition of "Antennas", Voltage at the terminals of the antenna = effective height X field strength. If we guess that a short whip might have the same effective height as a short dipole, then with a 1 volt per meter field strength X 0.5 as an effective height factor, their product would be 0.5 volts. I`ll assume rms because that`s the convention for expression. I don`t have much confidence in the number because I think you must determine the effective height experimentally. Terman says on page 991 of his 1943 "Radio Enginneers` Handbook: "If an antenna other than a loop is used, the effective height must be determined experimentally. Maybe someone has worked this out since 1943. Best regards, Richard Harrison, KB5WZI |
Antenna reception theory
Asimov wrote:
. . . RH The definition looks OK to me. The reason the signal is not the same RH as the microvolts-per-meter even when the antenna is a 1-meter length RH of wire with just the right slant is because the induced voltage gets RH divided between the antenna and its load (the receiver). Not only that, but also this: the antenna rebroadcasts half of the intercepted energy. But voltage isn't energy. Or power. Roy Lewallen, W7EL |
Antenna reception theory
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