![]() |
Antenna reception theory
Hi,
I am looking for an explanation of how an antenna receives a signal due to the E-field of an electromagnetic wave. I have looked in some books, and can understand transmission, but the books I have looked in don't explain reception. I have found an explanation of how the H-field induces a signal in a loop antenna: a changing magnetic flux will induce a current. But what about the E-field and a dipole antenna? I guess that the E-field causes electrons to move in the antenna wire, because in a solid conductor, electrons will move until the E-field inside the solid is cancelled out? I have googled but having difficulty finding a good explanation. Any pointers? Thanks & regards, Paul. -- Remove _rem_ before replying by email. |
Antenna reception theory
"Paul Taylor" wrote in message ... Hi, I am looking for an explanation of how an antenna receives a signal due to the E-field of an electromagnetic wave. I have looked in some books, and can understand transmission, but the books I have looked in don't explain reception. I have found an explanation of how the H-field induces a signal in a loop antenna: a changing magnetic flux will induce a current. But what about the E-field and a dipole antenna? I guess that the E-field causes electrons to move in the antenna wire, because in a solid conductor, electrons will move until the E-field inside the solid is cancelled out? I have googled but having difficulty finding a good explanation. =================================== It is impossible for an E-field to exist without an H-field. Therefore, antennas of all sorts receive signals in the same way as a simple loop. Calculations can begin using either the E-field or the H-field but they both give the same answer. ---- Reg. |
Antenna reception theory
Paul Taylor wrote:
Hi, I am looking for an explanation of how an antenna receives a signal due to the E-field of an electromagnetic wave. I have looked in some books, and can understand transmission, but the books I have looked in don't explain reception. I have found an explanation of how the H-field induces a signal in a loop antenna: a changing magnetic flux will induce a current. But what about the E-field and a dipole antenna? I guess that the E-field causes electrons to move in the antenna wire, because in a solid conductor, electrons will move until the E-field inside the solid is cancelled out? I have googled but having difficulty finding a good explanation. Any pointers? Thanks & regards, Paul. Transmission and reception work essentially the same way -- if an antenna induces a certain field pattern in space, then that same field pattern will induce the same voltages going the other way. Most books spend about that much space telling you about the principal, then use the rest of the time telling you how antennas transmit, leaving it to you to figure out how they receive. -- Tim Wescott Wescott Design Services http://www.wescottdesign.com |
Antenna reception theory
Paul Taylor wrote:
I have looked in some books, and can understand transmission, but the books I have looked in don't explain reception. This is another example of quantum physics being easier to understand than Maxwell's equations. RF photons are absorbed by free electrons in the copper antenna causing RF currents to flow in the antenna wire. -- 73, Cecil http://www.qsl.net/w5dxp |
Antenna reception theory
"Cecil Moore" wrote This is another example of quantum physics being easier to understand than Maxwell's equations. RF photons are absorbed by free electrons in the copper antenna causing RF currents to flow in the antenna wire. ======================================== So how does a dielectric antenna work? ---- Reg. |
Antenna reception theory
Reg Edwards wrote:
So how does a dielectric antenna work? I'm not sure since I don't find it in any of my references including ARRL, Kraus, Balanis, and the IEEE Dictionary. Is it a waveguide where the inside air is replaced by a dielectric? -- 73, Cecil http://www.qsl.net/w5dxp |
Antenna reception theory
Cecil Moore wrote:
Reg Edwards wrote: So how does a dielectric antenna work? I'm not sure since I don't find it in any of my references including ARRL, Kraus, Balanis, and the IEEE Dictionary. Is it a waveguide where the inside air is replaced by a dielectric? In the third edition of the _Antenna Engineering Handbook_ there is an article on surface-wave antennas which includes dielectric antennas starting on page 12-8. 73, Tom Donaly, KA6RUH |
Antenna reception theory
Tom Donaly wrote:
In the third edition of the _Antenna Engineering Handbook_ there is an article on surface-wave antennas which includes dielectric antennas starting on page 12-8. I'll take a look the next time I'm over at Texas A&M. In a nutshell, where does the radiation come from? -- 73, Cecil http://www.qsl.net/w5dxp |
Antenna reception theory
"Tim Wescott" bravely wrote to "All" (24 Nov 05 11:49:57)
--- on the heady topic of " Antenna reception theory" TW From: Tim Wescott TW Xref: core-easynews rec.radio.amateur.antenna:220333 TW Paul Taylor wrote: Hi, I am looking for an explanation of how an antenna receives a signal due to the E-field of an electromagnetic wave. TW Transmission and reception work essentially the same way -- if an TW antenna induces a certain field pattern in space, then that same field TW pattern will induce the same voltages going the other way. TW Most books spend about that much space telling you about the TW principal, then use the rest of the time telling you how antennas TW transmit, leaving it to you to figure out how they receive. For antenna to receive it must also transmit part of the signal it intercepts. Now that confuses this discussion a little more, doesn't it?! A*s*i*m*o*v .... I like the word `indolence.' It makes my laziness seem classy. |
Antenna reception theory
Most authors explain how a wave is generated, then resort to reciprocity
to explain the reception process. But a clear and simple direct explanation appears in Bailey, _TV and Other Receiving Antennas_ (pp. 141-2), of what happens when an electromagnetic wave strikes a conductor: "The second, and equally important effect [the first being reflection of much of the incident energy] is that some energy /does/ enter the outer skin of the conductor. That part of the energy, which is not reflected, must enter the conductor. The conditions at the surface of the conductor, as we have already seen, give rise to a small resultant electric vector and a large resultant magnetic vector. The presence of these at the conductor is direct evidence that power is entering the conductor. The small electric vector acts on the internal electrons of the conductor and impresses a direction force, tending to drive the electrons along the skin of the conductor in the direction of the electric vector. But from experience we know that /no/ electrons can ever be caused to move without gradually establishing their own magnetic field, and this usually takes /time/. The motion of electrons (which is electric current by definition) never takes place without the magnetic field. How, then, is the electric vector from the electromagnetic wave going to put these electrons in motion? It can only do so because the electromagnetic wave /also supplies a magnetic vector/ as well as an electric vector. And the value of this magnetic vector is exactly proportioned to supply just the right amount of magnetic field energy which the electrons require for immediate motion. Thus the electrons do not have to establish their own magnetic field, since this field is supplied by the electromagnetic wave. Hence, electromagnetic wave energy entering the conductor establishes immediate motion of electrons /along/ the conductor, the direction of motion at any instant corresponding to the direction of the electric vector. If the electric vector changes direction, the electrons will follow suit." Other posters have correctly pointed out that an antenna doesn't and can't receive a signal solely due to the E field; a time-changing E field can't exist without an accompanying time-changing H field. Roy Lewallen, W7EL Paul Taylor wrote: Hi, I am looking for an explanation of how an antenna receives a signal due to the E-field of an electromagnetic wave. I have looked in some books, and can understand transmission, but the books I have looked in don't explain reception. I have found an explanation of how the H-field induces a signal in a loop antenna: a changing magnetic flux will induce a current. But what about the E-field and a dipole antenna? I guess that the E-field causes electrons to move in the antenna wire, because in a solid conductor, electrons will move until the E-field inside the solid is cancelled out? I have googled but having difficulty finding a good explanation. Any pointers? Thanks & regards, Paul. |
Antenna reception theory
Hi,
Thanks for the replies. I also found a sentence in Joseph Carr's book, Practical Antenna Handbook second edition. On page 297: 'Large loop antennas are sensitive primarily to the electric field of the electromagnetic radio wave, but small loop antenna are primarily sensitive to the magnetic field of an EM wave.' I understand that the receiver antenna works in a reciprocal way to transmit, but if there are other descriptions out there concentrating on how antennas work at the receiving end, I would be interested to know. Regards, Paul. -- Remove _rem_ before replying by email. |
Antenna reception theory
Paul:
Try this site: http://www.qsl.net/vk5br/EHAntenna20_40.htm Respectfully, art in Reno Paul Taylor wrote: Hi, I am looking for an explanation of how an antenna receives a signal due to the E-field of an electromagnetic wave. I have looked in some books, and can understand transmission, but the books I have looked in don't explain reception. I have found an explanation of how the H-field induces a signal in a loop antenna: a changing magnetic flux will induce a current. But what about the E-field and a dipole antenna? I guess that the E-field causes electrons to move in the antenna wire, because in a solid conductor, electrons will move until the E-field inside the solid is cancelled out? I have googled but having difficulty finding a good explanation. Any pointers? Thanks & regards, Paul. -- Remove _rem_ before replying by email. |
Antenna reception theory
Roy Lewallen wrote: Most authors explain how a wave is generated, then resort to reciprocity to explain the reception process. But a clear and simple direct explanation appears in Bailey, _TV and Other Receiving Antennas_ (pp. 141-2), of what happens when an electromagnetic wave strikes a conductor: "The second, and equally important effect [the first being reflection of much of the incident energy] is that some energy /does/ enter the outer skin of the conductor. That part of the energy, which is not reflected, must enter the conductor. The conditions at the surface of the conductor, as we have already seen, give rise to a small resultant electric vector and a large resultant magnetic vector. The presence of these at the conductor is direct evidence that power is entering the conductor. The small electric vector acts on the internal electrons of the conductor and impresses a direction force, tending to drive the electrons along the skin of the conductor in the direction of the electric vector. But from experience we know that /no/ electrons can ever be caused to move without gradually establishing their own magnetic field, and this usually takes /time/. The motion of electrons (which is electric current by definition) never takes place without the magnetic field. How, then, is the electric vector from the electromagnetic wave going to put these electrons in motion? It can only do so because the electromagnetic wave /also supplies a magnetic vector/ as well as an electric vector. And the value of this magnetic vector is exactly proportioned to supply just the right amount of magnetic field energy which the electrons require for immediate motion. Thus the electrons do not have to establish their own magnetic field, since this field is supplied by the electromagnetic wave. Hence, electromagnetic wave energy entering the conductor establishes immediate motion of electrons /along/ the conductor, the direction of motion at any instant corresponding to the direction of the electric vector. If the electric vector changes direction, the electrons will follow suit." Hi Roy - It's certainly true that a moving charge generates a magnetic field, so perhaps I'm reading it wrong. But it appears to me that Mr. Bailey is arguing here that an electron cannot be compelled to move simply by the application of an electric field. Do you think that is what he is saying? Do you agree? Other posters have correctly pointed out that an antenna doesn't and can't receive a signal solely due to the E field; Given the statement below, I would be interested to know how anyone could have tested the claim. ;-) a time-changing E field can't exist without an accompanying time-changing H field. Roy Lewallen, W7EL Jim Kelley, AC6XG Paul Taylor wrote: Hi, I am looking for an explanation of how an antenna receives a signal due to the E-field of an electromagnetic wave. I have looked in some books, and can understand transmission, but the books I have looked in don't explain reception. I have found an explanation of how the H-field induces a signal in a loop antenna: a changing magnetic flux will induce a current. But what about the E-field and a dipole antenna? I guess that the E-field causes electrons to move in the antenna wire, because in a solid conductor, electrons will move until the E-field inside the solid is cancelled out? I have googled but having difficulty finding a good explanation. Any pointers? Thanks & regards, Paul. |
Antenna reception theory
Reg Edwards wrote:
It is impossible for an E-field to exist without an H-field. Must have been before electrostatics was invented. :-) ac6xg |
Antenna reception theory
Roy Lewallen wrote: Jim Kelley wrote: Hi Roy - It's certainly true that a moving charge generates a magnetic field, so perhaps I'm reading it wrong. But it appears to me that Mr. Bailey is arguing here that an electron cannot be compelled to move simply by the application of an electric field. Do you think that is what he is saying? Do you agree? No, I don't believe he's saying that. He says, The small electric vector acts on the internal electrons of the conductor and impresses a direction force, tending to drive the electrons along the skin of the conductor in the direction of the electric vector. . . Yes. But then he goes on to say, How, then, is the electric vector from the electromagnetic wave going to put these electrons in motion? That's what I was referring to. Do you understand why he would pose this question if he believed he had already given the answer in the paragraph you quoted? He shoulda quit while he was ahead maybe? ;-) Thanks, Jim Kelley, AC6XG |
Antenna reception theory
Jim Kelley wrote:
Hi Roy - It's certainly true that a moving charge generates a magnetic field, so perhaps I'm reading it wrong. But it appears to me that Mr. Bailey is arguing here that an electron cannot be compelled to move simply by the application of an electric field. Do you think that is what he is saying? Do you agree? No, I don't believe he's saying that. He says, The small electric vector acts on the internal electrons of the conductor and impresses a direction force, tending to drive the electrons along the skin of the conductor in the direction of the electric vector. . . Roy Lewallen, W7EL |
Antenna reception theory
On Mon, 28 Nov 2005 12:15:30 -0800, Jim Kelley
wrote: How, then, is the electric vector from the electromagnetic wave going to put these electrons in motion? That's what I was referring to. Do you understand why he would pose this question As already stated: But from experience we know that /no/ electrons can ever be caused to move without gradually establishing their own magnetic field, and this usually takes /time/. The need for time (impedance) is accommodated by the wave: It can only do so because the electromagnetic wave /also supplies a magnetic vector/ as well as an electric vector. The phase of the re-radiated signal is a function of the path length. If the path signal required the electric potential to sustain movement (no other motive force available), that would add an additional phase retardation that is not observed. Observation of what does occur is other wise described by Bailey as from experience we know.... Roy's quote comes from a nascent discussion of the topic of Reception that has a complete, later chapter devoted to it. 73's Richard Clark, KB7QHC |
Antenna reception theory
Jim Kelley wrote:
Reg Edwards wrote: It is impossible for an E-field to exist without an H-field. Must have been before electrostatics was invented. :-) ac6xg How do you make an electrostatic radio wave? 73, Tom Donaly, KA6RUH |
Antenna reception theory
"Jim Kelley" bravely wrote to "All" (28 Nov 05 11:52:53)
--- on the heady topic of " Antenna reception theory" JK From: Jim Kelley JK Xref: core-easynews rec.radio.amateur.antenna:220506 JK Reg Edwards wrote: It is impossible for an E-field to exist without an H-field. JK Must have been before electrostatics was invented. :-) Yes, but you are changing the topic into static fields. We were discussing changing electric fields, not statics but dynamics! A*s*i*m*o*v .... "Hey, I'm just this guy, see?" --Zaphod Beeblebrox |
Antenna reception theory
Jim Kelley wrote:
Roy Lewallen wrote: Jim Kelley wrote: Hi Roy - It's certainly true that a moving charge generates a magnetic field, so perhaps I'm reading it wrong. But it appears to me that Mr. Bailey is arguing here that an electron cannot be compelled to move simply by the application of an electric field. Do you think that is what he is saying? Do you agree? No, I don't believe he's saying that. He says, The small electric vector acts on the internal electrons of the conductor and impresses a direction force, tending to drive the electrons along the skin of the conductor in the direction of the electric vector. . . Yes. But then he goes on to say, How, then, is the electric vector from the electromagnetic wave going to put these electrons in motion? That's what I was referring to. Do you understand why he would pose this question if he believed he had already given the answer in the paragraph you quoted? He shoulda quit while he was ahead maybe? ;-) Well, it's obvious that an electric field can move an electron. The Lorentz force law tells us how much force results from a given E field, and we can get the resulting acceleration from Newtonian physics. An everyday example is an oscilloscope deflection system which uses an electric field to deflect electrons. (Actually, modern digital scopes typically use raster displays with magnetic deflection -- but many of still have older analog types with electric field deflection.) But if the antenna conductor were perfect, no E field at all could exist at the wire surface regardless of the amplitude of the E field of the oncoming wave. The wave's E field therefore couldn't directly influence the electrons in the (perfect) conductor. Only the H field of the wave, then, can induce a current in the perfect conductor. The direct influence of the E field on an imperfect conductor would be highly dependent on the conductivity of the wire, and I'd guess it would be very small compared to the influence of the H field from a typical oncoming wave on an electron in a good conductor. Maybe that's what he was saying. Roy Lewallen, W7EL |
Antenna reception theory
Asimov wrote:
Yes, but you are changing the topic into static fields. We were discussing changing electric fields, not statics but dynamics! When is someone going to come up with a context-free language? -- 73, Cecil http://www.qsl.net/w5dxp |
Antenna reception theory
Roy, W7EL wrote:
"But, if the antenna conductor were perfect, no E field at all could exist at the wire surface regardless of the magnitude of the E field of the oncoming wave." If we have a non-varying E field, a perfect conductor in the field would have the same voltage everywhere due to the short-circuit connecting all points. But, an electromagnetic wave sweeping the wire has an alternating electric field. Its phase is uniform (the same) across the wavefront because all points are equidistant from the source. A wire parallel to the E vector would simultaneously experience the same E field force throughout its length. "No E field at all could exist at the wire surface regardless of the magnitude of the E field of the oncoming wave," Why must the wire be perfect? Best regards, Richard Harrison, KB5WZI |
Antenna reception theory
Tom Donaly wrote: Jim Kelley wrote: Reg Edwards wrote: It is impossible for an E-field to exist without an H-field. Must have been before electrostatics was invented. :-) ac6xg How do you make an electrostatic radio wave? 73, Tom Donaly, KA6RUH Certainly you're aware that radio waves don't have a monopoly on E fields, Tom. 73, jk |
Antenna reception theory
Roy Lewallen wrote: Well, it's obvious that an electric field can move an electron. The Lorentz force law tells us how much force results from a given E field, and we can get the resulting acceleration from Newtonian physics. An everyday example is an oscilloscope deflection system which uses an electric field to deflect electrons. (Actually, modern digital scopes typically use raster displays with magnetic deflection -- but many of still have older analog types with electric field deflection.) Yes, I thought that much was obvious as well. But if the antenna conductor were perfect, no E field at all could exist at the wire surface regardless of the amplitude of the E field of the oncoming wave. The wave's E field therefore couldn't directly influence the electrons in the (perfect) conductor. Only the H field of the wave, then, can induce a current in the perfect conductor. The direct influence of the E field on an imperfect conductor would be highly dependent on the conductivity of the wire, and I'd guess it would be very small compared to the influence of the H field from a typical oncoming wave on an electron in a good conductor. Maybe that's what he was saying. Roy Lewallen, W7EL It could be what he was saying. But conductors are are called conductors for a reason, and it's not necessarily because they conduct magnetic fields well. 73, ac6xg |
Antenna reception theory
Jim Kelley wrote:
Certainly you're aware that radio waves don't have a monopoly on E fields, Tom. But they should have a monopoly on threads in this newsgroup. :-) -- 73, Cecil http://www.qsl.net/w5dxp |
Antenna reception theory
Asimov wrote: "Jim Kelley" bravely wrote to "All" (28 Nov 05 11:52:53) --- on the heady topic of " Antenna reception theory" JK From: Jim Kelley JK Xref: core-easynews rec.radio.amateur.antenna:220506 JK Reg Edwards wrote: It is impossible for an E-field to exist without an H-field. JK Must have been before electrostatics was invented. :-) Yes, but you are changing the topic into static fields. We were discussing changing electric fields, not statics but dynamics! But do you agree that it's not impossible for an E field to exist without an H field? ac6xg |
Antenna reception theory
Jim Kelley wrote:
But do you agree that it's not impossible for an E field to exist without an H field? Depends upon the context. I suspect he was talking within the context of RF EM waves? Is it possible for an RF E-field to exist without an RF H-field? -- 73, Cecil http://www.qsl.net/w5dxp |
Antenna reception theory
Tom Donaly wrote:
Jim Kelley wrote: Reg Edwards wrote: It is impossible for an E-field to exist without an H-field. Must have been before electrostatics was invented. :-) ac6xg How do you make an electrostatic radio wave? Wave to it first? - 73 de Mike KB3EIA - |
Antenna reception theory
Richard Harrison wrote:
Roy, W7EL wrote: "But, if the antenna conductor were perfect, no E field at all could exist at the wire surface regardless of the magnitude of the E field of the oncoming wave." If we have a non-varying E field, a perfect conductor in the field would have the same voltage everywhere due to the short-circuit connecting all points. But, an electromagnetic wave sweeping the wire has an alternating electric field. Its phase is uniform (the same) across the wavefront because all points are equidistant from the source. A wire parallel to the E vector would simultaneously experience the same E field force throughout its length. "No E field at all could exist at the wire surface regardless of the magnitude of the E field of the oncoming wave," Why must the wire be perfect? A time-varying E field can exist in a non-perfect conductor; it cannot exist in a perfect conductor. You can find the explanation for why this is in any electromagnetics text. Roy Lewallen, W7EL |
Antenna reception theory
Cecil Moore wrote: Jim Kelley wrote: But do you agree that it's not impossible for an E field to exist without an H field? Depends upon the context. I suspect he was talking within the context of RF EM waves? That's certainly a context where an E field is always accompanied by an H field. But the statement as it was written is nevertheless untrue. That was my only point. Is it possible for an RF E-field to exist without an RF H-field? Seems to beg an obvious answer. But the question brings up a point that people seem to be missing here. An E field is an E field - there are not different 'kinds' of E fields. The field itself is the same, whether it varies in time or not. A non-zero dE/dt allows for some of the more interesting properties to have non-zero solutions, but the fields themselves are not unique. I hope that concept isn't too controversial for this group. If it is, I will strive to keep such ideas to myself in the future. ac6xg |
Antenna reception theory
Jim Kelley wrote:
The field itself is the same, whether it varies in time or not. I wonder if that's true when taken out of context? :-) I'm no physicist but wouldn't a static electric field be made up of virtual photons while a dynamic electric field would be made up of non-virtual photons? -- 73, Cecil http://www.qsl.net/w5dxp |
Antenna reception theory
Cecil Moore wrote: Jim Kelley wrote: The field itself is the same, whether it varies in time or not. I wonder if that's true when taken out of context? :-) I'm no physicist but wouldn't a static electric field be made up of virtual photons while a dynamic electric field would be made up of non-virtual photons? Non-virtual photons, as opposed virtual non-photons I presume. I think physicists know they're going to have to wait until they get to the pearly gates before they can really learn what "electric fields are made out of". ;-) 73, jk |
Antenna reception theory
Cecil Moore wrote:
Jim Kelley wrote: Certainly you're aware that radio waves don't have a monopoly on E fields, Tom. But they should have a monopoly on threads in this newsgroup. :-) Methinks you ridicule the optically disinclined, Cecil. ac6xg |
Antenna reception theory
"Jim Kelley" bravely wrote to "All" (29 Nov 05 10:26:08)
--- on the heady topic of " Antenna reception theory" JK From: Jim Kelley JK Xref: core-easynews rec.radio.amateur.antenna:220548 JK Asimov wrote: "Jim Kelley" bravely wrote to "All" (28 Nov 05 11:52:53) --- on the heady topic of " Antenna reception theory" JK From: Jim Kelley JK Xref: core-easynews rec.radio.amateur.antenna:220506 JK Reg Edwards wrote: It is impossible for an E-field to exist without an H-field. JK Must have been before electrostatics was invented. :-) Yes, but you are changing the topic into static fields. We were discussing changing electric fields, not statics but dynamics! JK But do you agree that it's not impossible for an E field to exist JK without an H field? A static E field can exist alone but to detect it requires something like a field-mill which basically converts it into a changing EM field that can be readily detected. A simple field-mill is basically a rapidly spinning antenna. Relativity at work. A*s*i*m*o*v .... The truth is WAY out there! |
Antenna reception theory
Reg, G4FGQ wrote:
"It is impossible for an E-field to exist without an H-field." Agreed. By definition an electromagnetic wave includes an electric component and a magnetic component. That does not mean the components are inseparable. The purpose of a Faraday screen is to eliminate capacitive coupling while permitting magnetic coupling. I`ve worked in several medium wave broadcast plants. In these, each tower was coupled through a 1:1 air-core transformer to its transmission line. The transformer consisted of two identical coils, one on either side of a Faraday screen. The coils shared a cmmon axis. Electrically, the transformer was transparent at the transmitting frequency. It coupled the transmitting frequency as if the transformer did not exist to impede. Its purpose was to eliminate capacitive coupling, The Faraday screen provided a place where electric field lines are shunted to ground. The problem with capacitive coupling between a transmitter and a tower is that the higher the frequency, the less the reactance or opposition. The coupling is better through a capacitance to the harmonics of a frequency than it is for the fundamental. The Faraday screen removes this unwanted bias for imroved harmonic propagation. A side effect of the Faraday screen is that it removes lightning strokes before they reach the transmission line from the tower. The Faraday screen looks like a metal rake. Its back where the teeth or tines join is firmly grounded. The teeth are open-circuited. Current cannot circulate between and through the teeth, so no counter electromotive force can be generated to oppose magnetic coupling between primary and secondary coils. The rake is transparent for magnetic coupling but it is a stopper for electric coupling. By complete shielding, that is metalllically enclosihng one or both coils of an impedance coupling pair, magneric coupling between them can be practically eliminated. A coupling capacitor between the coils allows only the electric field to be effective. There`s no magnetic field involved. I`m no advocate of the E-H antenna, but the electric and magnetic components of a wave are easily separated. Best regards, Richard Harrison, KB5WZI |
Antenna reception theory
I'm afraid your Faraday screen might not work quite like you think it does.
In the vicinity of the screen, the E field is indeed reduced. However, you haven't stripped off the E field from the EM wave, or separated it. The E field is largely reflected from the screen, but out of phase with the original wave. So the E/H ratio is smaller on *both* sides of the screen. Close to the screen, much of the energy formerly in the E field has been transferred to the H field. But as you go beyond the screen in either direction, you'll find the E field increasing and the H field decreasing as the energy redistributes itself. Within a short distance (typically considerably less than a wavelength, but depending on the size of the screen), the ratio of E/H will again be close to 377 ohms, assuming air is the surrounding medium. The Faraday screen works in the broadcast application only because the "shielded" component is close to the screen, where the E/H ratio is low. In other words, you can modify the E/H ratio in a small region of space by moving the energy from one to the other. But you can't separate the two components or eliminate one or the other. This is of course referring to time-varying, not static, fields. Reg's statement is technically false, since he didn't say whether the fields are time-varying -- static E and H fields can independently exist. But time-varying E and H fields, which I'm sure is what he meant, can't. Roy Lewallen, W7EL Richard Harrison wrote: Reg, G4FGQ wrote: "It is impossible for an E-field to exist without an H-field." Agreed. By definition an electromagnetic wave includes an electric component and a magnetic component. That does not mean the components are inseparable. The purpose of a Faraday screen is to eliminate capacitive coupling while permitting magnetic coupling. I`ve worked in several medium wave broadcast plants. In these, each tower was coupled through a 1:1 air-core transformer to its transmission line. The transformer consisted of two identical coils, one on either side of a Faraday screen. The coils shared a cmmon axis. Electrically, the transformer was transparent at the transmitting frequency. It coupled the transmitting frequency as if the transformer did not exist to impede. Its purpose was to eliminate capacitive coupling, The Faraday screen provided a place where electric field lines are shunted to ground. The problem with capacitive coupling between a transmitter and a tower is that the higher the frequency, the less the reactance or opposition. The coupling is better through a capacitance to the harmonics of a frequency than it is for the fundamental. The Faraday screen removes this unwanted bias for imroved harmonic propagation. A side effect of the Faraday screen is that it removes lightning strokes before they reach the transmission line from the tower. The Faraday screen looks like a metal rake. Its back where the teeth or tines join is firmly grounded. The teeth are open-circuited. Current cannot circulate between and through the teeth, so no counter electromotive force can be generated to oppose magnetic coupling between primary and secondary coils. The rake is transparent for magnetic coupling but it is a stopper for electric coupling. By complete shielding, that is metalllically enclosihng one or both coils of an impedance coupling pair, magneric coupling between them can be practically eliminated. A coupling capacitor between the coils allows only the electric field to be effective. There`s no magnetic field involved. I`m no advocate of the E-H antenna, but the electric and magnetic components of a wave are easily separated. Best regards, Richard Harrison, KB5WZI |
Antenna reception theory
"Asimov" wrote:
A static E field can exist alone but to detect it requires something like a field-mill which basically converts it into a changing EM field that can be readily detected. A simple field-mill is basically a rapidly spinning antenna. Relativity at work. It's similar in some ways to a method for detecting magnetic fields used prior to the advent of Hall effect devices. Not sure how it relates to relativity. Perhaps it's true that an electric field is simpler create than to detect by direct means. But it isn't really any more difficult than, for example, measuring power by direct means. I think Ben Franklin measured the E field in a Leyden Jar by calibrating the leaf displacement caused by the Coulomb force resulting from the electric field between the two similarly charged surfaces. jk |
Antenna reception theory
"Jim Kelley" bravely wrote to "All" (29 Nov 05 14:46:41)
--- on the heady topic of " Antenna reception theory" JK From: Jim Kelley JK Xref: core-easynews rec.radio.amateur.antenna:220573 JK "Asimov" wrote: A static E field can exist alone but to detect it requires something like a field-mill JK It's similar in some ways to a method for detecting magnetic fields JK used prior to the advent of Hall effect devices. Not sure how it JK relates to relativity. I think a saturable core can be used to measure a static magnetic field. Early computer magnetic core memories worked like this. Relativity transforms static fields into dynamic fields by adding a velocity component to the measurement. JK Perhaps it's true that an electric field is simpler create than to JK detect by direct means. But it isn't really any more difficult than, JK for example, measuring power by direct means. I think Ben Franklin JK measured the E field in a Leyden Jar by calibrating the leaf JK displacement caused by the Coulomb force resulting from the electric JK field between the two similarly charged surfaces. That Leyden Jar experiment was measuring charges not the E field itself. An E field doesn't require the exchange of charges. I wonder if it is possible to directly measure an E field by the effect of the virtual quanta in its close vicinity? A*s*i*m*o*v .... Quoting one is plagiarism. Quoting many is research. |
Antenna reception theory
I wonder if it is possible to directly measure an E field by the
effect of the virtual quanta in its close vicinity? If the effect of virtual quanta could be measured, would they still be virtual? -- 73, Cecil http://www.qsl.net/w5dxp |
Antenna reception theory
Asimov wrote:
I think a saturable core can be used to measure a static magnetic field. Early computer magnetic core memories worked like this. I was referring to the similarity to a rotating coil gaussmeter. I think what you're describing now is something more akin to the fluxgate magnetometer. Relativity transforms static fields into dynamic fields by adding a velocity component to the measurement. I see. Is Omni magazine still in print by any chance? That Leyden Jar experiment was measuring charges not the E field itself. Leyden jars store charge. As I said before, they produce an indication by relying on the electric field between charged surfaces and the resulting Coulomb force. The more charge stored in the jar, the greater the electric field. Charge, E field, and Coulomb force all being in proportion, the Leyden jar produces a response in proportion to all three. jk |
All times are GMT +1. The time now is 11:44 PM. |
Powered by vBulletin® Copyright ©2000 - 2025, Jelsoft Enterprises Ltd.
RadioBanter.com