Roy Lewallen wrote:
. . .
Sorry, that's not just a little wrong, it's wrong by orders of
magnitude. For example, a 1 meter long 10 mm diameter dipole, terminated
in the complex conjugate of its self impedance (load Z = 0.8855 + j6030
ohms), in a 1 V/m field, has about 1667 volts across the load. Hardly a
half volt!

For the casual reader, I should emphasize that this analysis, like all
the others on this thread, assumes zero loss. The conditions I described
could never be achieved in real life because of unavoidable loss. But
it's important to first understand how a lossless system behaves before
we add the complicating factor of loss.

Roy Lewallen, W7EL