Home |
Search |
Today's Posts |
#11
![]() |
|||
|
|||
![]()
dansawyeror wrote:
Do the measuring ports of a bi-directional coupler accurately represent or preserve the relative phases of the signal? Let's look at a typical SWR meter sampling circuit. The current is sampled by a one turn primary on a ferrite toroid. The voltage is sampled by a tap on the line close to the point at which the toroid is mounted. At HF frequencies, a wavelength is so long compared to that configuration that physical sample point errors are usually considered to be negligible. That obviously changes at UHF+. No coupler 100% preserves the relative phases. The question is: What is the accuracy? For any configuration, a worst-case accuracy can be specified. At 4 MHz, it's not a problem. At 4 GHz, it's a big problem. At visible light frequencies, most don't even try. -- 73, Cecil http://www.qsl.net/w5dxp |
#12
![]() |
|||
|
|||
![]()
Frank,
The bi-directional coupler is a machined block about 1 x 3 x 5. The inside is a straight through line, the pickups are simply terminated one loop lines. It is a UHF coupler that works reasonably down to 2 meters. When I configure this to look at the forward and reflected 'open' circuit case they are not in phase. Reflected lags forward by about 40 degrees. (I checked the connection delay and this is not a cable issue.) This is frequency independent. Shorting the output reverses this relationship. The outputs are terminated in 50 Ohms so I conclude it is a 50 Ohm device. When I terminate the device in 50 Ohms the forward and reflected outputs are out of phase by about 140 degrees. What is the significance a non frequency dependent phase shift between forward and reflected? This shift is frequency independent. Thanks - Dan kb0qil Frank wrote: Your answer to the question about bidirectional couplers was they do not compensate for phase shift. Let me ask it again: Do the measuring ports of a bi-directional coupler accurately represent or preserve the relative phases of the signal? To put it another way is the phase shift of the driving and reflected signals changed by the same about? Thanks - Dan kb0qil The phases seen at each coupled port should be identical to the phase of the forward and reflected signals. This is easily verifiable, and frequency independant, as follows: No load -- forward and reverse amplitudes equal, and in phase; Short circuit at output -- forward and reverse amplitudes equal, and 180 degrees phase difference; 50 ohm load -- reverse than forward by = specified coupler directivity, and phase difference can 0 theta +/ 180. This is only true if the frequencies are low enough such that the standards do not require quantification by the use of "Standard definitions" -- see www.vnahelp.com. Regards, Frank |
#13
![]() |
|||
|
|||
![]()
Paul Burridge wrote:
On Sat, 03 Dec 2005 21:13:36 -0800, Roy Lewallen wrote: As I mentioned in my earlier posting, most people overestimate their ability to make accurate RF measurements. It's not at all trivial. Be sure to check your results frequently by measuring known load impedances close to the values being measured. How do you find the values of those "known" load impedances? Well, welcome to the world of metrology! Roy, I've seen your postings hereabouts over the years and you've always struck me as one of the most knowledgeable posters on this, *the* most technically-challenging of all hobbies. Thanks for your vote of confidence. But on the topic of network analyzer measurements, I gladly defer to Wes Stewart, Tom Bruhns, and other posters who have spent much more time making real-life measurements with them than I have. I've used them from time to time, and for some really challenging measurements, but not by any means as much as those folks have. I've recently bought a VNA and am going about the laborious process of setting it up with precisely-cut interconnects to the T/R bridge. Next thing I need to know is... Say I have a mica capacitor (for example) that I want to check for its SRF. How should I mount this component so as to minimize stray L&C from anything other than the component itself? IOW, what 'platform' (for want of a better word) do I need to construct to permit accurate measurements of this cap's RF characteristics in isolation? In general, you minimize stray inductance by keeping leads short, and capacitance by keeping conductors apart. The ideal setup is a coaxial environment right up to the DUT, but even that is subject to coupling around the DUT, both from one terminal to the other and from each terminal to ground. If possible, the best plan is to calibrate out the strays. That's a science and art in itself, and I'll have to yield to people with more experience than mine for practical information about how best to do this. The effect of the strays depends heavily on what you're measuring. For example, if you're measuring a low impedance, you can get by with more shunt C than if you're measuring a high impedance. If you're measuring a high impedance, you can tolerate more series inductance than when measuring a low impedance. So when you inevitably find that you have to make tradeoffs in designing a fixture, the trades you make will depend on what you expect to measure. Roy Lewallen, W7EL |
#14
![]() |
|||
|
|||
![]()
Dan,
your original posting says the shift you are getting is frequency dependent. Your last posting says it is not. Which one I read wrong? Thks Ivan "dansawyeror" wrote in message ... Frank, The bi-directional coupler is a machined block about 1 x 3 x 5. The inside is a straight through line, the pickups are simply terminated one loop lines. It is a UHF coupler that works reasonably down to 2 meters. When I configure this to look at the forward and reflected 'open' circuit case they are not in phase. Reflected lags forward by about 40 degrees. (I checked the connection delay and this is not a cable issue.) This is frequency independent. Shorting the output reverses this relationship. The outputs are terminated in 50 Ohms so I conclude it is a 50 Ohm device. When I terminate the device in 50 Ohms the forward and reflected outputs are out of phase by about 140 degrees. What is the significance a non frequency dependent phase shift between forward and reflected? This shift is frequency independent. Thanks - Dan kb0qil Frank wrote: Your answer to the question about bidirectional couplers was they do not compensate for phase shift. Let me ask it again: Do the measuring ports of a bi-directional coupler accurately represent or preserve the relative phases of the signal? To put it another way is the phase shift of the driving and reflected signals changed by the same about? Thanks - Dan kb0qil The phases seen at each coupled port should be identical to the phase of the forward and reflected signals. This is easily verifiable, and frequency independant, as follows: No load -- forward and reverse amplitudes equal, and in phase; Short circuit at output -- forward and reverse amplitudes equal, and 180 degrees phase difference; 50 ohm load -- reverse than forward by = specified coupler directivity, and phase difference can 0 theta +/ 180. This is only true if the frequencies are low enough such that the standards do not require quantification by the use of "Standard definitions" -- see www.vnahelp.com. Regards, Frank |
#15
![]() |
|||
|
|||
![]()
The posts refer to two different couplers, the first posting is in reference to
a Mini-circuits ZFDC-1-3. The last posting is in reference to a bi-directional coupler as described. At this point the objective is to 'learn' as much as possible about the operation of couplers. Ivan Makarov wrote: Dan, your original posting says the shift you are getting is frequency dependent. Your last posting says it is not. Which one I read wrong? Thks Ivan "dansawyeror" wrote in message ... Frank, The bi-directional coupler is a machined block about 1 x 3 x 5. The inside is a straight through line, the pickups are simply terminated one loop lines. It is a UHF coupler that works reasonably down to 2 meters. When I configure this to look at the forward and reflected 'open' circuit case they are not in phase. Reflected lags forward by about 40 degrees. (I checked the connection delay and this is not a cable issue.) This is frequency independent. Shorting the output reverses this relationship. The outputs are terminated in 50 Ohms so I conclude it is a 50 Ohm device. When I terminate the device in 50 Ohms the forward and reflected outputs are out of phase by about 140 degrees. What is the significance a non frequency dependent phase shift between forward and reflected? This shift is frequency independent. Thanks - Dan kb0qil Frank wrote: Your answer to the question about bidirectional couplers was they do not compensate for phase shift. Let me ask it again: Do the measuring ports of a bi-directional coupler accurately represent or preserve the relative phases of the signal? To put it another way is the phase shift of the driving and reflected signals changed by the same about? Thanks - Dan kb0qil The phases seen at each coupled port should be identical to the phase of the forward and reflected signals. This is easily verifiable, and frequency independant, as follows: No load -- forward and reverse amplitudes equal, and in phase; Short circuit at output -- forward and reverse amplitudes equal, and 180 degrees phase difference; 50 ohm load -- reverse than forward by = specified coupler directivity, and phase difference can 0 theta +/ 180. This is only true if the frequencies are low enough such that the standards do not require quantification by the use of "Standard definitions" -- see www.vnahelp.com. Regards, Frank |
#16
![]() |
|||
|
|||
![]()
On Sun, 04 Dec 2005 07:57:55 -0800, dansawyeror
wrote: Wes, Your answer to the question about bidirectional couplers was they do not compensate for phase shift. Let me ask it again: Do the measuring ports of a bi-directional coupler accurately represent or preserve the relative phases of the signal? To put it another way is the phase shift of the driving and reflected signals changed by the same about? Thanks - Dan kb0qil I'm not sure I understand the question(s) but in the case of a vector reflectometer using a dual directional coupler maybe this will help. Here is a dual directional coupler. Reverse Forward | | | | |----------R R ---------| X X Input --A-----------------------B--C Load Let's say that at frequency, F, the coupling factor (X) is -10 dB with no phase shift between point B and the forward port and between point A and the reverse port to keep it simple. So a wave propagating in the forward direction (Input -- Load) induces a signal at the forward port that is 10 dB below the input at 0 degrees phase with respect to point B. A wave propagating in the opposite direction has the same relationship at the reverse port; 10 dB down and 0 degrees phase with respect to point A. A to Reverse and B to Forward -might- track reasonably well in both magnitude and phase, but in this case, it's immaterial. Because B-A and C-B 0 there will be a frequency dependent phase difference between A, B and C. When we calibrate using a short on the load port here's what happens. The signal at the forward port becomes the reference, i.e., unity amplitude and 0 degrees phase. The short creates a 100% reflection and -180 degree phase shift. This signal propagates back down the main line to the source, which is assumed to be a perfect match, so there is no re-reflection. A -10 dB sample (by definition: unity) is coupled to the reverse port, with a phase shift, theta(F), determined by the electrical length of the line C - B - A. Unless we are lucky enough to be Lotto winners, the signal at the reflected port -will not- be 1 @ ang-180 deg. So our calibration routine must do whatever math is necessary to make the ratio B/A = 1 @ ang-180. This fudge factor is then applied to all subsequent measurements to "correct" the data. Now to address (I think) your question. If we change frequencies, theta(F) changes and the fudge factor no longer corrects for it. While the coupling factors might track, it is of little consolation because the calibration is good only at the frequency where it was performed. Automatic network analyzers perform calibration at each test frequency, or at least enough points to interpolate between. |
#17
![]() |
|||
|
|||
![]()
Wes,
Thanks. If I read the gist of your reply the physical dimensions are the root cause of the phase difference between the forward and reflected signals. Is this true? Thanks again - this is very helpful. Dan - kb0qil Wes Stewart wrote: On Sun, 04 Dec 2005 07:57:55 -0800, dansawyeror wrote: Wes, Your answer to the question about bidirectional couplers was they do not compensate for phase shift. Let me ask it again: Do the measuring ports of a bi-directional coupler accurately represent or preserve the relative phases of the signal? To put it another way is the phase shift of the driving and reflected signals changed by the same about? Thanks - Dan kb0qil I'm not sure I understand the question(s) but in the case of a vector reflectometer using a dual directional coupler maybe this will help. Here is a dual directional coupler. Reverse Forward | | | | |----------R R ---------| X X Input --A-----------------------B--C Load Let's say that at frequency, F, the coupling factor (X) is -10 dB with no phase shift between point B and the forward port and between point A and the reverse port to keep it simple. So a wave propagating in the forward direction (Input -- Load) induces a signal at the forward port that is 10 dB below the input at 0 degrees phase with respect to point B. A wave propagating in the opposite direction has the same relationship at the reverse port; 10 dB down and 0 degrees phase with respect to point A. A to Reverse and B to Forward -might- track reasonably well in both magnitude and phase, but in this case, it's immaterial. Because B-A and C-B 0 there will be a frequency dependent phase difference between A, B and C. When we calibrate using a short on the load port here's what happens. The signal at the forward port becomes the reference, i.e., unity amplitude and 0 degrees phase. The short creates a 100% reflection and -180 degree phase shift. This signal propagates back down the main line to the source, which is assumed to be a perfect match, so there is no re-reflection. A -10 dB sample (by definition: unity) is coupled to the reverse port, with a phase shift, theta(F), determined by the electrical length of the line C - B - A. Unless we are lucky enough to be Lotto winners, the signal at the reflected port -will not- be 1 @ ang-180 deg. So our calibration routine must do whatever math is necessary to make the ratio B/A = 1 @ ang-180. This fudge factor is then applied to all subsequent measurements to "correct" the data. Now to address (I think) your question. If we change frequencies, theta(F) changes and the fudge factor no longer corrects for it. While the coupling factors might track, it is of little consolation because the calibration is good only at the frequency where it was performed. Automatic network analyzers perform calibration at each test frequency, or at least enough points to interpolate between. |
Reply |
|
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Workman BS-1 Dipole Antenna = Easy Mod to make it a Mini-Windom Antenna ! | Shortwave | |||
On Topic | Shortwave | |||
The "Almost" Delta Loop Antenna for Limited Space Shortwave Listening (SWL) made from TV 'type' Parts | Shortwave | |||
Imax ground plane question | CB | |||
Outdoor Antenna and lack of intermod | Scanner |