On Thu, 29 Dec 2005 06:20:38 GMT, Owen Duffy wrote:


You know that Gamma=(Zl-Zo)/(Zl+Zo), rearrange the terms to find Zl
knowing Zo and Gamma, measure Gamma with your instrument, calculate
Zl... and the rest is easy.

For avoidance of doubt, the Zl above is the z at the instrument
interface. 'The rest is easy' is the process of working out Z at the
antenna knowning z at the source end of a known transmission line.

Back to my worked example, if you instrument indicated Gamma was 0.195
-117 in 50ohms, you would calculate Z to be 40-j15... and go from
there.

Meaning the rest of my example which led to a antenna z of
41.94+j18.03


What more do you need?

Owen

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