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#1
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Hello:
I am contemplating a half-wave wire antenna for the 160m band and would end-feed it against my roof as a counterpoise. If the wire length is carefully trimmed I should get a high feedpoint resistance with negligible reactance. Then comes the question of how to match this to a 50 Ohm system. The standard approach is using a parallel LC circuit and either make a tap or a link for the 50 Ohm connection. In this case, how should I select the L and C, as there are multiple choices leading to the same resonance frequency but with different Q values. Any suggestions? Or, would another matching network be more desirable, for example in terms of loss? An L-network might do the job, but it is not immediately clear to me if it would have any advantages or disadvantages over the parallel circuit. Any comments? I will be running substantial power into the antenna, so it is important that the solution does not result in excessive losses (heat) or voltages (although this will probably be inevitable at the feedpoint). 73 - Kris, TF3KX |
#2
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![]() The standard approach is using a parallel LC circuit and either make a tap or a link for the 50 Ohm connection. In this case, how should I select the L and C, as there are multiple choices leading to the same resonance frequency but with different Q values. Any suggestions? Or, would another matching network be more desirable, for example in terms of loss? An L-network might do the job, but it is not immediately clear to me if it would have any advantages or disadvantages over the parallel circuit. Any comments? I will be running substantial power into the antenna, so it is important that the solution does not result in excessive losses (heat) or voltages (although this will probably be inevitable at the feedpoint). 73 - Kris, TF3KX GM Kris I use an end fed, inverted L half wave on 160 meters on 160, 80 and 40 meters where it has a feed impedance of about 2600, 1600 and 700 Ohms respectively. This allows a remote tuned L network to be used for a match to 50 Ohms on all 3 bands without need for switching the capacitor from end to end of the inductor. My inductor is a piece of 2-1/2 inch miniductor, tap switched with a motor driven switch, and a motor driven vac variable. It allows a below 1.3:1 match across the entire band on all 3 bands and has been a very effective HF antenna for some 15 years. The bottom of the antenna ties to a control box thru a fairly small ceramic feedthru, (maybe 2 inches long) and Voltage has never been a problem even with 1500 Watts out. Fed against a 90 foot well casing that just happens to be in the right place, and a counterpoise under the flat top. When you don't KNOW that your ground is zero Ohms, feed as little current into it as possible! Regards W4ZCB |
#4
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In older handbooks, they often say that the parallel LC circuit used to
feed the end fed wire should replicate the output tank circuit of the transmitter. I have an end fed inverted "L" for 40 meters that works really well. It's 32 feet vertical and 98 feet horizontal, with the far end 8 ft. off the ground. I use a parallel tuned circuit at the base in a weatherproof box and it's fed with a 100 feet or so of RG 8 buried in PVC. The coax center conductor is tapped up a turn or two from the bottom of the coil. I consider this a single band antenna, and I use it only for 40 meters. John |
#5
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MATCHING END-FED 1/2-WAVE ANTENNAS TO THE TRANSMITTER.
Instead of depending on hearsay and old-wives tales, there is a logical way of selecting tuned-circuit L and C values. To begin, in the case of impedance matching it is always required to maximise power efficiency. It is the power lost in the tuned circuit which matters. To minimise power lost in the tuned circuit it is necessary to minimise the current circulating in it. (Circulating current is the antenna current times working Q but there's no need to know what Q actually is.) For a given radiated power the voltage across the tuned circuit and antenna when at resonance is fixed. So to minimise circulating current the reactances of L and C should be as high as practicably possible. That's obvious! So for a high reactance of C (which is approximately the reactance of L), C should be mimised. The limit on the smallness of C is the minimum setting value of the tuning capacitor, plus coil self-capacitance, plus stray capacitance associated with wiring and connections to the end of the antenna, plus an allowance for the antenna not being exactly at resonance, plus a small 'safety' margin to allow the tuning capacitor to be adjusted to either above or below resonance. For half-wave antennas at frequencies below 11 MHz a tuning capacitor setting of 20 or 25 pF is suitable. This choice automatically sets the value of the inductance (which is usually higher than the inductance value of a roller inductor and can be home-brewed quite easily.) The maximum setting of the tuning capacitor allows the circuit with the antenna to be tuned to the lower frequency bands. But efficiency will be reduced on lower frequency bands due to smaller reactances of L and C and the greater circulating current. Note that the reactances of L and C are always approximately equal to each other. Theoretically, if the antenna length is slightly shorter than 1/2-wavelength, then it is impossible to obtain an impedance match with this particular circuit. You can't have a tuning capacitor less than zero pF. It is prudent to select the overall antenna length to be a few feet longer than 1/2-wavelength at the desired operating frequency. On the other hand, it is just as well to remember, a non-resonant end-fed antenna wire is no less efficient than an exactly resonant wire provided it can be matched to whatever load resistance is required by the transmitter. (And the load resistance presented to the tansmitter as indicated by a TLI has nothing to do with the so-called, and imaginary, SWR). As Walter Maxwell has peviously pointed out, SWR = Short Wave Radio. But, despite its diagramatic simplicity, a parallel tuned circuit is a not-so-simple, quite complicated arrangement when used as an impedance matching transformer between an end-fed antenna and the transmitter. No maths needed - just arithmetic. Slight change of topic - I am presently imbibing White, Argentinian, Chardonnay Torrentes. I do hope my use of plain English language does not lead to misunderstandings. May I add that I much prefer a decent, intoxicated, political opposition-party leader to a sober, war-mongering Tony Blair. At least a few of you USA citizens must be acquainted with the relatively trivial events taking place in the 'mother' country. In sympathy with what's happening in the US. When will you impeach your so-called president and rid yourselves of your secret Nazi/OGPU CIA police. I'm sure the Constitution does not allow such people to exist. We would be happy to confine both Blair and Bush, here, in the historic Tower of London, chained to the cold stone walls, for an indefinite period, on bread and water, without access to legal representation, as so many other kidnapped prisoners (disappeared people), for years, are being presently detained without sound reason or charge. Have you no conscience? Or have you no idea what a map of the World looks like? To obtain an elementary understanding of a simple tuned circuit as an impedance-matching circuit, download program TUNEHALF from website below. There are other programs available related to the same subject. ---- .................................................. .......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. .......... ========================================= |
#6
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![]() To obtain an elementary understanding of a simple tuned circuit as an impedance-matching circuit, download program TUNEHALF from website below. There are other programs available related to the same subject. Intoxicated BS Diatribe snipped Or, use an "L" network. Same number of components, and it will even match impedances that call for negative component values in a parallel tuned circuit. W4ZCB |
#7
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![]() Or, use an "L" network. Same number of components, and it will even match impedances that call for negative component values in a parallel tuned circuit. W4ZCB ====================================== Actually, with an exact 1/2-wave antenna, an L-network suffers from the same disability as does the simple L and C tuned circuit. This is why automatic antenna tuner manufacturers, which use L-networks, state in their operating handbooks that exactly 1/2-wave antennas should be avoided. But it is not an important matter. Very few antennas are EXACTLY 1/2-wavelength in length. And it is a simple matter to shift the resonant frequency up or down a few KHz. ---- Reg, G4FGQ. |
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