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John Popelish wrote:
Since, in both standing waves and traveling waves, current at a point, changes magnitude and sign in exactly the same way (at a point, they are indistinguishable), they can both be described with phasor notation. Limiting oneself to a point measurement is handicapping onself. When the equation for standing wave current is compared to the equation for traveling wave current, the real differences are obvious. For standing waves, the phasor of a neighboring point has the same phase shift, ... Exactly! Therefore, it cannot be used to measure the phase shift through a coil or even through a wire. But at any point along both standing waves and traveling waves, there certainly is a phasor that represents the current at that point. For the standing wave current it is a phasor that doesn't rotate all up and down the wire. You have to admit, that's a weird phasor. It's more akin to DC than anything else. You need to get past this misconception that standing waves are not current and are not describable by phasors. Standing waves current is the superposition of two essentially equal currents traveling in opposite directions. If it was equal DC currents traveling in opposite directions, what would the net current be? -- 73, Cecil http://www.qsl.net/w5dxp |
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