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Cecil, W5DXP wrote:
"What caused the voltage to go to zero?" Equal and opposite voltages. Reaction to connecting wires together generates an opposite voltage which adds to zero with the incident voltage. Current doubles at the short. 1/4-wave back from the short, a virtual open circuit appears. Cecil claims this open circuit does not impede current. 1/4-wave short-circuit stubs are used as metallic insulators. They have the characteristics of resonant circuits constructed of a parallel-connected capacitor and coil, a very high impedance at resonance. From King, Mimno, and Wing, "Transmission Lines, Antennas, and Wave Guides" page 29: "A short-circuited line, one-quarter wavelength long at the desired output frequency may be connected across the output terminals of a transmitter or across the antenna feeder at any point without placing much load on the transmitter at this fundamental or desired output frequency, since at this frequency such a section has an impedance ideally infinite, actually about 400,000 ohms." Since I = E/Z, how much current do you think will flow into 400,000 ohms? King, Mimno, and Wing`s impedance might scale down to only 33,333 ohms on a 50-ohm line, still high, as they may have been considering a 600-ohm line. All my radar texts say resonant transmission line sections have the same characteristics as resonant lumped circuits and I trust them because the radar circuits using tuned transmission lines to route the signal, work. Best regards, Richard Harrison, KB5WZI |