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#1
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I'm not sure if that's meant to be humorous, or if you really did
misinterpret what I meant. In case it's the latter, I'll amplify. If a quarter wavelength shorted stub at frequency f1 has impedance R1, then a quarter wavelength shorted stub at frequency f2 will have an impedance of R1 * sqrt(f2 / f1), if it's made of the same type of transmission line, and the frequency is in the range where conductor loss dominates (below about 1 - 10 GHz for typical coax). Roy Lewallen, W7EL W5DXP wrote: Roy Lewallen wrote: All else being equal, the impedance gets higher as frequency increases. Double the frequency and you have a shorted 1/2WL stub. Isn't the impedance of a shorted 1/2WL stub lower than the impedance of a shorted 1/4WL stub? |
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#2
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Roy Lewallen wrote:
I'm not sure if that's meant to be humorous, or if you really did misinterpret what I meant. In case it's the latter, I'll amplify. Whoops, I really did misinterpret what you meant. When you said, "All else being equal," I inferred that you were including the physical length of the stub. Changing the length of the stub didn't seem to match the condition, "All else being equal,". Sorry. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 80,000 Newsgroups - 16 Different Servers! =----- |
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