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Bill Turner wrote:
ORIGINAL MESSAGE: Tom, W8JI wrote: "A reflector does not reflect anything. It radiates." *********** REPLY SEPARATOR *********** Tom could have said "it reflects by radiating". Semantics count here. 73, Bill W6WRT That's an interesting point. Suppose you have a two-element driven array with the elements spaced a quarter wave apart and fed 90 degrees out of phase. This produces a cardioid pattern, which has a deep null. Is the element toward the direction of the null "reflecting" and the other one "directing"? If so, what are they "reflecting" and "directing"? Each element intercepts considerable energy from the other and reradiates it, if that makes a difference. Here's another one: Build a 4 square array, assuming the ground is perfect. (The EZNEC example file 4Square.EZ or demo equivalent d_4Square.EZ can be used to illustrate this.) If you disconnect the feedline to the rear array element and short circuit the feedpoint (by deleting Source 1 in the EZNEC model), you'll still have a moderately good directional pattern with about 15 dB front-back ratio. The rear element is now a parasitic element, which we like to call a "reflector". You've said it "reflects by radiating". Now connect the rear element feedline as in the original antenna. The front/back ratio improves. But the feedpoint resistance of the rear element is negative. This isn't particularly unusual in driven arrays -- it means that the element in question is absorbing power from the other elements and sending down the feedline toward the source. The element is still radiating, because current is flowing on it. But it's absorbing more power from the surrounding region than it's giving back in the form of a field. (Again, the excess is being sent back along the feedline to be used by the other elements.) So, is that element now "reflecting"? If so, is it "reflecting by radiating"? Roy Lewallen, W7EL |
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