Home |
Search |
Today's Posts |
#21
![]() |
|||
|
|||
![]()
Gene Fuller wrote:
Cecil Moore wrote: Oh, I forgot to ask you a technical question, Gene. Given that at 11.78 MHz, the current at the bottom of the coil is 0.17 amps and the current at the top is 2.0 amps, how do you explain those values if the current is flowing up through the coil? The details are at the bottom of the following web page. I don't recall anyone ever questioning such matters. You seem to be trying to have it both ways. 0.17 amps is not equal to 2.0 amps. 0 degrees is not equal to 180 degrees. How are those values possible in a lumped inductor? -- 73, Cecil http://www.qsl.net/w5dxp |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Self capacitance of solenoid coils | Antenna | |||
FCC: Broadband Power Line Systems | Policy | |||
Transmission Lines & Electrical Code | Antenna | |||
parallel transmission lines | Antenna |