Tom Donaly wrote:
They also like to talk about "current drops" when they mean the
difference in current amplitude at two different points.

For an EM wave in a lossy environment, the attenuation factor
applies equally to the E-field and H-field, i.e. equally to
voltage and current. Both "drop" at the same rate.

The transmission line voltage equation contains that attenuation
factor and the current equation is simply the voltage equation
divided by the characteristic impedance.

In a lossy transmission line, the H-field and E-field "drop"
at the same rate since their ratio is fixed by the
characteristic impedance.

One more proof that EM waves are NOT lumped circuit voltages
and currents.
--
73, Cecil http://www.qsl.net/w5dxp