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Old May 4th 06, 04:33 PM posted to rec.radio.amateur.antenna
Cecil Moore
 
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Default 4:1 balun question


"Reg Edwards" wrote:
When it sees 2000 + j1000 ohms there's hardly any current to choke
anyway.


Yes, but how much current is there 3/8WL back from that point?
--
73, Cecil, W5DXP


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Old May 4th 06, 05:34 PM posted to rec.radio.amateur.antenna
Reg Edwards
 
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Default 4:1 balun question


"Cecil Moore" wrote in message
om...

"Reg Edwards" wrote:
When it sees 2000 + j1000 ohms there's hardly any current to choke
anyway.


Yes, but how much current is there 3/8WL back from that point?
--
73, Cecil, W5DXP


Isn't that where you should be placing the choke? Give it some work
to do! Don't blame the choke for doing nothing. Blame yourself!
----
Reg.


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Old May 4th 06, 05:46 PM posted to rec.radio.amateur.antenna
Cecil Moore
 
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Default 4:1 balun question

"Reg Edwards" wrote:

W5DXP wrote:
Yes, but how much current is there 3/8WL back from that point?


Isn't that where you should be placing the choke?


Kinda hard to do if the feedline is ladder-line. Maybe a more
logical thing to do is to increase the length of the ladder-line until
a current maximum point is available at the coax/ladder-line
junction.
--
73, Cecil, W5DXP


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Old May 5th 06, 01:03 PM posted to rec.radio.amateur.antenna
 
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Default 4:1 balun question

Please all, remember,

The common-mode currents the choke is suppressing are not necessarily
related to the antenna impedance (the load) or the transmit/receive
currents flowing in the antenna, though there can and will be some
coupling between the two on an antenna (if you measure antenna Z
with/without a choke they will usually differ).

To place the choke in the best spot, you need to measure the common
mode current on the feedline and not the load impedance. If you have
common mode currents induced by an unbalanced situation in the antenna
itself, right at the antenna is probably best. Other places might be
good if you are coupling electrical noise to your feedline.
W1HIS's article was most interesting in this respect.

I would assume that because the feedline current is common-mode (the
same in both conductors), it will usually travel at the velocity factor
of a wire in air rather than the feedline velocity factor, though I do
not know this.

73,
Glenn AC7ZN

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