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#1
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![]() "Reg Edwards" wrote: When it sees 2000 + j1000 ohms there's hardly any current to choke anyway. Yes, but how much current is there 3/8WL back from that point? -- 73, Cecil, W5DXP |
#2
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![]() "Cecil Moore" wrote in message om... "Reg Edwards" wrote: When it sees 2000 + j1000 ohms there's hardly any current to choke anyway. Yes, but how much current is there 3/8WL back from that point? -- 73, Cecil, W5DXP Isn't that where you should be placing the choke? Give it some work to do! Don't blame the choke for doing nothing. Blame yourself! ---- Reg. |
#3
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"Reg Edwards" wrote:
W5DXP wrote: Yes, but how much current is there 3/8WL back from that point? Isn't that where you should be placing the choke? Kinda hard to do if the feedline is ladder-line. Maybe a more logical thing to do is to increase the length of the ladder-line until a current maximum point is available at the coax/ladder-line junction. -- 73, Cecil, W5DXP |
#4
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Please all, remember,
The common-mode currents the choke is suppressing are not necessarily related to the antenna impedance (the load) or the transmit/receive currents flowing in the antenna, though there can and will be some coupling between the two on an antenna (if you measure antenna Z with/without a choke they will usually differ). To place the choke in the best spot, you need to measure the common mode current on the feedline and not the load impedance. If you have common mode currents induced by an unbalanced situation in the antenna itself, right at the antenna is probably best. Other places might be good if you are coupling electrical noise to your feedline. W1HIS's article was most interesting in this respect. I would assume that because the feedline current is common-mode (the same in both conductors), it will usually travel at the velocity factor of a wire in air rather than the feedline velocity factor, though I do not know this. 73, Glenn AC7ZN |
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