Home |
Search |
Today's Posts |
#51
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
Cecil Moore wrote:
Gene Fuller wrote: I do not disagree with anything you have said. Please answer this question. Does the amplitude of the standing wave current contain any phase information? You have previously asserted that it does. Roy says it doesn't. Time to chose between technical fact and agreeing with your friend (who is technically incorrect). Cecil, You win! You have now set the new world record in misquoting. You might want to give a call to the fine folks at Guinness. 73, Gene W4SZ |
#53
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
Tom Donaly wrote:
If all you have is the value of current at one point, you can't possibly tell anything about the phase. But the value of current at one point is *NOT* all we have so your supposition is irrelevant. After a century of theory by some of the most brilliant human minds, we know virtually everything there is to know about a 1/2WL thin-wire dipole. We know there *IS* indeed phase information in the standing wave current magnitude just Kraus graphed it in his book. You need to compare it to something - itself even - somewhere or sometime else in order to have an idea of phase. The standard thing to compare it to is the feedpoint current, e.g. provided by EZNEC, usually 1.0 amps at 0 degrees. Here's what I mean: suppose I have a piece of wire of unknown length, excited by an unknown frequency, and picking a random point on the wire I measure 1.73 amps. What is the phase? You're trying to square the circle and hear the sound of one hand clapping at one and the same time, Cecil. First, you insult me with irrelevant ad hominem attacks ... Of course, in your case, you know the length of the wire, the frequency of the wave and its wavelength, and you think you know the current distribution on the wire (a half wavelength dipole) so you don't need anything but a ruler to find what you're looking for. And second, you agree with Kraus and me ... Here is a chart regarding Kraus' 1/2WL thin-wire dipole copied from my other posting. Please tell us what is wrong with it and exactly why the standing wave current magnitude doesn't tell us how many degrees away the feedpoint is for the formula I = Io*cos(X). X degrees away standing wave arc-cosine of the from feedpoint current magnitude current magnitude 0 1.000 amps 0 deg 30 0.866 amps 30 deg 45 0.707 amps 45 deg 60 0.500 amps 60 deg 90 0.000 amps 90 deg Do you really think it is a mere coincidence that column 1 and column 3 are identical??? -- 73, Cecil http://www.qsl.net/w5dxp |
#54
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
Tom Donaly wrote:
For someone like me, Cecil can be (but usually isn't) a very useful crackpot. I can be pretty sure he's wrong, but the process of educating myself into turning that hunch into a dead certainty that I can prove to everyone (except him) can be enlightening. Now's your chance to enlighten us, Tom. Please explain again how the standing wave current magnitude on a 1/2WL thin-wire dipole doesn't depend upon how many degrees it is away from the feed point, i.e. doesn't contain any phase information. While you are at it, please explain exactly how Kraus is mistaken about this antenna when he plots the standing wave current as I = cos(X) where X is the number of degrees away from the feedpoint and feedpoint current equals 1 amp at 0 degrees. -- 73, Cecil http://www.qsl.net/w5dxp |
#55
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
Gene Fuller wrote:
Cecil Moore wrote: Please answer this question. Does the amplitude of the standing wave current contain any phase information? You have previously asserted that it does. Roy says it doesn't. Time to chose between technical fact and agreeing with your friend (who is technically incorrect). Cecil, You win! You have now set the new world record in misquoting. You might want to give a call to the fine folks at Guinness. It was a simple yes/no question, Gene. That you refuse to answer speaks volumes so I will ask it once again, copying from a previous posting that you ignored. Just insert an 'X' for the one you agree with. If you don't respond, I will add this to a long list of questions that I have asked that the "experts" are afraid to answer. _____ Standing wave current magnitude contains some phase information. _____ Standing wave current magnitude contains zero phase information. -- 73, Cecil http://www.qsl.net/w5dxp |
#56
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
Cecil Moore wrote:
Tom Donaly wrote: If all you have is the value of current at one point, you can't possibly tell anything about the phase. But the value of current at one point is *NOT* all we have so your supposition is irrelevant. After a century of theory by some of the most brilliant human minds, we know virtually everything there is to know about a 1/2WL thin-wire dipole. We know there *IS* indeed phase information in the standing wave current magnitude just Kraus graphed it in his book. You need to compare it to something - itself even - somewhere or sometime else in order to have an idea of phase. The standard thing to compare it to is the feedpoint current, e.g. provided by EZNEC, usually 1.0 amps at 0 degrees. Here's what I mean: suppose I have a piece of wire of unknown length, excited by an unknown frequency, and picking a random point on the wire I measure 1.73 amps. What is the phase? You're trying to square the circle and hear the sound of one hand clapping at one and the same time, Cecil. First, you insult me with irrelevant ad hominem attacks ... Of course, in your case, you know the length of the wire, the frequency of the wave and its wavelength, and you think you know the current distribution on the wire (a half wavelength dipole) so you don't need anything but a ruler to find what you're looking for. And second, you agree with Kraus and me ... Here is a chart regarding Kraus' 1/2WL thin-wire dipole copied from my other posting. Please tell us what is wrong with it and exactly why the standing wave current magnitude doesn't tell us how many degrees away the feedpoint is for the formula I = Io*cos(X). X degrees away standing wave arc-cosine of the from feedpoint current magnitude current magnitude 0 1.000 amps 0 deg 30 0.866 amps 30 deg 45 0.707 amps 45 deg 60 0.500 amps 60 deg 90 0.000 amps 90 deg Do you really think it is a mere coincidence that column 1 and column 3 are identical??? Cecil, you can always know something you already know. Knowing that your antenna is 1/2 wavelength long gives you all the information you need for your definition of phase. By the way, where did you get that table, from EZNEC? 73, Tom Donaly, KA6RUH |
#57
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
Cecil Moore wrote:
Tom Donaly wrote: For someone like me, Cecil can be (but usually isn't) a very useful crackpot. I can be pretty sure he's wrong, but the process of educating myself into turning that hunch into a dead certainty that I can prove to everyone (except him) can be enlightening. Now's your chance to enlighten us, Tom. Please explain again how the standing wave current magnitude on a 1/2WL thin-wire dipole doesn't depend upon how many degrees it is away from the feed point, i.e. doesn't contain any phase information. While you are at it, please explain exactly how Kraus is mistaken about this antenna when he plots the standing wave current as I = cos(X) where X is the number of degrees away from the feedpoint and feedpoint current equals 1 amp at 0 degrees. I didn't say that the value of the standing wave current on a 1/2 wavelength dipole doesn't vary with length. I did say that just measuring the value at some point doesn't give you all the information you need to calculate the phase. Of course, you already know the phase, because you defined the antenna as 1/2 wavelength, so finding any kl is trivial. Secondly, even if you're right about the current in your antenna being a sine function, in order to use that information, you have to measure the current input at the current maximum - which you've already defined to be the center of the antenna - in order to compare it with the current at the point of interest in order to get your result. In short, you still have to know the current at two points in order to get an answer. The information isn't contained in just one measurement. So let me turn it around and ask you to tell me again why you think you can get some "phase" information from measuring a single point on an antenna without knowing anything else about it. I haven't read Kraus, but I expect he was talking about an idealized, infinitely thin antenna. Add thickness to the wire, and a feedpoint gap, and you may come up with something slightly more complicated. 73, Tom Donaly, KA6RUH |
#58
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
Cecil Moore wrote:
Gene Fuller wrote: Cecil Moore wrote: Please answer this question. Does the amplitude of the standing wave current contain any phase information? You have previously asserted that it does. Roy says it doesn't. Time to chose between technical fact and agreeing with your friend (who is technically incorrect). Cecil, You win! You have now set the new world record in misquoting. You might want to give a call to the fine folks at Guinness. It was a simple yes/no question, Gene. That you refuse to answer speaks volumes so I will ask it once again, copying from a previous posting that you ignored. Just insert an 'X' for the one you agree with. If you don't respond, I will add this to a long list of questions that I have asked that the "experts" are afraid to answer. _____ Standing wave current magnitude contains some phase information. _____ Standing wave current magnitude contains zero phase information. If a magnitude can, by itself, contain phase information, why do we have to specify the angle in a phasor? 73, Tom Donaly, KA6RUH |
#59
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
Tom Donaly wrote:
Cecil, you can always know something you already know. Knowing that your antenna is 1/2 wavelength long gives you all the information you need for your definition of phase. Apparently that knowledge is not enough for W7EL who said regarding the current distribution in a 1/2WL thin-wire dipole: W7EL wrote: Of course I reject the notion that there's "phase information in the standing wave current magnitude". This in the face of technical evidence that the standing wave current magnitude is a cosine function of the number of degrees the referenced point is away from the feedpoint. Also contradicting Gene Fuller who said: The only "phase" remaining is the cos (kz) term, which is really an amplitude description, not a phase. By the way, where did you get that table, from EZNEC? From page 464 of "Antennas for all Applications", 3rd Edition, by Kraus and Marhefka. Where Kraus presents the independent variable in fractions of a wavelength, I simply converted it to degrees. Most knowledgeable people comprehend that there are 360 degrees per sinusoidal cycle, i.e. per one wavelength. -- 73, Cecil http://www.qsl.net/w5dxp |
#60
|
|||
|
|||
FIGHT! FIGHT! FIGHT!
On Mon, 15 May 2006 17:12:58 GMT, "Tom Donaly"
wrote: _____ Standing wave current magnitude contains some phase information. _____ Standing wave current magnitude contains zero phase information. If a magnitude can, by itself, contain phase information, why do we have to specify the angle in a phasor? Hi Tom, Cecil probably doesn't understand that both options give both current magnitude AND phase as choices. Rather makes the "question" pointless, but nothing new in the correspondence from our Xerox philosopher. For the record: ____X____ Standing wave current magnitude contains NO phase information. 73's Richard Clark, KB7QHC |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
Similar Threads | ||||
Thread | Forum | |||
Steveo Fight Checklist | CB | |||
Steveo/Race Worrier Fight Schedule so far | CB |