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-   -   100 Ohm Twin Lead (https://www.radiobanter.com/antenna/94448-100-ohm-twin-lead.html)

Cecil Moore May 16th 06 02:24 PM

100 Ohm Twin Lead
 
Buck wrote:

The SWR on the 600 ohm line will be 600/25 = 24:1

The SWR on 50 ohm coax will be 50/25 = 2:1

For a 25 ohm single band antenna, I would be inclined to go with
the coax.


Ok, I learned something, but I would be inclined to go with the 1/2
wave of 75 ohm and then the 50 ohm ;)


"1/2 wave of 75 ohm" would make matters worse for a 25 ohm
antenna since the SWR would be higher than for 50 ohms.
What you need is 1/4WL of 35 ohm coax like RG83.
--
73, Cecil http://www.qsl.net/w5dxp

Buck May 16th 06 02:41 PM

100 Ohm Twin Lead
 
On Tue, 16 May 2006 13:24:37 GMT, Cecil Moore
wrote:

Buck wrote:

The SWR on the 600 ohm line will be 600/25 = 24:1

The SWR on 50 ohm coax will be 50/25 = 2:1

For a 25 ohm single band antenna, I would be inclined to go with
the coax.


Ok, I learned something, but I would be inclined to go with the 1/2
wave of 75 ohm and then the 50 ohm ;)


"1/2 wave of 75 ohm" would make matters worse for a 25 ohm
antenna since the SWR would be higher than for 50 ohms.
What you need is 1/4WL of 35 ohm coax like RG83.


OOPS, I went back to the original problem with 100 ohm



--
73 for now
Buck
N4PGW

Cecil Moore May 16th 06 03:30 PM

100 Ohm Twin Lead
 
Buck wrote:

Cecil Moore wrote:

Buck wrote:
Ok, I learned something, but I would be inclined to go with the 1/2
wave of 75 ohm and then the 50 ohm ;)


"1/2 wave of 75 ohm" would make matters worse for a 25 ohm
antenna since the SWR would be higher than for 50 ohms.
What you need is 1/4WL of 35 ohm coax like RG83.


OOPS, I went back to the original problem with 100 ohm


Then you should use 1/4 wave of 75 ohm, not 1/2 wave.
--
73, Cecil http://www.qsl.net/w5dxp

Buck May 17th 06 05:37 AM

100 Ohm Twin Lead
 
On Tue, 16 May 2006 14:30:52 GMT, Cecil Moore
wrote:

Buck wrote:

Cecil Moore wrote:

Buck wrote:
Ok, I learned something, but I would be inclined to go with the 1/2
wave of 75 ohm and then the 50 ohm ;)

"1/2 wave of 75 ohm" would make matters worse for a 25 ohm
antenna since the SWR would be higher than for 50 ohms.
What you need is 1/4WL of 35 ohm coax like RG83.


OOPS, I went back to the original problem with 100 ohm


Then you should use 1/4 wave of 75 ohm, not 1/2 wave.

ok, a 100 ohm load fed with 50 ohm coax is a 2:1 swr. Fed with 75 ohm
coax, it is 1.33:1 ??

If the 75 ohm is fed with 50 ohm coax 1/4 wave down the 75 ohm coax,
it will be a close match?

Why did the impedance change to 52 ohms?
--
73 for now
Buck
N4PGW

John Popelish May 17th 06 06:01 AM

100 Ohm Twin Lead
 
Buck wrote:

ok, a 100 ohm load fed with 50 ohm coax is a 2:1 swr. Fed with 75 ohm
coax, it is 1.33:1 ??

If the 75 ohm is fed with 50 ohm coax 1/4 wave down the 75 ohm coax,
it will be a close match?

Why did the impedance change to 52 ohms?


Because of the energy bouncing back and forth between the 100 ohm load
(that mismatches the 75 ohm, so causes a reflection) and the 50 ohm
feed (that mismatches the 75 ohm section, so causes a reflection).

If the 1/4 wave section has an impedance that is the geometric mean of
the impedance on each end, it creates a perfect matching resonator.

So the perfect 1/4 wave matching section between 50 and 100 ohms would
have an impedance of the square root of (50 times 100) or 70.7 ohms.
75 is pretty close.

Cecil Moore May 17th 06 01:13 PM

100 Ohm Twin Lead
 
Buck wrote:
ok, a 100 ohm load fed with 50 ohm coax is a 2:1 swr. Fed with 75 ohm
coax, it is 1.33:1 ??


Yes, and 75/1.33 = 56.25 ohms. For a perfect match to 50
ohms, one would need Z0 = SQRT(100*50) = 70.7 ohms.

If the 75 ohm is fed with 50 ohm coax 1/4 wave down the 75 ohm coax,
it will be a close match?


The SWR on the 50 ohm coax will be 56.25/50 = 1.125:1

Why did the impedance change to 52 ohms?


It didn't. It changed to 56.25 ohms. The load is 100 ohms
and the Z0 is 75 ohms so the SWR is 1.33:1 at the current
minimum/voltage maximum point. To find the impedance 1/4WL
away, divide Z0 by SWR, 75/1.33 = 56.25 ohms.
--
73, Cecil http://www.qsl.net/w5dxp

Buck May 18th 06 04:46 AM

100 Ohm Twin Lead
 
On Wed, 17 May 2006 12:13:57 GMT, Cecil Moore
wrote:


It didn't. It changed to 56.25 ohms. The load is 100 ohms
and the Z0 is 75 ohms so the SWR is 1.33:1 at the current
minimum/voltage maximum point. To find the impedance 1/4WL
away, divide Z0 by SWR, 75/1.33 = 56.25 ohms.


Thanks, I understand how that works now.


--
73 for now
Buck
N4PGW


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