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#31
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Buck wrote:
The SWR on the 600 ohm line will be 600/25 = 24:1 The SWR on 50 ohm coax will be 50/25 = 2:1 For a 25 ohm single band antenna, I would be inclined to go with the coax. Ok, I learned something, but I would be inclined to go with the 1/2 wave of 75 ohm and then the 50 ohm ![]() "1/2 wave of 75 ohm" would make matters worse for a 25 ohm antenna since the SWR would be higher than for 50 ohms. What you need is 1/4WL of 35 ohm coax like RG83. -- 73, Cecil http://www.qsl.net/w5dxp |
#32
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On Tue, 16 May 2006 13:24:37 GMT, Cecil Moore
wrote: Buck wrote: The SWR on the 600 ohm line will be 600/25 = 24:1 The SWR on 50 ohm coax will be 50/25 = 2:1 For a 25 ohm single band antenna, I would be inclined to go with the coax. Ok, I learned something, but I would be inclined to go with the 1/2 wave of 75 ohm and then the 50 ohm ![]() "1/2 wave of 75 ohm" would make matters worse for a 25 ohm antenna since the SWR would be higher than for 50 ohms. What you need is 1/4WL of 35 ohm coax like RG83. OOPS, I went back to the original problem with 100 ohm -- 73 for now Buck N4PGW |
#33
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Buck wrote:
Cecil Moore wrote: Buck wrote: Ok, I learned something, but I would be inclined to go with the 1/2 wave of 75 ohm and then the 50 ohm ![]() "1/2 wave of 75 ohm" would make matters worse for a 25 ohm antenna since the SWR would be higher than for 50 ohms. What you need is 1/4WL of 35 ohm coax like RG83. OOPS, I went back to the original problem with 100 ohm Then you should use 1/4 wave of 75 ohm, not 1/2 wave. -- 73, Cecil http://www.qsl.net/w5dxp |
#34
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On Tue, 16 May 2006 14:30:52 GMT, Cecil Moore
wrote: Buck wrote: Cecil Moore wrote: Buck wrote: Ok, I learned something, but I would be inclined to go with the 1/2 wave of 75 ohm and then the 50 ohm ![]() "1/2 wave of 75 ohm" would make matters worse for a 25 ohm antenna since the SWR would be higher than for 50 ohms. What you need is 1/4WL of 35 ohm coax like RG83. OOPS, I went back to the original problem with 100 ohm Then you should use 1/4 wave of 75 ohm, not 1/2 wave. ok, a 100 ohm load fed with 50 ohm coax is a 2:1 swr. Fed with 75 ohm coax, it is 1.33:1 ?? If the 75 ohm is fed with 50 ohm coax 1/4 wave down the 75 ohm coax, it will be a close match? Why did the impedance change to 52 ohms? -- 73 for now Buck N4PGW |
#35
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Buck wrote:
ok, a 100 ohm load fed with 50 ohm coax is a 2:1 swr. Fed with 75 ohm coax, it is 1.33:1 ?? If the 75 ohm is fed with 50 ohm coax 1/4 wave down the 75 ohm coax, it will be a close match? Why did the impedance change to 52 ohms? Because of the energy bouncing back and forth between the 100 ohm load (that mismatches the 75 ohm, so causes a reflection) and the 50 ohm feed (that mismatches the 75 ohm section, so causes a reflection). If the 1/4 wave section has an impedance that is the geometric mean of the impedance on each end, it creates a perfect matching resonator. So the perfect 1/4 wave matching section between 50 and 100 ohms would have an impedance of the square root of (50 times 100) or 70.7 ohms. 75 is pretty close. |
#36
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Buck wrote:
ok, a 100 ohm load fed with 50 ohm coax is a 2:1 swr. Fed with 75 ohm coax, it is 1.33:1 ?? Yes, and 75/1.33 = 56.25 ohms. For a perfect match to 50 ohms, one would need Z0 = SQRT(100*50) = 70.7 ohms. If the 75 ohm is fed with 50 ohm coax 1/4 wave down the 75 ohm coax, it will be a close match? The SWR on the 50 ohm coax will be 56.25/50 = 1.125:1 Why did the impedance change to 52 ohms? It didn't. It changed to 56.25 ohms. The load is 100 ohms and the Z0 is 75 ohms so the SWR is 1.33:1 at the current minimum/voltage maximum point. To find the impedance 1/4WL away, divide Z0 by SWR, 75/1.33 = 56.25 ohms. -- 73, Cecil http://www.qsl.net/w5dxp |
#37
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On Wed, 17 May 2006 12:13:57 GMT, Cecil Moore
wrote: It didn't. It changed to 56.25 ohms. The load is 100 ohms and the Z0 is 75 ohms so the SWR is 1.33:1 at the current minimum/voltage maximum point. To find the impedance 1/4WL away, divide Z0 by SWR, 75/1.33 = 56.25 ohms. Thanks, I understand how that works now. -- 73 for now Buck N4PGW |
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