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Roy Lewallen wrote:
chuck wrote: . . . 2. What would the ohmic losses be over a one square foot by 33 foot path through salt water? Let's see, salt water conductivity is about 5 S/m, which is 1.524 S/ft. So the *DC* resistance of that piece of sea water would be 1.524 * 33 / (1 * 1) ~ 50 ohms. . . Oops. The DC resistance would be 33 / (1 * 1) / 1.524 ~ 22 ohms. Roy Lewallen, W7EL |
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