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Reg Edwards wrote:
The permittivity, K, of water is about 80. The relative velocity of propagation along a wire immersed in water is about VF = 1/Sqrt( K ) = 0.11 At a frequency of 7.5 MHz, a 1/4-wavelength of wire immersed in water is only 1.1 metres = 43 inches long. Furthermore, in salt sea water, considering a wire as a transmission line, dielectric loss is so high there is little or no current flowing at the end of a quarterwave radial wire. Longer wires can be disregarded because they carry no current. So, at 7.5 MHz, there is no point in considering a system which has more than a radius of 1.1 metres. At higher frequencies the radius is even less. A copper coin, 1" in diameter, immersed in a large volume of salt water, has an impedance low enough to be used as an efficient ground for a 1/4-wave HF vertical antenna. It is limited by its power handling capacity. I have made measurements years ago but have no records as I didn't attach any importance to them at the time. And still don't. Unpolluted, clean, fresh pond water, is a different kettle of fish. Permittivity is still about 80 but the resistivity is very much greater. About 1000 ohm-metres is a reasonable value. ---- Reg. Interesting info, Reg. I also made some kitchen table-top sal****er measurements about a year ago, but at much lower frequencies than you discuss. My measurements are not handy at the moment, but they don't comport with yours. I utilized a variety of electrode geometries: concentric, 4 pole, parallel plate, etc. Measurements of electric field strength, conductivity, path conductance, etc. are not difficult but interpretation of the data stumped me. As you remember, the conductance of a sal****er path is a direct function of the path's cross-sectional area. A penny doesn't produce much of a cross-sectional area at its end of the path. Maybe your pennies are better than ours, Certainly worth more. 73. Chuck |
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