Home |
Search |
Today's Posts |
|
#1
![]() |
|||
|
|||
![]()
Dave wrote:
is that line 1 second long, or 1/2 second long?? a 1 second long line would take 2 seconds worth of energy from the generator before the reflection returned to let it know the line is terminated. this is of course very important if you are measuring lines with tdr's where you can really see those returned waves, of course the time it takes them to get back to the tdr is double the one-way travel time... mess it up and you are looking for faults twice as far down the line as you calculate. The line is 1 second long. The source is generating 100 watts. So the number of joules generated starting at t=0 is 100N where N is the total number of seconds. At the end of 30 seconds, the generator will have sourced 3000 joules which must be conserved. I will generate an EXCEL spreadsheet at work today and post it to my web page when I get home. It will cover the first 30 seconds in 1 second increments. It will show that of the 3000 joules sourced by the generator during that first 30 seconds, only 2700 joules have reached the load. The other 300 joules are contained in the 200W forward wave and 100W reflected wave. (200 watts)(one second) = 200 joules in the forward wave (100 watts)(one second) = 100 joules in the reflected wave 200 joules + 100 joules = 300 joules not delivered to the load -- 73, Cecil http://www.qsl.net/w5dxp |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
brainteaser exercise | Antenna |