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#21
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On Mon, 19 Jun 2006 12:01:37 -0700, Roy Lewallen
wrote: do it. What the U.S. did was to declare the metric system to be official ("Mission Accomplished!") and change whiskey bottles from fifths to 750 ml (which was promoted by the booze industry because it made the bottles just a little smaller and they could charge the same price). Wow. Roy, you overlooked that the US, an earlier signup to SI, fixed the spelling of metre in the US variant of SI. Owen -- |
#22
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Dear Howard W3CQH:
You have not been clear about what information you need. What do you wish to accomplish? Here is Section 207: Telecommunications Act of 1996 SEC. 207. RESTRICTIONS ON OVER-THE-AIR RECEPTION DEVICES. Within 180 days after the date of enactment of this Act, the Commission shall, pursuant to section 303 of the Communications Act of 1934, promulgate regulations to prohibit restrictions that impair a viewer's ability to receive video programming services through devices designed for over-the-air reception of television broadcast signals, multichannel multipoint distribution service, or direct broadcast satellite services. It sure is not clear what this has to do with what you have said so far. ...... and, in "real" engineering: Kg is the unit of mass in the SI mks system. Newton is the unit of force. F does equal MA (at least for low velocities). 73 Mac, N8TT -- J. Mc Laughlin; Michigan U.S.A. Home: "Howard W3CQH" wrote in message ... Thanks to all that have answered my original post - but the information that I seek has not been answered. I understand that section 207 of the FCC telecomm act 1996 contains information that I might be able to use to help me in this matter. Where can I obtain a copy of Section 207? I cannot find it posted on the FCC website! Thanks, "Howard W3CQH" wrote in message news ![]() Looking for specs on any log periodic antenna that covers 50Mhz - 1300Mhz, (Ham variety). Specs must also contain that it can withstand 80MPH wind and 30 Lbs of ICE? Thanks and best DXin. de Howard W3CQH |
#23
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gravity wrote:
please read the NIST publications which define the Avoirdupois pound in terms of kilograms. this is not debateable since NIST is *the* authority in the US. The NIST isn't the authority on the laws of physics. One of the most basic of which is F=MA, if you use pounds for mass in that formula you get the wrong answer. Nothing that NIST says will change that. 200 lbs = 6.25 slugs * 32 ft/sec^2. Using pounds, the formula won't work any other way. -- Chris W KE5GIX Gift Giving Made Easy Get the gifts you want & give the gifts they want One stop wish list for any gift, from anywhere, for any occasion! http://thewishzone.com |
#24
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![]() Chris W wrote: Owen Duffy wrote: I was taught (in imperial units) to differentiate mass (pound) and force (pound-force). That learning stood me well when we changed to SI (metric) part way through school. You were taught wrong. If you use pounds in a formula that wants mass such as F=M*A you will get the wrong answer. So lets say you weigh 200 lbs on earth where A = 32 ft/sec^2. You can then calculate your mass by solving for M = F/A or 200/32 = 6.25. If you "weigh" 200 lb (no s at the end of unit symbols) on Earth, that _is_ your mass, in normal usage in either the medical sciences or in sports, which are of course the purposes for which we normally weigh ourselves. You can, of course, use those 200 pounds in the F = ma formula. For example, if you accelerate those 200 pounds at 40 ft/s², the force is 8000 lb·ft/s², which is, of course, 8000 poundals, since a poundal is the force which will accelerate a mass of one pound at a rate of 1 ft/s². When you are doing physical calculations it is very important to use the correct units, other wise you calculations are meaningless. Suppose you want to know what you will weigh on the moon where the acceleration due to gravity is 5.25 ft/sec^2. F = M*A if you use 200 for your mass you get, 200 * 5.25 = 1050, that indicates you would weigh 1050 lbs on the moon. Which is clearly wrong. Trying again with the correct units and you get, 6.25 * 5.25 = 32.8, now that sounds more like what you would weight on the moon. Not at all. It indicates that you exert a force due to gravity of 1050 poundals (not lbs) on the moon. On Earth, you would exert a force of somewhere in the neighborhood of 6410 poundals to 6450 poundals, depending on your specific location. Not only is it just as easy to use an unfamiliar unit for force as it is to use some strange unit for mass, but the absolute foot-pound-second system (which includes poundals) has been around considerably longer than the gravitational foot-pound-second system (which includes slugs), and rather than either of those systems, those still using English units are more likely to use the engineering system which includes both pounds and pounds force, but neither slugs nor poundals. Since that system is not a completely coherent system, of course, many of the formulas need to be adjusted with a g_c factor, a dimensionless number equal to the ratio of the acceleration used to define a pound-force to that used to define a poundal, or g_c = (32.174 ft/s²)/(1 ft/s²) = 32.174 In the non scientific world, where the metric unit KG is used for weight, M=F*A works just fine if you put what you call "weight" in KG in for M in the formula. The symbol for kilograms is kg, not KG. There is nothing different about the weight in the English units world, where the pound used for this purposes is, by definition, exactly 0.45359237 kg. Gene Nygaard |
#25
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![]() Chris W wrote: gravity wrote: please read the NIST publications which define the Avoirdupois pound in terms of kilograms. this is not debateable since NIST is *the* authority in the US. The NIST isn't the authority on the laws of physics. One of the most basic of which is F=MA, if you use pounds for mass in that formula you get the wrong answer. Nothing that NIST says will change that. 200 lbs = 6.25 slugs * 32 ft/sec^2. Using pounds, the formula won't work any other way. Bull****. Here are a couple of other ways that work just fine with FFU: 200 lb * 32.2 ft/s² = 6440 pdl 0.52 slinch * 386 in/s² = 200 lbf Be sure to distinguish pounds force (lbf) from pounds (lb), and units of measure should remain unchanged in the plural, without adding any language-specific "s" or whatever. Gene Nygaard |
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