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#31
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On 11 Jul 2006 12:21:06 -0700, "
wrote: I wanted to know what the current was in the center conductor of a piece of RG-8 being used as a monopole. The answer to that question is not trivially calculable, though it might be trivial in the sense of being trivia... who cares? I did. Dan Hi Dan, All the issues you focus on are quite particular and specific, and perhaps too much so. I find them equally interesting and you ask reasonable questions. Unfortunately, you question above suffers from every problem imaginable for measuring, and any report you get without considerable qualification is probably sheer fancy. It suffers from a version of Heisenberg's problem of disturbing what you attempt to measure, and invalidating everything in the process. Another way of stating this problem, with more practicality, is that you have to put a wire into the coax to add your meter to make the measurement. This then brings that wire's own contribution, which, as you've noted, can raise the stakes considerably. I, too, have played with a variant of your model (I can push the mesh finer and have worked with a 16 sided coax model). However, instead of driving the line like a monopole, I simply plunked a source into the wire skeleton of the "shield." But to return to your own published model, I've played with the length of wire 26 after discovering it emerged from both ends of the coax. I don't put much credit to Cecil's invention of topics, so I am unaware if this wire length meets some criteria (even if it did, I would still suspect the detail would have been spurious). Be that as it may. After truncating the wire 26 so that it did not come anywhere closer to the mouth of the coax (either end) than 5 feet, "induced" currents plummeted like a rock. 73's Richard Clark, KB7QHC |
#32
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Richard, You hit this nail on the head, for su
All the issues you focus on are quite particular and specific, and perhaps too much so. I find them equally interesting and you ask reasonable questions. Unfortunately, you question above suffers from every problem imaginable for measuring, and any report you get without considerable qualification is probably sheer fancy. It suffers from a version of Heisenberg's problem of disturbing what you attempt to measure, and invalidating everything in the process. I don't have much trouble with the antennas I actually build. The aluminum and wire I sling around tend to behave. I do have some vested interest in overspecific modeling in the sense that since I'm deploying all my antennas from the balcony of my apartment (with its overhanging roof), and don't have much space to build, adjustments and pruning are very hard to do. Some performance gains can certainly be had by adjustment... but in my situation now it's so much easier to push bits around in EZNEC. This one, though, was just pure impractical theoretical curiosity. That, and a little bit of being concerned that people seemed to "know" the answer, that the answer was obvious, and, well, I didn't think it was. The current in real experiment would be, as you pointed out, pretty much impossible to measure without disturbing it. But as I see it, from a practical standpoint, in a real system where you're using the shield of a piece of coax as an antenna , the current in the center conductor never matters. The existence of the current matters, at least as a learning experience. It matters in the sense that some seem to think that there couldn't be a current, just because a piece of coax is "shielded". Or because the center conductor is "floating". It's precisely the fact that the center conductor is "floating" that makes the (probably) weak coupling at the ends important. Thanks for posting your results. What you describe certainly jives with the fuzzy idea that I've got of what's doing the coupling ... or at least where it's happening. Of course, the tube without center conductor is certainly a waveguide well below cutoff, so we've got solid footing saying a short wire inside a long conductive tube a small fraction of a wavelength in diameter will have little current on it... and the model also exhibits this. I'm done with this one unless I find a leadless current meter (small, battery powered with an A/D converter and optical fiber out?) and a big piece of copper pipe laying around! 73, Dan |
#33
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![]() Cecil Moore wrote: wrote: Cecil Moore wrote: I have used that same circuit to switch a top hat in and out. How much RF power did I lose by taking that route? That is NOTHING like the problem the ZL on eHam had. Clutching at straws, are we? It's exactly like the ZL problem except the relay is used to switch a top hat instead of a wire. -- 73, Cecil http://www.qsl.net/w5dxp Cecil, In your alleged system, you carried RF through the coax and used the coax as a swixcthing stub. In the other fellows system, he had a high impedance feed and had to get a relay conductor past the high impedance feed without affecting the system. They are TOTALLY different. Even a card carrying mensa member can't be that out of touch with a simple system like this. 73 Tom |
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