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#1
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wrote:
You still need to be able to couple to the ends, and a floating center conductor is not the best way to couple energy in. However, there's no fundamental physical reason why currents *won't* flow on the center conductor in an open-ended piece of coax. How about when there's two RF chokes in series? -- 73, Cecil http://www.qsl.net/w5dxp |
#2
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I think it's just a matter of degree. The more RF chokes there are,
the less current will flow. It would be a straightforward matter to add more wire to the model and include loads for bypass caps and chokes. In either case (wire inside or outside of the shield) good decoupling where the wire lead exits is going to be important. The model so far may suggest that being inside the shield is better than being outside... but without that lead trailing away from the antenna some distance, it's not time to conclude much about the relay+half square problem. The 40m coax monopole answer would seem to be "yes, there's current on the center conductor, but it's small and coupled in through the ends" If you're using the standard EZNEC, you're going to have to knock another section off the top of the cage... if you've got EZNEC+ then just add away... I may try it when I get home... knock another section off and try a control wire... Might have to send off my money to Roy and go for EZNEC+... I know I can get around segment limitations with other programs but I do like EZNEC. This is probably the ninth time since I got the program a few months ago that I've hit the segment limit ... i like meshing things... Gives me a question about the (EZ)NEC limitations... should I be watching out for fine 2D meshes? It seems to work OK in this case... the base impedance of the meshed monopole and the current distribution viewed on the segments all makes sense, and it seems to me that there's not much reason to doubt that the currents are calculated correctly in the mesh as long as it's not coarse with respect to a wavelength... any caveats in this regard? 73, Dan |
#3
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I should have said "the more RF chokes there are, the less current will
flow in the center conductor of the case where the wire is inside the shield" by the way. If the RF chokes and wire are inside the shield, it will keep the current off the wire inside the shield. However, where the wire exits the shield, currents can still be induced on it... this is what allows current to flow on the unchoked center conductor, right? So why wouldn't it flow in the other direction. So you need chokes some distance outside the shield to isolate the rest of the wire from the antenna. If you put the wire outside the shield and put chokes at the top and bottom, some distance away from the antenna, then a very large current will be induced on the wire between the chokes compared to the current you get on the wire inside the shield. However, this doesn't immediately translate into more current on the control wire trailing away. It is just saying something about the wire between the top and bottom chokes. What you're trying to do is decouple the control wire going away from the antenna from the antenna. Decoupling the control wire that runs up inside or outside of the antenna isn't very important as long as current doesn't flow on the control wire to the shack. Whether or not inside or outside of the tower/tube helps depends on a lot of factors and should be answered with some sort of calculation... Seems that the various claims are testable... I'll post anything I come up with. Dan |
#5
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![]() Cecil Moore wrote: wrote: If the RF chokes and wire are inside the shield, it will keep the current off the wire inside the shield. I hope W8JI is reading this. He insists that it will still function as a stub and such an approach is "useless". However, where the wire exits the shield, currents can still be induced on it... this is what allows current to flow on the unchoked center conductor, right? So why wouldn't it flow in the other direction. So you need chokes some distance outside the shield to isolate the rest of the wire from the antenna. Just outside the shield is a relay with an RF bypass cap across its coil. -- 73, Cecil http://www.qsl.net/w5dxp Turn in your mensa membership card Cecil. You flunked basic grade-K problem solving logic. :-) |
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