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![]() Since my earlier post (dealing with the question of what is peak evelope power output in an AM transmitter), I've been doing more scrutinizing of tube Ip/Vp characteristic curves. They are much more non-linear than the impression you get from just looking at the curves. Also, it is rare or almost non-existant to find Ip vs screen voltage! Lets look at the venerable 833 (from my RCA TT-3 transmitting tube manual). This is a KW input class C triode. From the curve: at zero grid volts, 1 kV on the plate gives 175 ma plate current 2 kV 500 ma That's more than a doubling of Ip for a doubling of Vp at minus 50 grid volts, 2 kV on the plate gives 50 ma plate current 4 kV 750 ma looking in my RCA receiving tube manual (RC-20) I found for a 6FG6 a sharp cutoff tetrode that only at zero grid volts was there a near linear relationship between plate current and plate voltage (meaning zero current at zero voltage, and a straight line [which actually deviated slightly from a straight line] with some slope. But at 100 v on plate, current was 14 milliamps, at 200 v on the plate, plate current was 34 miliamps. Definitely NOT a linear relationship. For the 6EM7 a triode, and at any of a wide range of grid voltages, plate current could be doubled with only a 15-20% increase in plate voltage. My thinking on all of this leads me to claim that anyone who can start with a 100 watt carrier from an AM transmitter and make a few assumptions about 100% modulation and come up with a _calculation_ of something like 400 watts of peak power and represent that as having something to do with reality is pure conjecture. If anyone wants to put an appropriate oscilloscope on the transmitter output and measure the RF voltage of unmodulated carrier into an appropriate load and then measure the peak RF voltage when the carrier is modulated, then and only then do they have a reasonable _basis_ for making a claim about peak (instantaneous) output power. |
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