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![]() "clifto" wrote in message news ![]() Roger Hamlett wrote: If (for instance), you have a 3mm shaft, and 10mm balls, the casing has to have an internal diameter of 26mm, and the ratio is 26/3 = 8.66:1. I could be missing something, but at first glance I read the radius as the diameter of the 10mm ball (10mm) plus half the diameter of the 3mm shaft (1.5mm) and get 23mm internal diameter, ratio of 23:3 or 7.66:1. Just in case this turns out to be a corecktion I've included speling erors to comply with tradishun. Yes. Sorry, I just added up the internal diameter wrong.... It is fairly simple to visualise what is happening, if you realise that the balls are rolling round the internal diameter of the casing, driven by the small shaft at the centre, and for the assembly of three balls to complete one complete turn, their surfaces, must travel the internal diameter of the outer casing. Since the surfaces of the balls are driven by the internal shaft, you get the ratio from the ratio of these two diameters. Best Wishes |
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