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![]() Loading the circuit more reduces the pp voltage in the tank. And since the tank Z is about 200R, p=e(squared)/r so p=1.6 watts in the tank circuit. Where are you getting the "200R" value from? (And what is 'R'?) Another thought is to change the L/C ratio which should give a different loaded Q with a given poker position. This may provide more power out. |
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