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![]() happen. The output of the regulator will likely try to go to its full input voltage rail (because of the high gain of the darlingtons). The feedback loop in the regulator will try to bring it back down to the set output voltage. It probably can't because the gain of the darlingtons is too high, and the output stays banged against the input rail (22V). I dont understand what you mean by this. The voltage gain of the darlington transistors is less than unity in this case since they are being used as emitter followers. I am dropping 8.5 volts at 20 amps or 170 watts is being dissipated by the transistors. This may not be a real problem. I know my commercial power supply of similar size only provides about 18 volts to the collector of the pass transistors and this would result in about half as much power being wasted. What voltage would you normally expect at the the collector of the pass transistors. I have also thought that maybe I dont have that much of a real problem since I doubt if the power supply will ever be put under the same demands as it does working into my load bank. Also I think I should add two more transistors in paralell with the two I have. I think this would distribute the heat better over my heat sink and have less localized heating. I dont think the size of my heatsink is a problem, it is probably overkill. it is a 8in chimney type heat sink( i think that what you call them) 8x8x10 inches finned inside and out. The transistor body is mount on the outside withe the wires going down the inside of the chimney. The end of the chimney is designed to take a muffin fan. Jimmie |
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