Home |
Search |
Today's Posts |
#1
![]() |
|||
|
|||
![]()
One thing that puzzled me for years was that the output impedance of
an amplifying stage could be much higher than the voltage drop across the active element divided by the current through it. Now, clearly as current sources, this would be true, and it could be measured., by changing the loads. But, how could you calculate such a value up front? |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Transmitter Output Impedance | Antenna | |||
Transmitter Output Impedance | Antenna | |||
Measuring RF output impedance | Homebrew | |||
Measuring RF output impedance | Homebrew | |||
Tuna Tin (II) output impedance | Homebrew |