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Old May 16th 14, 08:44 PM posted to uk.radio.amateur,rec.radio.amateur.homebrew
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First recorded activity by RadioBanter: Sep 2012
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Default Output Impedance

One thing that puzzled me for years was that the output impedance of
an amplifying stage could be much higher than the voltage drop
across the active element divided by the current through it.

Now, clearly as current sources, this would be true, and it could be
measured.,
by changing the loads.

But, how could you calculate such a value up front?



 
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