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Old July 31st 03, 05:32 PM
Damien Teney
 
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Okay, but as it isn't constant over the tuning range, do I have to use the
average value of it in the formulas of the filter ?


VCO gain is basically the first derivative (slope) of the tuning voltage

vs.
frequency function. It's rare to find a VCO that tunes truly linearly, so
it will differ over the tuning range.


There are two ways I've plotted the tuning voltage vs. frequency. One
of them is the obvious way; connect a frequency counter to the output
of the VCO (taking care not to load the VCO output inappropriately;
you'll want to simulate the conditions under which the VCO will actually
be used), and then vary the tuning voltage very carefully, plotting the
voltage vs. frequency. From this you can calculate the tuning gain.

Another way, and it might be easier, is to include the VCO in a PLL.

Guess at
the parameters and you'll probably get a loop that locks up. As long as

the loop
is in lock, you can vary the frequency by programming the PLL and measure

the
tuning voltage. As long as your loop reference is reasonably accurate

you'll
get at least as good results as if you used a frequency counter and I

believe this
method is better since you're measuring the VCO gain in the system.

Enjoy!
Dana K6JQ



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Old July 31st 03, 05:32 PM
Damien Teney
 
Posts: n/a
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Okay, but as it isn't constant over the tuning range, do I have to use the
average value of it in the formulas of the filter ?


VCO gain is basically the first derivative (slope) of the tuning voltage

vs.
frequency function. It's rare to find a VCO that tunes truly linearly, so
it will differ over the tuning range.


There are two ways I've plotted the tuning voltage vs. frequency. One
of them is the obvious way; connect a frequency counter to the output
of the VCO (taking care not to load the VCO output inappropriately;
you'll want to simulate the conditions under which the VCO will actually
be used), and then vary the tuning voltage very carefully, plotting the
voltage vs. frequency. From this you can calculate the tuning gain.

Another way, and it might be easier, is to include the VCO in a PLL.

Guess at
the parameters and you'll probably get a loop that locks up. As long as

the loop
is in lock, you can vary the frequency by programming the PLL and measure

the
tuning voltage. As long as your loop reference is reasonably accurate

you'll
get at least as good results as if you used a frequency counter and I

believe this
method is better since you're measuring the VCO gain in the system.

Enjoy!
Dana K6JQ



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Old July 31st 03, 05:35 PM
Dana Myers K6JQ
 
Posts: n/a
Default VCO gain



Damien Teney wrote:
Hello,
I've made a VHF receiver and I want to add a PLL to control the VCO. In
order to calculate the loop filter, I need to know the VCO gain, but I don't
know how to calculate (or measure) it. For information the VCO is a colpitts
oscillator.
Could someone help me ?


VCO gain is basically the first derivative (slope) of the tuning voltage vs.
frequency function. It's rare to find a VCO that tunes truly linearly, so
it will differ over the tuning range.


There are two ways I've plotted the tuning voltage vs. frequency. One
of them is the obvious way; connect a frequency counter to the output
of the VCO (taking care not to load the VCO output inappropriately;
you'll want to simulate the conditions under which the VCO will actually
be used), and then vary the tuning voltage very carefully, plotting the
voltage vs. frequency. From this you can calculate the tuning gain.

Another way, and it might be easier, is to include the VCO in a PLL. Guess at
the parameters and you'll probably get a loop that locks up. As long as the loop
is in lock, you can vary the frequency by programming the PLL and measure the
tuning voltage. As long as your loop reference is reasonably accurate you'll
get at least as good results as if you used a frequency counter and I believe this
method is better since you're measuring the VCO gain in the system.

Enjoy!
Dana K6JQ

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Old July 31st 03, 05:35 PM
Dana Myers K6JQ
 
Posts: n/a
Default



Damien Teney wrote:
Hello,
I've made a VHF receiver and I want to add a PLL to control the VCO. In
order to calculate the loop filter, I need to know the VCO gain, but I don't
know how to calculate (or measure) it. For information the VCO is a colpitts
oscillator.
Could someone help me ?


VCO gain is basically the first derivative (slope) of the tuning voltage vs.
frequency function. It's rare to find a VCO that tunes truly linearly, so
it will differ over the tuning range.


There are two ways I've plotted the tuning voltage vs. frequency. One
of them is the obvious way; connect a frequency counter to the output
of the VCO (taking care not to load the VCO output inappropriately;
you'll want to simulate the conditions under which the VCO will actually
be used), and then vary the tuning voltage very carefully, plotting the
voltage vs. frequency. From this you can calculate the tuning gain.

Another way, and it might be easier, is to include the VCO in a PLL. Guess at
the parameters and you'll probably get a loop that locks up. As long as the loop
is in lock, you can vary the frequency by programming the PLL and measure the
tuning voltage. As long as your loop reference is reasonably accurate you'll
get at least as good results as if you used a frequency counter and I believe this
method is better since you're measuring the VCO gain in the system.

Enjoy!
Dana K6JQ

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Old August 1st 03, 10:03 AM
Damien Teney
 
Posts: n/a
Default

The most common 'gotcha' here is confusing radians/volt and Hz/volt.
Some PLL data sheets and textbooks use radians, while others use hertz.
Since the difference is more than 6:1, you want to make sure you get
this part right, or you'll end up with a broadband jammer.


Yep right, my formulas use radians/volt, so, how can I transform the hz/v
value that I got with your trick, to rad/v ?




  #6   Report Post  
Old August 1st 03, 10:03 AM
Damien Teney
 
Posts: n/a
Default

The most common 'gotcha' here is confusing radians/volt and Hz/volt.
Some PLL data sheets and textbooks use radians, while others use hertz.
Since the difference is more than 6:1, you want to make sure you get
this part right, or you'll end up with a broadband jammer.


Yep right, my formulas use radians/volt, so, how can I transform the hz/v
value that I got with your trick, to rad/v ?


  #7   Report Post  
Old August 1st 03, 10:09 AM
Leon Heller
 
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"Damien Teney" wrote in message
...
The most common 'gotcha' here is confusing radians/volt and Hz/volt.
Some PLL data sheets and textbooks use radians, while others use hertz.
Since the difference is more than 6:1, you want to make sure you get
this part right, or you'll end up with a broadband jammer.


Yep right, my formulas use radians/volt, so, how can I transform the hz/v
value that I got with your trick, to rad/v ?



omega = 2*PI*f

that's where the 6:1 came from. 8-)

73, Leon
--
Leon Heller, G1HSM

http://www.geocities.com/leon_heller


  #8   Report Post  
Old August 1st 03, 10:09 AM
Leon Heller
 
Posts: n/a
Default


"Damien Teney" wrote in message
...
The most common 'gotcha' here is confusing radians/volt and Hz/volt.
Some PLL data sheets and textbooks use radians, while others use hertz.
Since the difference is more than 6:1, you want to make sure you get
this part right, or you'll end up with a broadband jammer.


Yep right, my formulas use radians/volt, so, how can I transform the hz/v
value that I got with your trick, to rad/v ?



omega = 2*PI*f

that's where the 6:1 came from. 8-)

73, Leon
--
Leon Heller, G1HSM

http://www.geocities.com/leon_heller


  #9   Report Post  
Old August 1st 03, 02:14 PM
Mike Andrews
 
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Leon Heller wrote:

"Damien Teney" wrote in message
...


Yep right, my formulas use radians/volt, so, how can I transform the hz/v
value that I got with your trick, to rad/v ?


omega = 2*PI*f


that's where the 6:1 came from. 8-)


One cycle = 360 degrees = 2*pi radians, which makes
radians/volt = 2*pi*hz/volt.

--
"Of course they're pallid and mushroom-like, Howard!
They're _mushrooms_!"
-- from a Gahan Wilson cartoon
involving H.P. Lovecraft
  #10   Report Post  
Old August 1st 03, 02:14 PM
Mike Andrews
 
Posts: n/a
Default

Leon Heller wrote:

"Damien Teney" wrote in message
...


Yep right, my formulas use radians/volt, so, how can I transform the hz/v
value that I got with your trick, to rad/v ?


omega = 2*PI*f


that's where the 6:1 came from. 8-)


One cycle = 360 degrees = 2*pi radians, which makes
radians/volt = 2*pi*hz/volt.

--
"Of course they're pallid and mushroom-like, Howard!
They're _mushrooms_!"
-- from a Gahan Wilson cartoon
involving H.P. Lovecraft


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