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On Sun, 05 Oct 2003 13:50:43 +0100, Paul Burridge
wrote: snip I'm getting very little output. After tuning the transmitter, per the specs, and measuring the output using the method suggested by the author of the web page, I figure I'm getting 1 watt or less. How is this figure arrived at? How are you measuring it? 1W doesn't sound much, but it can go a long way on 40M., given an efficient antenna system with short, low-loss feeder and matched radiation resistance. Voltage is measured across my 50 ohm dummy load and rectified using a ..05 mfd ceramic disc cap and a 1N34A diode. Then I'm calculating thusly: Power = (Voltage x Voltage) / 50 I'm taking the author's word that this works for a ballpark estimate. I'm measuring 7 volts across the load, maximum, which works out to 1 watt or less. I've verified that my meter is accurate. I am running this into a dipole cut for 40 meters, which is 7 feet off the ground. That's *way* too low! As you must know for any ariel, you gotta get that thing up as high off the ground as you can and that's even more important at low frequencies like 7Mhz. We have a mess of power lines around the house, so it's hard to find a spot to even get it 7 feet high in a straight line. I'm thinking about trying it on the roof, which is about 20 feet high at the highest point, and mabye angling it in the center. One of the transistors (Q2) is supposed to be heat sinked. I have put a large homemeade heat sink on this, using plenty of heat sink grease, and it gets so hot I can barely touch it. Something's wrong, then. The heat dissipated in your final transistor should equate to the output power at the antenna if the system is matched properly. Sounds like your tranny's trying to dissipate rather more than a Watt. Are you sure you don't have a feeder/matching problem somewhere? Have you cut the ariel to the right length? Are you using a balun? Have you tried a substitute balun? The length of each element is 32' 11", which I calculated for use at 7110 kHz. There's no balun; I'm using coax, the shield is connected to one element and the center conductor is connected to the other. The coax might be 75 ohm. Pretty soon I'll have RG-58 for the entire run, but right now it's a mix of RG-6/U and RG-59/U. Get another ham a couple of miles away from you to give you a signal report. It might show up something useful. I will do that. Thanks. -- -John Sandin KC0QWE Remove the "T" to respond by e-mail |
#3
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The circuit you describe should be delivering approximately the peak
voltage, not RMS, so the formula is more like V X V / 100. At 7 volts peak, that means you're putting out around 1/2 watt. That's a lot below the 3 watt figure you mentioned, so you should track down why it's so much lower. Pay special care to the circuit components in the final transistor output (collector) circuit, and make sure the inductors are built as described and the components are connected correctly. Roy Lewallen, W7EL John Sandin wrote: . . . Voltage is measured across my 50 ohm dummy load and rectified using a .05 mfd ceramic disc cap and a 1N34A diode. Then I'm calculating thusly: Power = (Voltage x Voltage) / 50 I'm taking the author's word that this works for a ballpark estimate. I'm measuring 7 volts across the load, maximum, which works out to 1 watt or less. I've verified that my meter is accurate. . . . |
#4
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The circuit you describe should be delivering approximately the peak
voltage, not RMS, so the formula is more like V X V / 100. At 7 volts peak, that means you're putting out around 1/2 watt. That's a lot below the 3 watt figure you mentioned, so you should track down why it's so much lower. Pay special care to the circuit components in the final transistor output (collector) circuit, and make sure the inductors are built as described and the components are connected correctly. Roy Lewallen, W7EL John Sandin wrote: . . . Voltage is measured across my 50 ohm dummy load and rectified using a .05 mfd ceramic disc cap and a 1N34A diode. Then I'm calculating thusly: Power = (Voltage x Voltage) / 50 I'm taking the author's word that this works for a ballpark estimate. I'm measuring 7 volts across the load, maximum, which works out to 1 watt or less. I've verified that my meter is accurate. . . . |
#5
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On Sun, 05 Oct 2003 13:50:43 +0100, Paul Burridge
wrote: snip I'm getting very little output. After tuning the transmitter, per the specs, and measuring the output using the method suggested by the author of the web page, I figure I'm getting 1 watt or less. How is this figure arrived at? How are you measuring it? 1W doesn't sound much, but it can go a long way on 40M., given an efficient antenna system with short, low-loss feeder and matched radiation resistance. Voltage is measured across my 50 ohm dummy load and rectified using a ..05 mfd ceramic disc cap and a 1N34A diode. Then I'm calculating thusly: Power = (Voltage x Voltage) / 50 I'm taking the author's word that this works for a ballpark estimate. I'm measuring 7 volts across the load, maximum, which works out to 1 watt or less. I've verified that my meter is accurate. I am running this into a dipole cut for 40 meters, which is 7 feet off the ground. That's *way* too low! As you must know for any ariel, you gotta get that thing up as high off the ground as you can and that's even more important at low frequencies like 7Mhz. We have a mess of power lines around the house, so it's hard to find a spot to even get it 7 feet high in a straight line. I'm thinking about trying it on the roof, which is about 20 feet high at the highest point, and mabye angling it in the center. One of the transistors (Q2) is supposed to be heat sinked. I have put a large homemeade heat sink on this, using plenty of heat sink grease, and it gets so hot I can barely touch it. Something's wrong, then. The heat dissipated in your final transistor should equate to the output power at the antenna if the system is matched properly. Sounds like your tranny's trying to dissipate rather more than a Watt. Are you sure you don't have a feeder/matching problem somewhere? Have you cut the ariel to the right length? Are you using a balun? Have you tried a substitute balun? The length of each element is 32' 11", which I calculated for use at 7110 kHz. There's no balun; I'm using coax, the shield is connected to one element and the center conductor is connected to the other. The coax might be 75 ohm. Pretty soon I'll have RG-58 for the entire run, but right now it's a mix of RG-6/U and RG-59/U. Get another ham a couple of miles away from you to give you a signal report. It might show up something useful. I will do that. Thanks. -- -John Sandin KC0QWE Remove the "T" to respond by e-mail |
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