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Diego Stutzer October 14th 03 07:38 PM

V and I not in phase at resonance Frequency in RLC network?
 
Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?
Or why this Problem is showing up?
Thanks to anyone reading this and especially to those who post
answers.
D. Stutzer

Don Pearce October 14th 03 07:56 PM

On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?
Or why this Problem is showing up?
Thanks to anyone reading this and especially to those who post
answers.
D. Stutzer


The impedance should be R + jwL + 1/(jwC)

d

_____________________________

http://www.pearce.uk.com

Don Pearce October 14th 03 07:56 PM

On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?
Or why this Problem is showing up?
Thanks to anyone reading this and especially to those who post
answers.
D. Stutzer


The impedance should be R + jwL + 1/(jwC)

d

_____________________________

http://www.pearce.uk.com

John Fields October 14th 03 08:02 PM

On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?


---

1
f = -------------
2pi(sqrt(LC))


--
John Fields

John Fields October 14th 03 08:02 PM

On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?


---

1
f = -------------
2pi(sqrt(LC))


--
John Fields

Pawel Stobinski October 14th 03 08:30 PM

Don Pearce wrote:
The impedance should be R + jwL + 1/(jwC)



1/j = j/j*j = j/-1 = -j

-j/wC = 1/jwC

--
Pawel Stobinski
Republic of Poland





Pawel Stobinski October 14th 03 08:30 PM

Don Pearce wrote:
The impedance should be R + jwL + 1/(jwC)



1/j = j/j*j = j/-1 = -j

-j/wC = 1/jwC

--
Pawel Stobinski
Republic of Poland





Diego Stutzer October 14th 03 10:32 PM


John Fields schrieb in im Newsbeitrag:
...
On 14 Oct 2003 11:38:29 -0700,
(Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?


---

1
f = -------------
2pi(sqrt(LC))


--
John Fields


WOW!! Thank you soo much. The world is sound and the laws of physics apply
again. I just confused w (omega) and f.
Best Regards
D. Stutzer



Diego Stutzer October 14th 03 10:32 PM


John Fields schrieb in im Newsbeitrag:
...
On 14 Oct 2003 11:38:29 -0700,
(Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?


---

1
f = -------------
2pi(sqrt(LC))


--
John Fields


WOW!! Thank you soo much. The world is sound and the laws of physics apply
again. I just confused w (omega) and f.
Best Regards
D. Stutzer



Michael October 15th 03 01:25 AM

The impedance should be R + jwL + 1/(jwC)


You sure?, how do the j parts cancel at resonance if they are both added?

Michael October 15th 03 01:25 AM

The impedance should be R + jwL + 1/(jwC)


You sure?, how do the j parts cancel at resonance if they are both added?

Tom Bruhns October 15th 03 01:51 AM

Which voltage and which current? Clearly the voltage across the
capacitor will always be pi/2 relative to the current in that
capacitor, and the same (but opposite sign) for an inductor. Also,
are you doing an AC or a transient analysis? If transient, are the
transients settled, are you really on the resonance frequency, and are
you simulating with sufficient time resolution? Oh, and I'm not quite
sure what you mean by "lambda/4" phase shift. Is that degrees or
radians, and what's lambda?

Cheers,
Tom

(Diego Stutzer) wrote in message . com...
Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?
Or why this Problem is showing up?
Thanks to anyone reading this and especially to those who post
answers.
D. Stutzer


Tom Bruhns October 15th 03 01:51 AM

Which voltage and which current? Clearly the voltage across the
capacitor will always be pi/2 relative to the current in that
capacitor, and the same (but opposite sign) for an inductor. Also,
are you doing an AC or a transient analysis? If transient, are the
transients settled, are you really on the resonance frequency, and are
you simulating with sufficient time resolution? Oh, and I'm not quite
sure what you mean by "lambda/4" phase shift. Is that degrees or
radians, and what's lambda?

Cheers,
Tom

(Diego Stutzer) wrote in message . com...
Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?
Or why this Problem is showing up?
Thanks to anyone reading this and especially to those who post
answers.
D. Stutzer


Dale Parfitt October 15th 03 01:51 AM



Don Pearce wrote:

On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp.


-j/wc= 1/jwc


Dale Parfitt October 15th 03 01:51 AM



Don Pearce wrote:

On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp.


-j/wc= 1/jwc


Reg Edwards October 15th 03 03:03 AM

Multiply top and bottom of 1/jwC by j (This does not change its value) and
you get 1/jwC = minus j/wC.

Back to school with your algebra.



Reg Edwards October 15th 03 03:03 AM

Multiply top and bottom of 1/jwC by j (This does not change its value) and
you get 1/jwC = minus j/wC.

Back to school with your algebra.



budgie October 15th 03 03:12 AM

On Wed, 15 Oct 2003 02:03:05 +0000 (UTC), "Reg Edwards"
wrote:

Multiply top and bottom of 1/jwC by j (This does not change its value) and
you get 1/jwC = minus j/wC.

Back to school with your algebra.


His algebra looks perfectly fine to me. But as others have pointed
out, he's left the 2pi out.

budgie October 15th 03 03:12 AM

On Wed, 15 Oct 2003 02:03:05 +0000 (UTC), "Reg Edwards"
wrote:

Multiply top and bottom of 1/jwC by j (This does not change its value) and
you get 1/jwC = minus j/wC.

Back to school with your algebra.


His algebra looks perfectly fine to me. But as others have pointed
out, he's left the 2pi out.

Reg Edwards October 15th 03 03:43 AM


"budgie" wrote in message
...
On Wed, 15 Oct 2003 02:03:05 +0000 (UTC), "Reg Edwards"
wrote:

Multiply top and bottom of 1/jwC by j (This does not change its value)

and
you get 1/jwC = minus j/wC.

Back to school with your algebra.


His algebra looks perfectly fine to me. But as others have pointed
out, he's left the 2pi out.


------------------------------------------

Yes. I apologise for my remark about school. I gained the incorrect
impression from the previous replies.

The w in wC stands for omega = 2*Pi*F, the angular frequency.



Reg Edwards October 15th 03 03:43 AM


"budgie" wrote in message
...
On Wed, 15 Oct 2003 02:03:05 +0000 (UTC), "Reg Edwards"
wrote:

Multiply top and bottom of 1/jwC by j (This does not change its value)

and
you get 1/jwC = minus j/wC.

Back to school with your algebra.


His algebra looks perfectly fine to me. But as others have pointed
out, he's left the 2pi out.


------------------------------------------

Yes. I apologise for my remark about school. I gained the incorrect
impression from the previous replies.

The w in wC stands for omega = 2*Pi*F, the angular frequency.



Active8 October 15th 03 06:52 AM

On Tue, 14 Oct 2003 19:56:43 +0100, Don Pearce, said...
On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?
Or why this Problem is showing up?
Thanks to anyone reading this and especially to those who post
answers.
D. Stutzer


The impedance should be R + jwL + 1/(jwC)

d

_____________________________

http://www.pearce.uk.com

now that were all done playing with j...

Z = sqrt[R^2 + (jwL)^2 - (1/jwC)^2] = sqrt[R^2 + (jwL)^2 + (j/wC)^2]

this is scary ****.

mike

Active8 October 15th 03 06:52 AM

On Tue, 14 Oct 2003 19:56:43 +0100, Don Pearce, said...
On 14 Oct 2003 11:38:29 -0700, (Diego Stutzer)
wrote:

Hi,
Well, I'm really confused.
I simulate a simple serial R-C-L-Network (all in series).

As far as I know the total (input-)Impedance of the network is:
Z = R + jwL - j/(wC) resp. the resonance frequency (where Zin=R) is
1/sqrt(L*C).
At resonance frequency, the Impedance should be real and therefore in
my hummel opinion Voltage and Current schould be in phase.

The funny thing is, when i build up such a network in Schematics
(Cadence PSD 14.1/Orcad 9.2) and simulate it with the PSpice A/D
Simulator, the current is displaced (relative to the voltage) about
lambda/4 - obviously not in phase!?

Can anyone tell my where I made a mistake?
Or why this Problem is showing up?
Thanks to anyone reading this and especially to those who post
answers.
D. Stutzer


The impedance should be R + jwL + 1/(jwC)

d

_____________________________

http://www.pearce.uk.com

now that were all done playing with j...

Z = sqrt[R^2 + (jwL)^2 - (1/jwC)^2] = sqrt[R^2 + (jwL)^2 + (j/wC)^2]

this is scary ****.

mike

Active8 October 15th 03 07:11 AM

On Wed, 15 Oct 2003 02:43:27 +0000 (UTC), Reg Edwards, said...

"budgie" wrote in message
...
On Wed, 15 Oct 2003 02:03:05 +0000 (UTC), "Reg Edwards"
wrote:

Multiply top and bottom of 1/jwC by j (This does not change its value)

and
you get 1/jwC = minus j/wC.

Back to school with your algebra.


His algebra looks perfectly fine to me. But as others have pointed
out, he's left the 2pi out.


------------------------------------------

Yes. I apologise for my remark about school. I gained the incorrect
impression from the previous replies.

The w in wC stands for omega = 2*Pi*F, the angular frequency.

now that were all done playing with j...

don't forget

Z = sqrt{R^2 + [(wL) - (1/wC)]^2]}

and

Z(s) = R + Ls + 1/Cs

which is just plain easier to deal with 'til you need to journey back
into time domain land. no need to leave it f(t) for this deal, though.

all that j stuff... that was scary ****. so easy to make a mistake.
swapping w and f is another good one. only works for f/f stuff.

mike

Active8 October 15th 03 07:11 AM

On Wed, 15 Oct 2003 02:43:27 +0000 (UTC), Reg Edwards, said...

"budgie" wrote in message
...
On Wed, 15 Oct 2003 02:03:05 +0000 (UTC), "Reg Edwards"
wrote:

Multiply top and bottom of 1/jwC by j (This does not change its value)

and
you get 1/jwC = minus j/wC.

Back to school with your algebra.


His algebra looks perfectly fine to me. But as others have pointed
out, he's left the 2pi out.


------------------------------------------

Yes. I apologise for my remark about school. I gained the incorrect
impression from the previous replies.

The w in wC stands for omega = 2*Pi*F, the angular frequency.

now that were all done playing with j...

don't forget

Z = sqrt{R^2 + [(wL) - (1/wC)]^2]}

and

Z(s) = R + Ls + 1/Cs

which is just plain easier to deal with 'til you need to journey back
into time domain land. no need to leave it f(t) for this deal, though.

all that j stuff... that was scary ****. so easy to make a mistake.
swapping w and f is another good one. only works for f/f stuff.

mike

Don Pearce October 15th 03 07:33 AM

On Tue, 14 Oct 2003 21:30:18 +0200, "Pawel Stobinski"
wrote:

Don Pearce wrote:
The impedance should be R + jwL + 1/(jwC)



1/j = j/j*j = j/-1 = -j

-j/wC = 1/jwC


Quite right - the unusual format fooled me.

d

_____________________________

http://www.pearce.uk.com

Don Pearce October 15th 03 07:33 AM

On Tue, 14 Oct 2003 21:30:18 +0200, "Pawel Stobinski"
wrote:

Don Pearce wrote:
The impedance should be R + jwL + 1/(jwC)



1/j = j/j*j = j/-1 = -j

-j/wC = 1/jwC


Quite right - the unusual format fooled me.

d

_____________________________

http://www.pearce.uk.com

Paul Burridge October 15th 03 09:18 AM

On Wed, 15 Oct 2003 06:11:13 GMT, Active8
wrote:

now that were all done playing with j...

don't forget

Z = sqrt{R^2 + [(wL) - (1/wC)]^2]}

and

Z(s) = R + Ls + 1/Cs

which is just plain easier to deal with 'til you need to journey back
into time domain land. no need to leave it f(t) for this deal, though.

all that j stuff... that was scary ****. so easy to make a mistake.


Especially so given the limited typography of this particular medium.
I suspect few of us would have a problem if we could only view these
formulae in a suitably appropriate typeface!!!
--

"Windows [n.], A thirty-two bit extension and GUI shell to a sixteen bit patch
to an eight bit operating system originally coded for a four bit
microprocessor and produced by a two bit company."

Paul Burridge October 15th 03 09:18 AM

On Wed, 15 Oct 2003 06:11:13 GMT, Active8
wrote:

now that were all done playing with j...

don't forget

Z = sqrt{R^2 + [(wL) - (1/wC)]^2]}

and

Z(s) = R + Ls + 1/Cs

which is just plain easier to deal with 'til you need to journey back
into time domain land. no need to leave it f(t) for this deal, though.

all that j stuff... that was scary ****. so easy to make a mistake.


Especially so given the limited typography of this particular medium.
I suspect few of us would have a problem if we could only view these
formulae in a suitably appropriate typeface!!!
--

"Windows [n.], A thirty-two bit extension and GUI shell to a sixteen bit patch
to an eight bit operating system originally coded for a four bit
microprocessor and produced by a two bit company."

Laycock, Christopher October 15th 03 11:12 AM

R + jwL + 1/(jwC)
= R + jwL -j/(wC)
so at resonance wL=1/(wC)
ie w=1/sqrt(LC)

Chris

"Michael" wrote in message
om...
The impedance should be R + jwL + 1/(jwC)


You sure?, how do the j parts cancel at resonance if they are both added?+




Laycock, Christopher October 15th 03 11:12 AM

R + jwL + 1/(jwC)
= R + jwL -j/(wC)
so at resonance wL=1/(wC)
ie w=1/sqrt(LC)

Chris

"Michael" wrote in message
om...
The impedance should be R + jwL + 1/(jwC)


You sure?, how do the j parts cancel at resonance if they are both added?+




John Fields October 15th 03 12:42 PM

On 14 Oct 2003 17:51:11 -0700, (Tom Bruhns) wrote:

Which voltage and which current? Clearly the voltage across the
capacitor will always be pi/2 relative to the current in that
capacitor, and the same (but opposite sign) for an inductor. Also,
are you doing an AC or a transient analysis? If transient, are the
transients settled, are you really on the resonance frequency, and are
you simulating with sufficient time resolution? Oh, and I'm not quite
sure what you mean by "lambda/4" phase shift. Is that degrees or
radians, and what's lambda?


---
Since he calculated the resonant frequency of the circuit using

f = 1/sqrt(L*C),

his answer will always be a frequency 6.28 times higher than it should
be, so the reactance of the inductor will be greater than the reactance
of the capacitor, making the phase angle positive.

"Lambda" is usually taken to mean wavelength, so "lambda/4" would mean a
quarter wavelength; in this context, 90°, the approximate phase
difference between his simulated voltage and current.

--
John Fields

John Fields October 15th 03 12:42 PM

On 14 Oct 2003 17:51:11 -0700, (Tom Bruhns) wrote:

Which voltage and which current? Clearly the voltage across the
capacitor will always be pi/2 relative to the current in that
capacitor, and the same (but opposite sign) for an inductor. Also,
are you doing an AC or a transient analysis? If transient, are the
transients settled, are you really on the resonance frequency, and are
you simulating with sufficient time resolution? Oh, and I'm not quite
sure what you mean by "lambda/4" phase shift. Is that degrees or
radians, and what's lambda?


---
Since he calculated the resonant frequency of the circuit using

f = 1/sqrt(L*C),

his answer will always be a frequency 6.28 times higher than it should
be, so the reactance of the inductor will be greater than the reactance
of the capacitor, making the phase angle positive.

"Lambda" is usually taken to mean wavelength, so "lambda/4" would mean a
quarter wavelength; in this context, 90°, the approximate phase
difference between his simulated voltage and current.

--
John Fields

Active8 October 15th 03 01:31 PM

On Wed, 15 Oct 2003 09:18:51 +0100, Paul Burridge, said...
On Wed, 15 Oct 2003 06:11:13 GMT, Active8
wrote:

now that were all done playing with j...

don't forget

Z = sqrt{R^2 + [(wL) - (1/wC)]^2]}

and

Z(s) = R + Ls + 1/Cs

which is just plain easier to deal with 'til you need to journey back
into time domain land. no need to leave it f(t) for this deal, though.

all that j stuff... that was scary ****. so easy to make a mistake.


Especially so given the limited typography of this particular medium.
I suspect few of us would have a problem if we could only view these
formulae in a suitably appropriate typeface!!!

what pre tell, is a typeface that would make it hard? wing-dings?

i admit, even in HTML with arial or fixed-pitch, where you have sub and
super tags and greek letter codes, you can't do much. i tried a few free
math notation tools for HTML and wasn't happy. plus you need a plugin
for most if not all. W^3C has a standard. i'd like to see more math
capabiliies in browsers. we could attach formulae without violating the
no bianaries rule. of course microshaft and standards will probably
never be seen in the same line of code.

i still don't see why text based math legibility is font dependant. i
see i could have eliminated some clarifying parens by

- -
| 2 1 2 |
sqrt | R + ----- | or a 1/2 power instead of sqrt
| jwC |
- -
created by Andy´s ASCII-Circuit v1.22.310103 Beta www.tech-chat.de

does that also foul up?

brs,
mike

Active8 October 15th 03 01:31 PM

On Wed, 15 Oct 2003 09:18:51 +0100, Paul Burridge, said...
On Wed, 15 Oct 2003 06:11:13 GMT, Active8
wrote:

now that were all done playing with j...

don't forget

Z = sqrt{R^2 + [(wL) - (1/wC)]^2]}

and

Z(s) = R + Ls + 1/Cs

which is just plain easier to deal with 'til you need to journey back
into time domain land. no need to leave it f(t) for this deal, though.

all that j stuff... that was scary ****. so easy to make a mistake.


Especially so given the limited typography of this particular medium.
I suspect few of us would have a problem if we could only view these
formulae in a suitably appropriate typeface!!!

what pre tell, is a typeface that would make it hard? wing-dings?

i admit, even in HTML with arial or fixed-pitch, where you have sub and
super tags and greek letter codes, you can't do much. i tried a few free
math notation tools for HTML and wasn't happy. plus you need a plugin
for most if not all. W^3C has a standard. i'd like to see more math
capabiliies in browsers. we could attach formulae without violating the
no bianaries rule. of course microshaft and standards will probably
never be seen in the same line of code.

i still don't see why text based math legibility is font dependant. i
see i could have eliminated some clarifying parens by

- -
| 2 1 2 |
sqrt | R + ----- | or a 1/2 power instead of sqrt
| jwC |
- -
created by Andy´s ASCII-Circuit v1.22.310103 Beta www.tech-chat.de

does that also foul up?

brs,
mike

Kieren October 15th 03 10:25 PM

....snip

i still don't see why text based math legibility is font dependant. i
see i could have eliminated some clarifying parens by

- -
| 2 1 2 |
sqrt | R + ----- | or a 1/2 power instead of sqrt
| jwC |
- -
created by Andy´s ASCII-Circuit v1.22.310103 Beta www.tech-chat.de

does that also foul up?

brs,
mike



Oh, Mike. That's ugly!! Strangely, when I see it in this window I type
replies in, it's much clearer! Hey, ho. I agree with you about viewing
these things in browsers... always hard. For my money, the first ones in
this chain were as good as any I've seen

Kieren October 15th 03 10:25 PM

....snip

i still don't see why text based math legibility is font dependant. i
see i could have eliminated some clarifying parens by

- -
| 2 1 2 |
sqrt | R + ----- | or a 1/2 power instead of sqrt
| jwC |
- -
created by Andy´s ASCII-Circuit v1.22.310103 Beta www.tech-chat.de

does that also foul up?

brs,
mike



Oh, Mike. That's ugly!! Strangely, when I see it in this window I type
replies in, it's much clearer! Hey, ho. I agree with you about viewing
these things in browsers... always hard. For my money, the first ones in
this chain were as good as any I've seen

Michael October 16th 03 12:59 AM


all that j stuff... that was scary ****. so easy to make a mistake.
swapping w and f is another good one. only works for f/f stuff.

mike


I get a bit scared of all the j's too, I prefer polar. Usually you
want a magnitude and angle in the end result anyway.

Michael October 16th 03 12:59 AM


all that j stuff... that was scary ****. so easy to make a mistake.
swapping w and f is another good one. only works for f/f stuff.

mike


I get a bit scared of all the j's too, I prefer polar. Usually you
want a magnitude and angle in the end result anyway.


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